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TN 12th Computer Applications வலையமைப்பு வடமிடல் Sample Question Papers Study Material - QB365 Set A

Published on: 28/11/2025
Download Tamil Nadu 12th Standard Chemistry question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
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1.
Which of the following is a co-polymer?
Orlon
PVC
Teflon
PHBV
2.
Which one given below is a non-reducing sugar?
Glucose
Sucrose
maltose
Lactose
3.
The product formed by the reaction an aldehyde with a primary amine ________.
carboxylic acid
aromatic acid
schiff ’s base
ketone
4.
The method by which aniline cannot be prepared is _________.
degradation of benzamide with Br2 / NaOH
potassium salt of phthalimide treated with chlorobenzene followed by hydrolysis with aqueous NaOH solution.
reduction of Nitrobenzene with LiAlH4
reduction of nitrobenzene by Sn / HCl
5.
Which one of the following reduces tollens reagent
formic acid
acetic acid
benzophenone
none of these
6.
7.
HO CH2 CH2 – OH on heating with periodic acid gives ______.
methanoic acid
Glyoxal
methanol
CO2
8.
9.
Which of the following compounds on reaction with methyl magnesium bromide will give tertiary alcohol.
benzaldehyde
propanoic acid
methyl propanoate
acetaldehyde
10.
Which one of the following is correctly matched?
Emulsion - Smoke
Gel - butter
foam - Mist
whipped cream - sol
11.
Fog is colloidal solution of _______.
solid in gas
gas in gas
liquid in gas
gas in liquid
12.
Which of the following electrolytic solution has the least specific conductance?
2N
0.002N
0.02N
0.2N
13.
Faraday constant is defined as_______.
charge carried by 1 electron
charge carried by one mole of electrons
charge required to deposit one mole of substance
charge carried by 6.22 ×1010 electrons
14.
The percentage of pyridine (C5H5N) that forms pyridinium ion (C5H5NH) in a 0.10M aqueous pyridine solution _______.(Kb for C5H5N = 1.7×10-9) is
0.006%
0.013%
0.77%
1.6%
15.
The solubility of BaSO4 in water is 2.42 × 10-3gL-1 at 298K. The value of its solubility product(Ksp) will be (Given molar mass of BaSO4 =233g mol-1)
1.08 × 10-14mol2L-2
1.08 × 10-12mol2L-2
1.08 × 10-10mol2L-2
1.08 × 10-8mol2L-2
16.
What is the major product obtained when 2,3 – dimethyl pentan -3 – ol is heated in the presence of H2SO4.
17.
What is the action of HCN on
(i) propanone
(ii) 2,4-dichlorobenzaldehyde
iii) ethanal
18.
Explain any one method for coagulation.
19.
Which will be adsorbed more readily on the surface of charcoal and why? NH3 or CO2?
20.
Why does conductivity of a solution decrease on dilution of the solution.
21.
There are two isomers with the formula CH3NO2. How will you distinguish between them?
22.
Write a note on denaturation of proteins.
23.
Define ionic product of water. Give its value at room temperature.
24.
25.
3,3 – dimethylbutan -2-ol on treatment with conc. H 2SO4 to give tetramethyl ethylene as a major product. Suggest a suitable mechanism.
26.
27.
Describe adsorption theory of catalysis
28.
How will you distinguish between primary secondary and tertiary alphatic amines.
29.
Describe the construction of Daniel cell. Write the cell reaction.
30.
What are bio degradable polymers? Give examples.
31.
Give the differences between primary and secondary structure of proteins.
32.
What type of linkages hold together monomers of DNA?
33.
Derive an expression for Ostwald’s dilution law.
34.
Explain common ion effect with an example.
35.
Write all the possible isomers of an alcohol having the molecular formula C5H12O and give their IUPAC names.
36.
Write a note on catalytic poison
37.
Write a note on electro osmosis.
38.
Why is AC current used instead of DC in measuring the electrolytic conductance?
39.
State Faraday’s Laws of electrolysis
40.
Write the expression for the solubility product of Ca3(PO4)2
41.
How is terylene prepared?
42.
What are food preservatives?
43.
What are reducing and non – reducing sugars?
1.
(d)
PHBV
2.
(b)
Sucrose
3.
