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Published on: 19/08/2019
Light Reflection and Refraction
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1.
"A ray of light incident on a rectangular glass slab immersed in any medium emerges parallel to itself." Draw a labelled ray diagram to justify the statement?
2.
Draw a ray diagram to show the path of the reflected ray corresponding to an incident ray which is directed towards the principal focus of a convex mirror. Mark on the angle of incidence and the angle of reflection.
3.
A ray of light falls normally on the surface of a transparent glass slab. Draw a ray diagram to show its path and also mark angle of incidence and angle of emergence.
4.
"The magnification 'm' for a mirror is +1." What does this signify?
5.
Explain why a ray of light passing through the centre of curvature of a concave mirror, gets reflected along the same path?
6.
An object 1 cm high produces a real image 1.5 cm high, when placed at a distance of 15 cm from concave mirror. Calculate the position of the image.
7.
Which of the two has a great power? A lens of short focal length or a lens of large focal length
8.
What does negative sign in the value of magnification of a mirror indicate?
9.
A person uses concave mirror for shaving, where should he position his face in front of it?
10.
Where is the image formed in a convex mirror, when the object is anywhere in front of it?
11.
Draw a ray diagram showing the path of rays of light when it enters with oblique incidence (i) from air into water; (ii) from water into air.
12.
Refractive index of diamond with respect to glass is 1.6 and absolute refractive index of glass is 1.5. Find out the absolute refractive index of diamond.
13.
What are the factors that determine the focal length of a lens?
14.
Why do we prefer a convex mirror as a rear view mirror in vehicles?
15.
Define the principal focus of a concave mirror .
16.
Which of the following ray diagram is correct for the ray of light incident on a lens shown in Figure?

Fig. A
Fig. B
Fig. C
Fig. D
17.
In which of the following, the image of an object placed at infinity will be highly diminished and point sized?
Concave mirror only
Convex mirror only
Convex lens only
Concave mirror, convex mirror, concave lens and convex lens
18.
A full length image of a distant tall building can definitely be seen by using.
a concave mirror
a convex mirror
a plane mirror
both concave as well as plane mirror
19.
Which of the following statements is true?
A convex lens has 4 dioptre power having a focal length 0.25 m
A convex lens has -4 dioptre power having a focal length 0.25 m
A concave lens has 4 dioptre power having a focal length 0.25 m
A concave lens has -4 dioptre power having a focal length 0.25 m.
20.
A 10 mm long awl pin is placed vertically in front of a concave mirror. A 5 mm long image of the awl pin is formed at 30 cm in front of the mirror. The focal length of this mirror is.
- 30 cm
- 20 cm
- 40 cm
- 60 cm
21.
No matter how far you stand from a mirror, your image appears erect. The mirror is likely to be
plane
concave
convex
either plane or convex
22.
Where should an object be placed in front of a convex lens to get a real image of the size of the object?
At the principal focus of the lens
At twice the focal length
At infinity
Between the optical centre of the lens and its principal focus
23.
Which one of the following materials cannot be used to make a lens?
Water
Glass
Plastic
Clay
24.
List the sign conventions for reflection of light by spherical mirrors. Draw a diagram and apply these conventions in the determination of focal length of a spherical mirror which forms a three times magnified real image of an object placed 16 cm in front of it.
25.
(a) Draw a ray diagram to show the formation of image by concave lens when an object is placed in front of it.
(b) In the above diagram mark the object -distance (u) and the image-distance (v) with their proper signs (=ve or -ve as per the new Cartesian sign convention) and state how these distance are related to the focal length (f) of the concave lens in this case.
(c) Find the nature and power of a lens which forms a real and inverted image of magnification -1 at a distance of 40 cm from its optical centre.
26.
It is desired to obtain an erect image of an object, using concave mirror of focal length of 12 cm
(i) What should be the range of distance of an object placed in front of the mirror?
(ii) Will the image be smaller or larger than the object? Draw ray diagram to show the formation of image in this case.
(iii) Where will the image of this object be, if its placed 24 cm in front of the mirror?
Draw a ray diagram for this situation also to justify your answer.
