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Published on: 27/07/2018
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Take MCQ Mathematics Test

1.
Which of the following is not true?
rational numbers are closed under addition
rational numbers are closed under subtraction.
rational numbers are closed under multiplication
rational numbers are closed under division
2.
Zero (0) is
the identity for addition of rational numbers
the identity for subtraction of rational numbers
the identity for multiplication of rational numbers
the identity for division of rational numbers.
3.
Which of the following statements is always true?
\(\frac{x-y}{2}\) is a rational number between x and y
\(\frac{x+y}{2}\) is a rational number between x and y
\(\frac{x\times y}{2}\) is a rational number between x and y
\(\frac{x\div y}{2}\) is a rational number between x and y
4.
\(\frac{x+y}{2}\) is a rational number
between x and y
less than x and y both
greater than x and y both
less than x but greater than y
5.
Three rational numbers lying between\(\frac{-5}{4}\) and \(\frac{1}{2}\)are
-1, 0 ,\(\frac{4}{3}\)
\(\frac{-3}{4},\frac{-1}{2},\frac{1}{4}\)
\(\frac{-3}{4},\frac{4}{3},\frac{1}{4}\)
\(\frac{-7}{4},-1,0\)
6.
| Numbers | Associative for | |||
| Addition | Subtraction | Multiplication | Division | |
| Whole numbers | yes | ________ |
_________ |
________ |
7.
| Numbers | Closed under | |||
| Addition | Subtraction | Multiplication | Division | |
| Natural numbers | ___________ | no | ___________ | __________ |
8.
| Numbers | Closed under | |||
| Addition | Subtraction | Multiplication | Division | |
| Whole numbers | ___________ | ___________ | Yes | __________ |
9.
Write five rational numbers between the multiplicative inverse of \(5{1\over5}\) and additive inverse of 1.
10.
Write five rational numbers which are greater than -7
11.
Find five rational numbers between \({1\over4}and\ {1\over2}\)
12.
Find ten rational numbers between \({-2\over5} and {1\over2}\)
13.
Multiply the multiplicative inverse of -2 with its reciprocal.
14.
Solve \(-5+{7\over10}+{3\over7}+(-3)+{5\over14}+{-4\over5}\)
15.
Find using distributivity. \(\{ {9\over16}\times {4\over12} \} +\{ {9\over 16}\times {-3\over 9} \}\)
16.
Find using distributivity. \( \{{7\over5}\times ({-3\over12}) \}+ \{{7\over16}\times {5\over12} \}\)
17.
Verify that -(-x) = x,for x = \(-13\over17\)
18.
Write the additive inverse of the following \(19\over-6\)
19.
Write the additive inverse of the following \(-5\over9\)
20.
Write the additive inverse of the following \(2\over8\)
21.
Rearrange suitably and find the sum in each of the following:
\({-5\over7}+{5\over6}+{1\over7}+3+{-13\over6}\)
22.
Find the value of \({x\over y }+xy\) , using appropriate property and name it \(x={1\over3},y={2\over 5}\)
1.
(d)
rational numbers are closed under division
2.
(a)
the identity for addition of rational numbers
3.
(b)
\(\frac{x+y}{2}\) is a rational number between x and y
4.
(a)
between x and y
5.
(b)
\(\frac{-3}{4},\frac{-1}{2},\frac{1}{4}\)
6.
( )
| Numbers | Associative for | |||
| Addition | Subtraction | Multiplication | Division | |
| Whole numbers | Yes, e.g. 2 +(0+5) =(2 +0)+5 \(\Rightarrow\)7=7, which is true |
\(No \ e.g \\ 2-(0-5)\\ \neq (2-0)-5\\ \Rightarrow 7 \neq -3\) which is not true |
Yes, e.g.2 x[3 x (-5)] =(2 x3)x(-5) \(\Rightarrow\)2 x[-15]=(6)x(-5) \(\Rightarrow\)-30=- 30, which is true. |
No eg \((2\div 3)\div 5\neq 2 \div (3\div5) \\ \Rightarrow ({2\over 3})\div 5\neq2 \div ({3\over 5}) \\ \Rightarrow {2\over 3}\times {1\over 5} \neq 2 \times {5\over 3}\\ \Rightarrow {2\over 15} \neq {10\over 3}\) which is not true |
7.