(c)
schiff ’s base
4.
(b)
potassium salt of phthalimide treated with chlorobenzene followed by hydrolysis with aqueous NaOH solution.
5.
6.
(d)
7.
(c)
methanol
8.
(c)
9.
10.
(b)
Gel - butter
11.
dispersion medium-gas
dispersed phase-liquid
12.
In general, specific conductance of an electrolyte decreases with dilution.So,0.002N solution has least specific conductance.
13.
IF = 96500 C = charge of one mole of e- charge of 6.022 x 10-23 electron
14.
C5H5N + H-OH ⇌ C5H5 +NH + OH-
\(\frac { { \alpha }^{ 2 }{ C } }{ 1-\alpha } =K_b\)
\(\alpha\)2C \(\approx\) Kb
\(\alpha = \sqrt {\frac{K_b} C} = \sqrt {\frac{1.7 \times 10^{-9}} {0.1}}\)
\(= \sqrt{1.7} \times 10^{-4}\)
Percentage of dissociation =\(= \sqrt{1.7} \times 10^{-4}\) x 100
= 1.3 x 10-2 = 0.013%
15.
BaSO4 ⇌ Ba2+ + SO42-
Ksp = (s) (s)
Ksp = (s)2
= (2.42 × 10-3gL-1)2
\(=\frac{2.42 \times 10^{-3} gL^{-1}}{233 \text{ g mol}^{-1}}\)
= (0.01038 x 10-3)2
= (1.038 x x 10-5)2
= 1.077 x 10-10
= 1.08 × 10-10mol2L-2
16.
17.
(ii) 2,4-dichlorobenzaldehyde.
(iii) ethanal
18.
Addition of electrolytes:
A negative ion causes the precipitation of positively charged sol and vice versa. When the valency of ion is high, the precipitation power is increased.
For example, the precipitation power of some cations and anions varies in the following order
\(\mathrm{Al}^{3+}>\mathrm{Ba}^{2+}>\mathrm{Na}^{+} \text {, Similarly }\left[\mathrm{Fe}\left(\mathrm{CN}_{6}\right)\right]^{3-}>\mathrm{SO}_{4}{ }^{2-}>\mathrm{Cl}^{-}\)
The precipitation power of electrolyte is determined by finding the minimum concentration (millimoles/lit) required to cause precipitation of a sol in 2 hours. This value is called flocculation value. The smaller the flocculation value greater will be precipitation.
19.
The critical temperature of NH3 is 406 K and that of CO2 is 304 K. So, NH3 has higher critical temperature and greater VanderWaal's forces of attraction than CO2. So NH3 will be more adsorbed than CO2.
20.
On dilution the concentration decreases. Conductivity decreases with decrease in concentration (or dilution) as the number of ions per unit volume that carry the current in a solution decrease on dilution.
21.
a) Primary and secondary nitroalkanes, having α-H, also show an equilibrium mixture of two tautomers namely nitro - and aci - form
b) Difference:
| S.No | Nitro form | Aci - form |
| 1. | Less acidic in nature. | More acidic |
| 2. | Dissolves in NaOH slowly | Dissolves in NaOH instantly |
| 3. | Decolourises FeCl3 solution | With FeCl3 gives reddish brown colour |
| 4. | Electrical conductivity is low | Electrical conductivity is high |
22.
(i) Each protein has a unique three-dimensional structure formed by interactions such as disulphide bond, hydrogen bond, hydrophobic and electrostatic interactions. These interactions cain be disturbed when the protein is exposed to a higher temperature, certain chemicals such as urea, alteration of pH, ionic strength etc., It leads to the loss of the three-dimensional structure partially or completely. The process of a losing its higher order structure without losing the primary structure, is called denaturation. When a protein denatures, its biological function is also lost.
(ii) Since the primary structure is intact, this process can be reversed in certain proteins. This can happen spontaneously upon restoring the original conditions or with the help of special enzymes called cheperons (proteins that help proteins to fold correctly).
(iii) Example: coagulation of egg white by action of heat.
23.