Show the positions of the pole, the principal and the centre of curvature in the above ray diagrams.
27.
(i) One half of a convex lens of focal length 10 cm is converted with a black paper. Can such a lens produce an image of a complete object placed at a distance of 30 cm from the lens? Draw ray diagram to justify your answer.
(ii) A 4 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 20 cm. The distance of the object from the lens is 15 cm. Find nature, position and size of the image.
28.
The image of a candle flame formed by a lens is obtained on a screen placed on the other side of the lens. If the image is three times the size of the flame and the distance between lens and image is 80 cm, at what distance should the candle be placed from the lens? What is the nature of the image at a distance of 80 cm and the lens?
29.
Write laws of refraction. Explain the same with the help of ray diagram, when a ray of light passes through a rectangular glass slab.
1.
-S.png)
Angle of refraction = 40o
Deviation of rays
Angle of emergence = 55o
Direction of rays
2.

ㄥi = Angle of incidence
ㄥr = Angle of refraction
3.
-S.png)
4.
(a) Image is of same size as the object.
(b) Image is virtual and erect.
5.
The ray passing through the centre of curvature incident to the mirror along its normal so angle i = angle r = 0. Therefore, the ray retraces its path.
6.
\(-\frac { v }{ u } =\frac { h' }{ h } \\ \frac { -v }{ -15 } =\frac { -1.5 }{ 1 } \\ v=-22.5cm\)
7.
A lens of short focal length
8.
Image is real
9.
Between pole and principal focus
10.
Between pole and focus, behind the convex mirror.
11.
(i) When ray of light enters from air medium into water, medium it bends towards the normal as shown.
-S.png)
(ii) When ray of light enters from water medium into air medium, it bends away from the normal as shown
-S.png)
12.
\(^{ g }{ n }_{ d }=1.6.{ n }_{ g }=1.5,{ n }_{ d }=?\\ ^{ g }{ n }_{ d }=\frac { { n }_{ d } }{ { n }_{ g } } \Rightarrow 1.6-\frac { { n }_{ d } }{ 1.5 } \\ or\quad { n }_{ d }=1.6\times 1.5=2.40\)
13.
The focal length of a lens depends on
(a) Radii of curvature of the surface of the lens.
(b) Nature of material of the lens.
(c) Nature of medium in which lens is placed.
14.
The field of view of a convex mirror is wider than that of concave mirror and convex mirror always produces erect image of object, so we prefer convex mirror as rear view mirror for vehicles.
15.
The principal focus of a concave mirror is a point on the principal axis at which a light ray parallel to the principal axis converges after reflection.
Light rays that are parallel to the principal axis of a concave mirror converge at a specific point on its principal axis after reflecting from the mirror. This point is known as the principal focus of the concave mirror.
It is denoted by F.
16.
(a)
Fig. A
17.
(d)
Concave mirror, convex mirror, concave lens and convex lens
18.
(b)
a convex mirror
19.
(a)
A convex lens has 4 dioptre power having a focal length 0.25 m
20.
(b)
- 20 cm
21.
(d)
either plane or convex
22.
(b)
At twice the focal length
23.
(d)
Clay
24.
(a) Sign conventions
1. The object is always placed to the left of the mirror.
2. All the distances parallel to the principal axis are always measured from the pole of the spherical mirror.
3. All the distances measured along the direction of incident light (along +ve x-axis), are considered to be positive.
4. Those distances measured opposite to the direction of incidence light (i.e. along -ve x-axis), are taken as negative.
5. The distances measured in upward direction, i.e. perpendicular to and above the principal axis (along +ve y-axis), are taken as positive.
6. The distances measured in the downward direction, (along -ve y-axis), i.e. perpendicular to and below the principal axis are taken as negative.
(b) u=-16cm, m=-3 for real But \(m=-\frac { v }{ u } =-3\)
v = 3u = 3 (-16) = -48 cm.
Using mirror formula
\(\frac { 1 }{ f } =\frac { 1 }{ v } +\frac { 1 }{ u } \)
We get, \(\frac { 1 }{ f } =\frac { 1 }{ -48 } +\frac { 1 }{ -16 } \)
\(=\frac { 1 }{ -48 } -\frac { 1 }{ 16 } =\frac { -1-3 }{ 48 } =\frac { -4 }{ 48 } =\frac { -1 }{ 12 } \)
f=-12cm
(c) Negative sign of focal length indicated that mirror is concave in nature.