( )
| Numbers | Closed under | |||
| Addition | Subtraction | Multiplication | Division | |
| Natural numbers | yes e.g (2+3=5)Natural numbers | no e.g (2-3=-1)Not a Natural numbers | e.g (2x3=6)Natural numbers | no e.g (2\(\div\) 3)Not a Natural numbers |
8.
( )
| Numbers | Closed under | |||
| Addition | Subtraction | Multiplication | Division | |
| Whole numbers | yes e.g (0+5=5)Whole numbers | No e.g (5-7=-2)Not a Whole numbers | Yes e.g (3x7=21)Whole numbers | No e.g (5\(\div\)8) Not a Whole numbers |
9.
The multiplicative inverse of \(5{1\over5}\) \((={26\over5})\ is\ {5\over26}\)
And the additive inverse of 1 is-1.
Now, on making same denominator, we get
-1 = \({-1\times26\over 26}\)
10.
Five rational numbers greater than -7 are
\({-7\over2},{-7\over3},{-7\over4},{-7\over5},{-7\over6}\)
11.
Converting \(\frac { 1 }{ 4 } \) and \(\frac { 1 }{ 2 } \) rational numbers with the same denominations , we have
\(\frac { 1 }{ 4 } \times \frac { 8 }{ 8 } =\frac { 8 }{ 32 } \) and \(\frac { 1 }{ 2 } \times \frac { 16 }{ 16 } =\frac { 16 }{ 32 } \)
Five rational numbers between \({8\over32}=({1\over4})and{16\over32}=({1\over2})are{9\over32},{10\over32},{11\over32},{12\over32},{13\over32}\)
12.
We have, \({-2\over5}={-2\times4 \over 5\times4}={-8\over20}\)
[multiplying the numerator and denominator both by 4] and \({1\over2}={1\times10 \over 2\times10}={10\over20}\)
Here, difference between 10 and -8 = 10 - (-8) = 18
(i.e. more than 10)
Hence, rational numbers between \({-8\over20}and {10\over20}\) are \({-7\over20},{-6\over20},{-5\over20},{-4\over20},{-3\over20}.{-2\over20},{-1\over20},0,{1\over20},{2\over20}\)
13.
\(1\over4\)
14.
\(-256\over35\)
15.
We have,\(\{ {9\over16}\times {4\over12} \} +\{ {9\over 16}\times {-3\over 9} \} = {9\over16} \times [{4\over12}+({-3\over9})] \)
[by distributivity, taking \( {9\over16}\) as common factor]
\(={9\over16}\times[{4\over12}-{3\over9}]={9\over16}\times[{12-12\over36}]\)
\([\because LCM \ of\ 12\ and \ 9=36]\)
\(={9\over16}\times {0\over36}\)
\(= {9\over16}\times0=0\)
16.
We have, \( \{{7\over5}\times ({-3\over12}) \}+ \{{7\over16}\times {5\over12} \}={7\over5}\times[{-3\over12}+{5\over12}]\)
[by distributivity, taking \({7\over5}\) as common factor]
\(={7\over5}\times[{-3+5 \over 12}]= {7\over5}\times {2\over 12}={7\over30}\)
17.
We have, x = \(-13\over17\)
\(LHS =-(-x)=-\{-({-13\over17})\}=-\{{13\over17}\}\)
=-\({13\over17}\) = x = RHS
So, - (-x) = x is verified for x = \({13\over17}\).
18.
we have, \(19\over-6\) so, additive inverse of \(19\over-6\) is \(19\over6\)
19.
we have, \(-5\over9\) so, additive inverse of \(-5\over9\) is \(5\over9\)
20.
we have, \(2\over8\) so, additive inverse of \(2\over8\) is \(-2\over8\)
21.
\(23\over21\)
22.
\({29\over30}\)
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