(i) \(\mathrm{K}_{\mathrm{w}}=\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\left[\mathrm{OH}^{-}\right]=1 \times 10^{-14}\left(25^{\circ} \mathrm{C}\right)\)
(ii) Ionic product of water is defined as the product of the concentration of hydronium and hydroxide ions of pure water. Its value at 25oC is \(1 \times 10^{-14} \mathrm{~mol}^{2} \mathrm{dm}^{-2}\)
24.
25.
Mechanism:
This mechanism undergoes Saytzeff rule.
During intramolecular dehydration, if there is a possibility to form a carbon - carbon double bond at different locations, the preferred location is the one that gives the more (highly) substituted alkene i.e., the stable alkene.
26.
27.
1. Langmuir explained the action of catalyst in heterogeneous catalysed reactions based on adsorption. The reactant molecules are adsorbed on the catalyst surfaces, so this can also be called as contact catalysis.
2. According to this theory, various steps involved in a heterogeneous catalyse reaction are given as follows:
(i) Reactant molecules diffuse from bulk to the catalyst surface.
(ii) The reactant molecules are adsorbed on the surface of the catalyst.
(iii) The adsorbed reactant molecules are activated and form activated complex which is decomposed to form the products.
(iv) The product molecules are desorbed.
(v) The product diffuse away from the surface of the catalyst.
28.
| S.No | Reagents or Reaction | Primary amine RNH2 | Secondary amine R2NH | Tertiary amine R3N |
|---|---|---|---|---|
|
1. |
Carbylamine reaction or with CHCl3/KOH |
Carbylamine is formed (unpleasant smell) |
- | - |
| 2. | Mustard oil reaction or CS2/HgCl2 (Hoffmann's mustard oil test) |
Alkyl isothiocyanate is formed (Mustard oil odour) |
- | - |
| 3. | HNO2 (or) NaNO2 / HCl |
Alcohol is formed +H2 | Yellow oily nitrosoamine is formed, insoluble in water. (Liberman's Test) |
Forms nitrite in cold, soluble in water. |
| 4. | CH3COCl | N-acetyl derivative is formed | N,N- diacetyl derivative is formed |
- |
| 5. | Diethyl oxalate Hoffmann's method |
Solid oxamide is formed | Liquid oxamic ester is formed |
- |
| 6. | Benzene sulphonyl chloride in presence of excess. KOH (Hinsberg's reaction) |
N- alkyl benzene sulphonamide is formed (soluble) |
N, N - dialkyl benzene sulphonamide is formed (Insoluble). |
- |
| 7. | With RX | 1 mol → 2o amine 2 mol → 3o amine 3 mol → Quarternary salt |
1 mol → 3o amine 2 mol → Quarternary salt |
1 mol → Quarternary salt |
29.
1. Daniel cell is a galvanic cell. This is a voltaic cell also.
(a) The separation of half reaction is the basis for the construction of Daniel cell. It consists of two half cells.
(i) Oxidation half cell: A metallic zinc strip that dips into an aqueous solution of zinc sulphate taken in a beaker, as shown in Figure
(ii) Reduction half cell: A copper strip that dips into an aqueous solution of copper sulphate taken in a beaker, as shown in Figure
(iii) Joining the half cells:
(a) The zinc and copper strips are externally connected using a wire through a switch (k) and a load (example: volt meter). The electrolytic solution present in the cathodic and anodic compartment are connected using an inverted U tube containing a agar-agar gel mixed with an inert electrolyte such as KCI, Na2SO4 etc.,
(b) The ions of inert electrolyte do not react with other ions present in the half I cells and they are not either oxidised (or) reduced at the electrodes. The solution in the salt bridge cannot get poured out, but through which the ions can move into (or) out of the half cells.
(c) When the switch (k) closes the circuit, the electrons flows from zinc strip to copper strip. This is due to the following redox reactions which are taking place at the respective electrodes.
(iv) Anodic oxidation:
(i) zinc strip acts as the anode.
(ii) Here,oxidation occurs.
The electrode at which the oxidation occur is called the anode. In Daniel cell, the oxidation take place at zinc electrode, i.e., zinc is oxidised to Zn2+ ions and the electrons.
The Zn2+ ions enters the solution and the electrons enter the zinc metal, then flow through the external wire and then enter the copper strip.
Electrons are liberated at zinc electrode and hence it is negative (-ve).