-S.png)
25.
-S.png)
(b) CB=-uCF = -fCB=-v
The relation between u, v and f is given by the lens formula:
\(\frac { 1 }{ f } =\frac { 1 }{ v } -\frac { 1 }{ u } \)
As both u and v are negative the above equation will change to
\(\frac { 1 }{ f } =\frac { 1 }{ (-v) } -\frac { 1 }{ (-u) } \)
\(\frac { 1 }{ f } =\frac { -1 }{ v } +\frac { 1 }{ u } \)
\(\Rightarrow \frac { 1 }{ f } =\frac { 1 }{ u } -\frac { 1 }{ v } \)
We know that the focal length of a concave lens is negative, so the above equation will be changed to
\(\frac { 1 }{ -f } =\frac { 1 }{ u } -\frac { 1 }{ v } \)
\(\Rightarrow \frac { 1 }{ f } =\frac { 1 }{ v } -\frac { 1 }{ u } \)
(c) Magnification m=-1
v = + 40 cm (real and inverted)
Nature of the lens = ?
Power of the lens, P =?
\(\frac { v }{ u } =m\Rightarrow \frac { +40 }{ u } =-1\)
40=-u ⇒ u = -40 cm
According to the lens formula,
\(\frac { 1 }{ f } =\frac { 1 }{ v } -\frac { 1 }{ u } \)
\(\Rightarrow \frac { 1 }{ f } =\frac { 1 }{ 40 } -\frac { 1 }{ -40 } =\frac { 1 }{ 40 } +\frac { 1 }{ 40 } =\frac { 2 }{ 40 } =\frac { 1 }{ 20 } \)
f = +20 cm
fis +ve thus the lens is convex
\(P=\frac { 1 }{ f(metres) } =\frac { 1\times 100 }{ 20 } =+5D\)
Since power of lens is positive, lens will be converging in nature.
26.
In a concave mirror an erect image will be obtained when the object is placed between pole and focus of the mirror.
-S.png)
Since, focal length is 12 cm,
(i) Therefore, the range of object distance is between 0 cm to <12 cm (from zero to less than 12 cm).
(ii) Image formed wall be magnified. i.e. larger than the object.
(iii) If the object is placed at 24 cm in front of the mirror, it means that object is placed at 2F. ie., at the centre of curvature (at C) of the mirror.
-S.png)
The real, inverted and same size (of the object) image will also be formed at 24 cm.
27.
(i) Yes.If a convex lens of focal length 10cm is covered one half with a black paper, it can produce an image of the complete object between F2 and 2F2.The rays of light coming from the object get refracted by the upper half of the lens. The image formed will be real, inverted and diminished.

(ii)Object height, h1=4cm
Focal length, f=+20cm
Object distance, u=-15cm
Image distance, v=?
Image height, h2=?
By lens formula,
\({1\over f}={1\over v}-{1\over u}\)
\(\Rightarrow\ {1\over v}={1\over f}+{1\over u}={1\over +20}+{1\over -15}={1\over 20}-{1\over 15}\)
\(\Rightarrow\ {1\over V}={3-4\over 60}={-1\over 60}\)
v=-60cm
Negative sign of v shows that the image is virtual.
28.
Given m = -3, v = 80 cm, u = ?
Using the expression \(m=\frac { -v }{ u } \)
we have \(-3=\frac { 80 }{ u } \) or \(u=\frac { -80 }{ 3 } =-26.67cm\)
The image is real and the lens is a convex lens.
29.
The following are the laws of refraction of light.
(i)The incident ray, the refracted ray and the normal to the interface of two transparent media at the point of incidence, all lie in the same plane.
(ii)The ratio of sine of angle of incidence to the sine of angle of refraction is a constant, for the light of a given pair of media. This law is also known as Snell's law of refraction. The ray diagram is as shown. As seen in the refracted ray are in the same plane.
-S.png)
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