CBSE 11th Standard Maths Subject Probability HOT Questions 6 Mark Questions With Solution 2021
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CBSE 11th Standard Maths Subject Probability HOT Questions 6 Mark Questions With Solution 2021
11th Standard CBSE
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Reg.No. :
Mathematics
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A box contains 200 bolts and 70 nuts. It is given that 60% bolts and 40% nuts are rusted.Two objects are selected at random from the box.Find the probability that either both are bolts or both are rusted.
(a) -
If 4-digit numbers greater than 5,000 are randomly formed from the digits 0, 1, 3, 5, and 7, what is the probability of forming a number divisible by 5 when, (i) the digits are repeated? (ii) the repetition of digits is not allowed?
(a) -
If 4digit numbers greater than 5000 are randomly formed the digits 0,1,3,5 and 7.What is the probability of forming a number divisible by 5 when the repetition of digits are not allowed?
(a)
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CBSE 11th Standard Maths Subject Probability HOT Questions 6 Mark Questions With Solution 2021 Answer Keys
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\(\frac { 28363 }{ 36315 } \)
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The four digit numbers greater than 5000are randomly formed from the digits 0,1,3,5,7.
(i) Given, the digits are repeated.
The number formed is greater than 5000, the leftmost digit is either 7or 5. The remaining three places can be filled by any of the digits 0,1,3,5or 7.
Total four digit number formed greater than 5000 is 2×5×5×5−1=249.
If unit digit of a number is 0 or 5 then number is divisible by 5.
Total numbers that are divisible by 5is 2×5×5×2−1=99.
Assume E be the event when number is divisible by 5and digits are repeating.
The probability is, P( E )= 99 249 = 33 249
Thus, the probability of number divisible by 5when digits repeated is 33 249 .
(ii) Given, repetition of digit is not allowed. Then the thousands place can be filled with digits either 5or 7and remaining three places can be filled with any of the remaining four digits.
Total four digit number formed greater than 5000is 2×4×3×2=48.
If the digit at thousand place is 5 then unit place can be filled with 0 and tens and hundreds places can be filled with any of the remaining three digits.
The four digits number formed started with 5and divisible with 5is 3×2=6.
If the digit at thousand place is 7 then unit place can be filled with 0or 5.
The four digit numbers starting with 7and divisible by 5is 1×2×3×2=12.
Total number greater than 5000and divisible by 5is, 6+12=18
The probability of a number formed is divisible by 5 with repetition of digits is, 18 48 = 3 8
Thus, the required probability is 3 8 . -
(a) Thousand's place can be filled in 2 ways(5 or 7).
(b) The remaining 3 places can be filled in 4 x 3 x 2 ways.
Number of 4digits numbers = 2 x 4 x 3 x 2
(c) If the number is divisible by 5 then its units place is either 0 or 5.
(d) If units place is 0, then thousands, place can be filled in 2 ways and other two places can be filled in 3 x 2 ways.
(e) If units place is 5, then thousands place can be filled in 1 way and other two places can be filled in 3 x 2 ways.
Number of 4digits numbers divisible by 3
= 2 x 3 x 2 +1 x 3 x 2
\(=\frac { 3 }{ 8 } \)