\(Zn_{ (s) }\longrightarrow { { Zn }^{ 2+ }_{ (aq) }+{ 2e }^{ - } } \) (loss of electron-oxidation)
(v) Cathodic reduction:
As discussed earlier. the electrons flow through the circuit from zinc to copper, where the Cu2+ ions in the solution accept the electrons, get reduced to copper and the same get deposited on the electrode Here, the electrons are consumed and hence it is positive (+ve).
\({ Cu }_{ (aq) }^{ 2+ }+{ 2e }^{ - }\longrightarrow { { Cu }_{ (s) } } \)(gain of electron - reduction)
b) When a Zinc metal strip is placed in a copper sulphate solution, the blue colour of the solution fades and the copper is deposited on the zinc strip as red - brown crust due to the following spontaneous chemical reaction.
\(\mathrm{Zn}_{(\mathrm{s})}+\mathrm{CuSO}_{4(\mathrm{aq})} \rightarrow \mathrm{ZnSO}_{4(\mathrm{aq})}+\mathrm{Cu}_{(\mathrm{s})}\)
The energy produced in the above reaction is lost to the surroundings as heat.
In the above redox reaction, Zinc is oxidised to Zn2+ ions and the Cu2+ ions are reduced to metallic copper. The half reactions are represented as below.
\(\mathrm{Zn}_{(\mathrm{s})} \rightarrow \mathrm{Zn}^{2+}{ }_{(\mathrm{aq})}+2 \mathrm{e}^{-} \text {(oxidation) } \)
\(\mathrm{Cu}^{2+}{ }_{(\mathrm{aq})}+2 \mathrm{e}^{-} \rightarrow \mathrm{Cu}_{(\mathrm{s})} \text { (reduction) }\)
If we perform the above two half reactions separately in an apparatus as shown in figure, some of the energy produced in the reaction will be converted into electrical energy.
30.
1. The materials that are readily decomposed by microorganisms in the environment are called biodegradable.
2. Natural polymers degrade on their own after certain period of time but the synthetic polymers do not.
3. It leads to serious environmental pollution. One of the solution to this problem is to produce biodegradable polymers which can be broken down by soil micro organism.
Examples:
(i) Polyhydroxy butyrate (PHB)
(ii) Polyhydroxy butyrate-co-A- hydroxyl valerate (PHBV)
(iii) Polyglycolic acid (PGA), Polylactic acid (PLA)
(iv) Poly ( E caprolactone) (PCL)
(v) Biodegradable polymers are used in medical field such as surgical sutures, plasma substitute etc...
4. these polymers are decomposed by enzyme action and are either metabolized or excreted from the body.
31.
Primary structure of Proteins:
Proteins are polypeptide chains, made up of amino acids are connected through peptide bonds. The relative arrangement of the amino acids in the polypeptide chain is called the primary structure of the protein. Knowledge of this is essential as even small changes have potential to alter the overall structure and function of a protein.
\(\mathrm{H}_{2} \mathrm{~N}-\mathrm{Gly}-\mathrm{Met}-\mathrm{Phe}-\mathrm{Cys}-\mathrm{Arg}-\mathrm{Asp}-\mathrm{COOH}\)
α - Helix:
In the α-helix sub-structure, the amino acids are arranged in a right handed helical (spiral) structure and are stabilised by the hydrogen bond between the carbonyl oxygen of one amino acid (n residue) with amino hydrogen of the fifth residue (n + 4th residue). The side chains of the residues protrude outside of the helix. Each turn of an α-helix contains about 3.6 residues and is about 5.4 Å long. The amino acid proline produces a kink in the helical structure and often called as a helix breaker due to its rigid cyclic structure.
1. Linear sequence of aminoacids
2. Linear
3. Composed of peptide bonds formed between amino acids.
Secondary structure of Proteins:
The amino acids in the polypeptide chain forms highly regular shapes (sub-structures) through the hydrogen bond between the carbonyl oxygen (-C=O) and the neighbouring amine hydrogen (-NH) of the main chain. α-Helix and β-strands or sheets are two most common substructures formed by proteins.
β-Strand:
β-Strands are extended peptide chain rather than coiled. The hydrogen bonds occur between main chain carbonyl group one such strand and the amino group of the adjacent strand resulting in the formation of a sheet like structure. This arrangement is called β-sheets.
