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Published on: 14/09/2019
Laws of Motion
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1.
Why are curved roads generally banked?
2.
A stone, when thrown on a glass window, smashes the window pane to pieces. But a bullet fired from a gun passes through making a hole. Why?
3.
Name the forces which have shortest range and the longest range.
4.
The linear momentum of the body can change only in the direction of applied force. Comment.
5.
What provides the centripetal force to a car taking a turn on a level road?
6.
Which law of motion is involved in rocket propulsion?
7.
What is the apparent weight felt by a person in an elevator, when it is accelerating: (i) upward (ii) downward?
8.
What is the angle between frictional force and instantaneous velocity of the body moving over a rough surface?
9.
An athlete runs some distance before taking a jump. Explain why?
10.
Explain why a cricketer moves his hands backwards while holding a catch.
11.
Explain why passengers are thrown forward from their seats when a speeding bus stops suddenly,
12.
A body of mass 2 kg is being dragged with a uniform velocity of 2 ms -1 on a rough horizontal plane. The coefficient of friction between the body and the surface is 0.2. Calculate the amount of heat generated per second. Take g =9.8 ms-2 and J = 1.2Jcal-1
13.
A force of 128 If acts on a mass of 490 g for 10 s. What velocity will it give to the mass ?
14.
A passenger of mass 72.2 kg is riding in an elevator while standing on a platform scale. What does the scale read when the elevator cab is
(i) descending with constant velocity
(ii) ascending with constant acceleration, 3.5 m/s2?
15.
Why are porcelain objects wrapped in paper or straw before packing for transportation ?
1.
Curved roads are generally banked so as to help in providing centripetal force needed to balance the centrifugal force, arising due to circular motion on the curved road.
2.
A stone gains lesser momentum compared to a bullet. Window pane can create enough resistance to the stone, and not to the bullet.
3.
Nuclear forces have the shortest range and gravitational forces have the longest range.
4.
The statement is correct. It is in accordance with Newton's second law of motion.
5.
The force of friction between the road and the tyres of car.
6.
Newton's third law of motion
7.
(i) Apparent weight = m (g + a)
(ii) Apparent weight = m (g - a).
8.
The angle is 180°, because force of friction always opposes the relative motion.
9.
Running provides greater momentum which helps in jumping through a longer distance.
10.
The ball comes with large momentum after being hit by the batsman. When the player takes catch it causes large impulse on his palms which may hurt the cricketer. When he moves his hands backward the time of contact of ball and hand is increased so the force is reduced.
11.
The passengers in a speeding bus have inertia of motion. When the bus is suddenly stopped the passengers are thrown forward due to this inertia of motion.
12.
Given, m = 2 kg, u = 2ms-1,\(\mu \) = 0.2
Force of friction, F \(= \mu R\)
\( F=\ \mu mg\ \ \left[ \because R\ =mg \right] \)
\(F=\quad 0.2\times 2\times 9.8\)
\( F=\ 3.92Nx = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
Distance moved per second s = ut
s = \(2\times 1=2\)
Work done by friction per second, W = Fs
W = 3.92\(\times\)2 = 7.84 J
Heat produced, \(H=\frac { W }{ J } \Rightarrow \quad H=\frac { 7.84 }{ 4.2 } \)
H = 1.87 cal
13.
25.6 m/s
14.
Given, mass, m = 72.2 kg
Gravity acceleration, g = 9.8 m/s2
Scale reading = apparent weight = R = ?
(i) While descending with constant velocity, a = 0
\(\therefore \) R = mg
R = 72.2 x 9.8
\(\Longrightarrow \) R = 707.56 N
(ii) While ascending with a = 3.2 m/s2
R = m ( g + a )
R = 72.2 ( 9.8 + 3.2 ) = 938.6 N
15.
Porcelain objects are wrapped in paper or straw before packing to reduce the chances during transportation. During transportation sudden jerks or even fall can take place. Forces are created at the point of collision and the force takes longer time to reach the porcelain objects through paper or straw for same change in momentum as F = \({ \Delta p }/{ \Delta t }\) and therefore a lesser force acts on object.
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