CBSE 12th Standard Chemistry Subject Coordination Compounds Ncert Exemplar 5 Mark Questions 2021
By QB365 on 25 May, 2021
QB365 Provides the updated NCERT Exemplar Questions for Class 12, and also provide the detail solution for each and every NCERT Exemplar questions. NCERT Exemplar questions are latest updated question pattern from NCERT, QB365 will helps to get more marks in Exams
QB365 - Question Bank Software
CBSE 12th Standard Chemistry Subject Coordination Compounds Ncert Exemplar 5 Mark Questions 2021
12th Standard CBSE
-
Reg.No. :
Chemistry
-
Using crystal field theory, draw energy level diagram, write electronic configuration of the central metal atom/ion and determine the magnetic moment value in the following :
(i) \([CoF_6]^{3-}, [Co(H_2O)_6]^{2+},[Co(CN)_6]^{3-}\)
(ii) \([FeF_6]^{3-}, \ [Fe(H_2O)_6]^{2+}, [Fe(CN)_6]^{4-}\).(a) -
Using valence bond theory, explain the following in relation to the complexes given below :
\([Mn(CN)_6]^{3-}, [Co(NH_3)_6]^{3+}, [Cr(H_2O)_6]^{3+}, [FeCl_6]^{4-}\)
(i) Type of hybridisation
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value.(a) -
CoSO4Cl.5 NH3 exists in two isomeric forms 'A' and 'B' gives white precipitate with BaCl2 but does not react with AgNO3. Answer the following questions.
(i) Identify 'A' and 'B' and write their structure formulas.
(ii) Name the type of isomerism involved
(iii) Give the IUPAC name of 'A' and 'B'.(a) -
What is the relationship between observed colour of the complex and the wavelength of light absorbed by the complex ?
(a) -
Why are different colours observed in octahedral and tetrahedral complexes for the same metal and same ligands ?
(a)
*****************************************
CBSE 12th Standard Chemistry Subject Coordination Compounds Ncert Exemplar 5 Mark Questions 2021 Answer Keys
-
(i) \([CoF_6]^{3-}\)
\( [Co(H_2O)_6]^{2+}\)
\([Co(CN)_6]^{3-}\)
(ii) \([FeF_6]^{3-}\)
\(\ [Fe(H_2O)_6]^{2+}\)
\([Fe(CN)_6]^{4-}\)
It is diamagnetic due to the absence of unpaired electrons. -
\([Mn(CN)_6]^{3-}\)
d2sp3, (ii) inner orbital complex, (iii) paramagnetic, (iv) 2.87 B.M.
(i) d2sp3 (ii) Inner orbital complex, (iii) diamagnetic, (iv) \(\mu=0\)
(i) d2sp3, (ii) Inner orbital complex, (iii) paramagnetic, (iv) 3.87 B.M.
(i) sp3d2, (ii) outer orbital complex (iii) paramagnetic (iv) 4.9 B.M. -
(i) As isomer A reacts with AgNO3 to give a white precipitate, CI must be present in the ionization sphere. As it does not react with BaCI2, SO42- must be present in coordination sphere.
Formula of A = [Co(NH3)5SO4] CI (coordination no. of Co = 6) As reactions are reverse for isomer B, formula of B = [Co(NH3)5CI]S04
(ii) Ionization isomerism.
(iii) A = Pentaarnminesulphatocobalt (III) chloride ; B = Pentaamminechloridocobalt (ill) sulphate -
When white light falls on the complex, some part of it is absorbed. Greater the CFSE, greater is the energy absorbed or shorter is the wavelength absorbed \((E={hc\over\lambda })\). The observed colour is the complementary colour of the colour absorbed.
-
\({ \triangle }_{ t }=\left( \frac { 4 }{ 9 } \right) { \triangle }_{ 0 }\). Thus, \({ \triangle }_{ t }\) is smaller than \({ \triangle }_{ 0 }\). Hence, less energy (higher wavelength) is absorbed by tetrahedral complexes than by octahedral complexes of the same metal and ligands. Therefore, the observed colour are different.
