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Published on: 22/10/2025
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1.
If the mean and the mode of a distribution are 15 and 18 respectively, then the median of the distribution is
17
15
16
18
2.
The median class for the data given below is
| Class | 20-40 | 40-60 | 60-80 | 80-100 | 100-120 |
| Frequency | 10 | 12 | 14 | 13 | 17 |
80 - 100
20 - 40
40 - 60
60 - 80
3.
The median of first seven prime numbers is
5
7
11
13
4.
For the following distribution
| Class | 0-5 | 5-10 | 10-15 | 15-20 | 20-25 |
| Frequency | 10 | 15 | 12 | 20 | 9 |
The lower limit of modal class is
15
25
30
35
5.
The time in seconds, taken by 150 athletes to run a 100m hurdle race are tabulated below
| Time (sec) | 13-14 | 14-15 | 15-16 | 16-17 | 17-18 | 18-19 |
| Number of Athletes | 2 | 4 | 5 | 71 | 48 | 20 |
The number of athletes who completed the race in less than 17 sec, is
11
71
82
68
6.
If the mean of 6, 7, x, 8, y, 14 is 9, then
x + y = 21
x + y = 19
x - y = 19
x - y = 21
7.
If the mean of five observations x, x + 2, x + 4, x + 6 and x + 8 is 11, then the values of x is
4
7
11
6
8.
The mean of five observations is 15. If the mean of first three observations is 14 and that of the last three observations is 17, then the third observation is
20
19
18
17
9.
If the mean and median of a data are 10 and 11 respectively, then mode of the data is
12
8
20
13
10.
If for a distribution \(\sum_1^n f_i x_i=132+5 p, \sum_1^n f_i=20\) and mean of the distribution is 8.1, then the value of p is
3
6
4
5
11.
For the following frequency distribution
| Class | Frequency |
| 0-5 | 2 |
| 5-10 | 7 |
| 10-15 | 18 |
| 15-20 | 10 |
| 20-25 | 8 |
| 25-30 | 5 |
If the mode and the median are 12.9 and 14.44 respectively, then the mean is
15.2
16
13
17
12.
If median of 20 observations is 50 and mode is also 50, then the mean is
55
49
50
45
13.
If the mean of the following distribution is 6, find the value of ‘p’.
| x | 2 | 4 | 6 | 10 | p+6 |
| f | 3 | 2 | 3 | 1 | 2 |
7
12
8
6
14.
The mean of first ten even natural numbers is
30
11
100
10
15.
If the point of intersection of a less than and more than ogive is (15,20), then the value of median is
5
20
15
35
16.
Ths symbol Σ(sigma) stands for
Multiplication
Subtraction
Summation
Division
17.
The median of the given data is 46 and the total number of items is 230
| variable | Frequency | Cumulative Frequency |
| 10-20 | 12 | 12 |
| 20-30 | 30 | 42 |
| 30-40 | 34 | 76 |
| 40-50 | 65 | 141 |
| 50-60 | 46 | 187 |
| 60-70 | 25 | 212 |
| 70-80 | 18 | 230 |
Using the formula Mode = 3 Median – 2 Mean, the mean will be
45.9
44.5
44
43
18.
What is the empirical relationship between the three measures of central tendency?
3 Mean = Mode + 2 Median
3 Median = Mode + 2 Mean
3 Median = 2Mode + Mean
3 Mean = 2Mode + Median
19.
The mean and median of same data are 24 and 26 respectively. The value of mode is :
23
25
30
26
20.
The mean of a data set with 12 observations is calculated as 19.25. If one more value is included in the data, then for the new data with 13 observations, mean becomes 20. Value of this 13th observation is
30
28
31
29
21.
| Expenditure | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
| No of famileis | 14 | 23 | 27 | 21 | 15 |
What is the mode of the given data
24
22
25
21
22.
Find the median class of the following distribution
| Class | 100-200 | 200-300 | 300-400 | 400-500 | 500-600 | 600-700 |
| Frequency | 25 | 35 | 26 | 44 | 18 | 12 |
400-500
300-400
200-300
500-600
23.
If the mean and the median are 25.41 and 26.5 respectively. then the mode is
29
28.68
25.6
28
24.
The lower limit of the modal class of the following data is
| C.I | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
| Frequency | 5 | 8 | 13 | 7 | 6 |
10
50
30
20
25.
Calculate mode of the following data: 20,60,70,70,60,70,60,10,70,80
70
20
80
60
26.
If the mean of the following data is 18.75, then the value of p is
| x1 | 10 | 15 | p | 25 | 30 |
| f1 | 5 | 10 | 7 | 8 | 2 |
18.5
20
15
30
27.
The mean of 5 observations x, x + 2, x + 4, x + 6 and x + 8 is 11, then the value of x is:
6
11
4
7
28.
If there are two class intervals 10-20 and 20-30, then in which interval will 20 fall?
10-20
20-30
Neither in 10-20 nor 20-30
In both, 10-20 and 20-30
29.
Mode is not affected by
Maximum value
Minimum value
Extreme values
All of the above
30.