32.
Watson & Crick proposed a 3-dimensional secondary structure of DNA. In this DNA molecule, Monomners of DNA are held together by Phosphodiester linkage. This linkages are occured in 5' & 3' carbon atoms of Pentose sugar.
33.
(i) Ostwald's dilution law relates the dissociation constant of the weak acid (Ka) with its degree of dissociation (α) and the concentration (c).
where \(\alpha=\frac{\text { Number of moles dissociated }}{\text { Total number of moles }}\)
(ii) The dissociation of acetic acid can be represented as
\(\mathrm{CH}_{3} \mathrm{COOH} \rightleftharpoons \mathrm{H}^{+}+\mathrm{CH}_{3} \mathrm{COO}^{-}\)
The dissociation constant of acetic acid is,
\({ K }_{ a }=\frac { \left[ { H }^{ + } \right] \left[ { CH }_{ 3 }COO^{ - } \right] }{ \left[ { CH }_{ 3 }COOH \right] } \) ........(1)
| CH3COOH | H+ | CH3COO- | |
| Initial number of moles | 1 | - | - |
| Degree of dissociation of CH3COOH | α | - | - |
| Number of moles at equilibrium | 1-α | α | α |
| Equilibrium concentration | (1-α)C | αC | αC |
Substituting the equilibrium concentration in equation (1)
\({ K }_{ a }=\cfrac { \left( \alpha C \right) \left( \alpha C \right) }{ \left( 1-\alpha \right) C } \)
\({ K }_{ a }=\cfrac { { \alpha }^{ 2 }C }{ 1-\alpha } \) .......(2)
(iii) We know that weak acid dissociates only to a very small extent compared to one, a is so small and hence in the denominator (1 - α) ⋍1. The above expression (2) now becomes,
ka =a2C \(\Rightarrow { \alpha }^{ 2 }=\cfrac { { k }_{ a } }{ C } \) ; \(\alpha =\sqrt { \cfrac { { K }_{ a } }{ C } } \)
(iv) When dilution increases, the degree of dissociation of weak electrolyte also increases. This is called Ostwald's dilution law
Also \(;\left[\mathrm{H}^{+}\right]=\alpha \mathrm{C}\) and \(\left[\mathrm{H}^{+}\right]=\left(\sqrt{\frac{\mathrm{K}_{\mathrm{a}}}{\mathrm{C}}}\right) \mathrm{C}=\sqrt{\frac{\mathrm{K}_{\mathrm{a}} \mathrm{C}^{2}}{\mathrm{C}}}=\sqrt{\mathrm{K}_{\mathrm{a}} \cdot \mathrm{C}}\)
Similarly for a weak base
\(\begin{aligned} & \mathrm{K}_{\mathrm{b}}=\alpha^2 \mathrm{C} ; \quad \therefore \alpha=\sqrt{\frac{\mathrm{k}_{\mathrm{b}}}{\mathrm{C}}}, \\ \end{aligned}\)
\(\begin{aligned} & {\left[\mathrm{OH}^{-}\right] \alpha \mathrm{C}=\sqrt{\frac{\mathrm{K}_{\mathrm{b}}}{\mathrm{C}}} \times \mathrm{C}=\sqrt{\frac{\mathrm{K}_{\mathrm{b}} \mathrm{C}^2}{\mathrm{C}}}=\sqrt{\mathrm{K}_{\mathrm{b}} \mathrm{C}}} \end{aligned}\)
34.
(i) The dissociation of a weak acid (CH3COOH) is suppressed in the presence of a salt (CH3COONa) containing an ion common to the weak electrolyte. It is called the common ion effect.
(ii) Consider the dissociation of a weak acid, acetic acid whose ionisation is incomplete.
CH3COOH(aq) ⇌ H+(aq) + CH3COO-(aq)
(iii) If the salt sodium acetate with common ion CH3COO- is added to the above equilibrium, it dissociates completely increasing.
CH3COONa(aq)⟶Na+(aq) + CH3COO-(aq)
(iv) Hence, the overall concentration of CH3COO- is increased, and the acid dissociation equilibrium is disturbed.
