Let width of rectangle (b)= x cm
Then, length of rectangle (I) = 3x cm
∴ Perimeter = 2 (l + b)
⇒ 40 =2 (3x + x)
⇒ 8x =40
⇒ x=\(\frac{40}{8}\)=5cm
Hence, length is 15 cm and width is 5 cm.

The area of the rectangle is 1.40 sq m.

10

140 cm

Perimeter of the figure ABCDEF = Sum of measurements of all sides
= AB + BC + CD + DE+ EF+ FA=100+120+90 + 45 +60+80 = 495 m

70m

Given, length of rectangle (l) = 8 m
and breadth of rectangle (b)= 6 m
Perimeter of rectangle = Perimeter of square
2 (l + b) = 4 \(\times\) Side of a square
⇒ 2(8 + 6) = 4 \(\times\) side of a square
Side of square =\(\frac{2(8+6)}{4}\)=7m
∴ Area of square = (7 \(\times\) 7) = 49 sq m

Area of room = 1.4 \(\times\) 9.5 m² = 1.4\(\times\) 9.5\(\times\) 10000 cm²
Area of one tile = 20\(\times\) 10= 200 cm²

Number of tiles\(=\frac { Area\quad of\quad the\quad room }{ Area\quad of\quad tile } =\frac { 74\times 95\times 100 }{ 200 } \)
\(=\frac { 74\times 95 }{ 2 } =95\times 37=3515\)

150 sq cm

Given, length of a rectangular plot = 500 m
and breadth of a rectangular plot = 200 m
∴ Area of the rectangular plot = Length \(\times\) Breadth
= 500 m\(\times\) 200 m
= 100000 sq m
∴ Cost of tiling per hundred square metres = Rs. 8
∴ Cost of 1 sq m = Rs.\(\frac { 8 }{ 100 } \)
Now, cost of 100000 sq metre =Rs.100000\(\times\frac { 8 }{ 100 } \)
=Rs. 8000
Hence, the cost of tiling rectangular plot is Rs. 8000

Let side of squared garden be x m.
Given that, perimeter of a squared garden = 48 m
∴ 4 x Side of a square = 48
⇒ 4x=48⇒x=\(\frac{48}{4}=12m\)
Now, area of the squared garden = (X)²
=(12)²=144m²
Also given, area of small flower bed cover inside the garden = 18 m²
∴ Area of the 9B.rden not covered by flower bed
= Area of squared garden - Area of flower bed
=144 m² -18 m² = 126 m²
The fractional part of the garden covered by flower bed=\(\frac { Area\quad covered\quad by\quad the\quad flower }{ Remaming\quad Area\quad of\quad the\quad squared\quad garden } \)
\(=\frac { 18 }{ 126 } =\frac { 2 }{ 14 } =\frac { 1 }{ 7 } \)
Hence, ratio of the area covered by the flower bed and the remaining area is 1 : 7.

Given, length of rectangular field (I) = 250 m and width is 150 m

Perimeter of this field = 2 (I + b) = 2 (250 + 150) m
= 2 \(\times\) 400 m = 800 m
Distance covered in one round = Perimeter = 800 m
Distance covered in three rounds
= 3\(\times\) 800= 2400 m
Now, number of rounds to cover 4 km, i.e. 400 m.
=\(\frac{4000}{800}=5\) [∵1 km= 1000 m]
Hence, she should run 5 times around the field to cover the distance of 4 km

Number of tiles =\(\frac { Area\quad of\quad the\quad floor }{ Area\quad of\quad one\quad tile } =\frac { 40\times 30 }{ 2\times 2 } =\frac { 1200 }{ 4 } \)
=300

Area of a square = Side \(\times\) Side⇒64= Side \(\times\) Side
⇒8\(\times\) 8= Side\(\times\)Side ⇒ Side = 8m
Perimeter = 4\(\times\)ide= 4\(\times\)8 =32 m

Area of a play ground = I x b
⇒ 1190=35b ⇒b=\(\frac{1190}{35}=34m\)

Diagonal of a square = \(\sqrt2\) x Side

Area = 5 x 3 = 15 sq cm