For the following distribution the modal class is
| Marks below | 10 | 20 | 30 | 40 | 50 | 60 |
| Number of students | 2 | 11 | 25 | 45 | 57 | 75 |
20-30
40-50
30-40
10-20
31.
Frequency table of the marks of 50 students as given below:
| Marks Obtained | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 |
| No of students | 3 | f1 | 20 | 10 | 5 | f2 |
Given that the median marks are 28.5, the missing frequencies will be
f1 = 7, f2 = 9
f1 = 5, f2 = 7
f1 = 8, f2 = 7
f1= 7, f2 = 5
32.
Which measure of central tendency takes in account all the data?
Mean
Median
Mode
All of the above
33.
The mode, median and mean of the following data are:
| Marks obtained | Frequency | Cumulative Frequency |
| 0-10 | 5 | 5 |
| 10-20 | 10 | 15 |
| 20-30 | 18 | 33 |
| 30-40 | 30 | 63 |
| 40-50 | 20 | 83 |
| 50-60 | 12 | 95 |
| 60-70 | 5 | 100 |
mode = 35.45, median = 35.66, mean = 35.76
mode = 34.3, median = 36.7, mean = 36.7
mode = 33.3, median = 35.7, mean = 36.4 mode = 45.3, median = 32.7, mean = 35.4
mode = 45.3, median = 32.7, mean = 35.4
34.
The value of the observation having greatest frequency is called____
Mean
Median
Mode
All of above
35.
For a symmetrical distribution, which is correct
Mean = Median = Mode
Mean < Mode < Median
Mean > Mode > Median
Mode = Mean + Median/2
36.
A boy scored the following marks in various tests during a term, each test being marked out of 20 15, 17, 16, 7, 10, 12, 14, 16, 19, 12, 16. The median marks are
15
16
13
18
37.
The relation connecting the measures of central tendencies is
Mode = 2 median + 3 mean
Mode = 3 median – 2 mean
Mode = 3 median + 2 mean
Mode = 2 median – 3 mean
38.
Median of the data given below will lie in the class
| Height(in cm) | frequency |
| Below 140 | 4 |
| 140-145 | 7 |
| 145-150 | 18 |
| 150-155 | 11 |
| 155-160 | 6 |
| 160-165 | 5 |
150-155
140-145
160-165
145-150
39.
For the following distribution the differences in the upper limit of median and modal class is
| C1 | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
| F | 2 | 5 | 7 | 5 | 2 |
40
10
0
20
40.
The median of the following data is:
| Rent (in Rs) | 15-25 | 25-35 | 35-45 | 45-55 | 55-65 | 65-75 | 75-85 | 85-95 |
| No. of houses | 8 | 10 | 15 | 25 | 40 | 20 | 15 | 7 |
65
45
50
58
41.
| Expendicture | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
| No. of families | 14 | 23 | 27 | 21 | 15 |
What is the mode of the given data?
25
27
22
21
42.
The median of first ten natural numbers is
6
5.5
11
5
43.
A batsman in his 12th innings makes a score of 63 runs and thereby increases his average score by 2. His average score after 12th
41
60
51
45
44.
If the median of the following data is 166.79, then the mean and mode are
| Class Interval | Frequency |
| 130-140 | 5 |
| 140-150 | 9 |
| 150-160 | 17 |
| 160-170 | 28 |
| 170-180 | 24 |
| 180-190 | 10 |
| 190-200 | 7 |
Mode = 161.9 Mean = 168
Mode = 152.9 Mean = 166.73
Mode = 160.9 Mean = 167
Mode = 167.3, Mean = 168.03
45.
The mean of the following data is: 45, 35, 20, 15, 25, 40
15
25
35
30
46.
The mean of a data set with 12 observations is calculated as 19.25. If one more value is included in the data, then for the new data with 13 observations, mean becomes 20. The value of this 13th observation is
29
28
30
31
1.
(c)
16
2.
(d)
60 - 80
3.
(b)
7
4.
(a)
15
5.
(c)
82
6.
(b)
x + y = 19
7.
(b)
7
8.
(c)
18
9.
(d)
13
10.
(b)
6
11.
(a)
15.2
12.
(c)
50
13.
(d)
6
14.
(b)
11
15.
(c)
15
16.
(c)
Summation
17.
(a)
45.9
18.
(b)
3 Median = Mode + 2 Mean
19.
(c)
30
20.
(d)
29
21.
(a)
24
22.
(b)
300-400
23.
(b)
28.68
24.
(d)
20
25.
(a)
70
26.
(b)
20
27.
(d)
7
28.
(b)
20-30
29.
(d)
All of the above
30.
(b)
40-50
31.
(b)
f1 = 5, f2 = 7
32.
(a)
Mean
33.
(a)
mode = 35.45, median = 35.66, mean = 35.76
34.
(c)
Mode
35.
(a)
Mean = Median = Mode
36.
(a)
15
37.
(b)
Mode = 3 median – 2 mean
38.
(d)
145-150
39.
(c)
0
40.
(d)
58
41.
(b)
27
42.
(b)
5.5
43.
(a)
41
44.
(a)
Mode = 161.9 Mean = 168
45.
(d)
30
46.
(a)
29
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