(v) So, in order to maintain the equilibrium, the excess CH3COO- ions combines with H+ ions to produce much more unionized CH3COOH i.e, the equilibrium will shift towards the left. In other words, the dissociation of CH3COOH is suppressed.
35.
36.
(i) Certain substances when added to a catalysed reaction decreases or completely destroys the activity of catalyst and they are often known as catalytic poisons.
For example,
(ii) In the reaction, 2SO2 + O2 ⟶ 2SO3 with a Pt catalyst, the poison is As2O3
(iii) i.e., As2O3 destroys the activity of Pt. As2O3 blocks the activity of the catalyst. So, the activity is lost.
37.
A sol is electrically neutral. Hence the medium carries an equal but opposite charge to that of dispersed particles. When sol particles are prevented from moving, under the influence of electric field the medium moves in a direction opposite to that of the sol particles. This movement of dispersion medium under the influence of electric potential is called electro osmosis.
38.
(a) If we apply DC current through the conductivity cell, it will lead to the electrolysis of the solution taken in the cell.
(b) So, AC current is used for this measurement to prevent electrolysis.
39.
First law:
The mass of the substance (m) liberated at an electrode during electrolysis is directly proportional to the quantity of charge (Q) passed through the cell.
m α Q \(\left[\because \mathrm{I}=\frac{\mathrm{Q}}{\mathrm{t}} \Rightarrow \mathrm{Q}=\mathrm{It}\right]\)
m α It
m = ZIt
Where Z = electro chemical equivalent of the substance
I = current
t = time of passage of current
Second law:
When the same quantity of charge is passed through the solutions of different electrolytes, the amount of substances liberated at the respective electrodes are directly proportional to their electrochemical equivalents.
m α Z
\(\frac{m_{1}}{Z_{1}}=\frac{m_{2}}{Z_{2}}\)
m = mass of the metal deposited
Z = electro chemical equivalent
40.
\(\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2} \rightleftharpoons 3 \mathrm{Ca}^{2+}_{(aq)}+2 \mathrm{PO}_{4_{(aq)}}^{3-}\\\)
(s) (3s) (2s)
\(K_{sp}=[Ca^{2+}]^{3}[PO_{4}^{3-}]^{2}\)
\(K_{sp}=(3s)^{3}(2s)^{2}\)
\(K_{sp}=27s^{3}.4s^{2}\)
\(K_{sp}=108s^{5}\)
(or)
\(K_{s p} =m^{m} \cdot n^{n} \cdot(s)^{m+n} \)
\(K_{\text {sp }} =3^{3} \cdot 2^{2} \cdot(s)^{3+2} \)
\(K_{s p} =27 \times 4 \times(s)^{5} \)
\(=108(s)^{5}=108 s^{5}\)
41.
(i) Monomers :Ethylene glycol and terepathalic acid (or) dimethyl terephthalate.
(ii) Catalyst : Zinc acetate and antimony trioxide.
(iii) Temperature : 500 K
(iv) Product : Terylene
(v) Uses : blending with cotton or wool fibres and as glass reinforcing materials in safety helmets
42.
(i) Preservatives are chemicals added to food which are capable of inhibiting, retarding or arresting the process of fermentation, acidification or other decomposition of food by the growth of micro organisms (or)
(ii) Chemical substances which are added to food that prevents the spoilage of food materials by destroying the food - spoiling micro-organisms are called food preservatives.
(iii) Eg: sodium benzoate, NaCl, Acetic acid Sodium metabisulphite, potassium meta bisulphite etc.
43.
i) Reducing sugars:
1. Sugars which reduce Tollen's reagent or Fehling's solution or Benedict's solution are called reducing sugars.
2. These contain either α - hydroxyl ketone or cyclical hemi acetal or hemi ketal or structures in equilibrium with open chain forms having a free- CHO or C=O group.
3. E.g. a) All monosaccharide's like D - glucose, D - fructose (aldoses and ketoses)
b) Sugars like Lactose and maltose except sucrose.
ii) Non - reducing sugars:
1. Sugars which do not reduce either Tollen's reagent, Fehling's solution or Benedict's solution are called non-reducing sugars.
2. They contain a stable acetal or ketal structures which cannot be opened into a free carbonyl group.
E.g. Sucrose, starch, cellulose, glycogen, dextrin etc.
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