1. Molecular mass of carbon dioxide = 44 g
2. Therefore, the mass of 1 mol of CO₂ is 44 g. As per Avogadro's rule, 1 mol of substance has \(6.022 \times 10^{23}\) molecules.
3. Therefore mass of \(6.022 \times 10^{23}\) molecules of CO₂ is 44 g.
4. Hence, the mass of 1 molecule of CO₂ is \(=\frac{44}{6.022 \times 10^{23}}=7.306 \times 10^{-23} \mathrm{~g}\)

2M

\( \text { Mass of one molecule }=\frac{\text { Molar mass }}{\text { avogadro's No. }} =\frac{194}{6.022 \times 10^{23}} g=3.22 \times 10^{-22} g \)

Molecular mass of H₂O = 2 × 1 + 16 = 18 g mol^-1
18g of water = 1 gram of molecule 
∴ 576 g of water =1/18 × 576 = 32 gram molecule

According to law of conservation of law of mass,
mass of reactants = mass of products.
AgNO₃ + NaCl⟶ AgCl + NaNO₃8.5 g
  x g          5.85 g               14.35 g
∴  x + 5.85 = 14.35 + 8.5 or  x = 17.0 g

Given,
Speed of light, c=3.0×10⁸m s⁻¹
Time taken to cover the distance =2.00 ns
2.00×10⁻⁹m
Calculation(distance travelled)
We know,
Distance travelled by light=speed of light×time taken
=(3.0×10⁸ ms⁻¹)×(2.00×10⁻⁹ s)
6.0×10⁻¹m=0.6m
Final Answer: Distance travelled by light in 2 ns is 0.6m

The coefficients of reactants and products involved in a chemical equation represented by the balanced form are known as stoichiometric coefficients N₂(g)+3H₂⟶2NH₃(g)
The stoichiometric coefficients are 1,2 and 2 respectively.

N₂O₅,CCL₄,C₆,H₁₂O₆,C₂H₆O.

A = 14g

14 g

0.33 mol

1.54 ×10³pm μ s ^-1.

Rounding off a number means that the digits which are not significant have to be dropped. The rules are as follows:
1. If the digit to be dropped is more than 5, then add 1 to the preceding significant figure. For e.g., in the number 11.06, the digit to be dropped is 6. Therefore, the preceding digit 0 is increased by one & the result is 11.1.
2. If the digit to be dropped is less than 5, then it is deleted as such without bringing any change in the preceding significant figure. For e.g., 43.123 is to report up to four significant figures, then the last digit 3 is dropped & the final answer is 43.12.
3. If the digit to be dropped is 5 then the preceding significant digit in the number may be left unchanged if it is even & may be increased by 1 in case it is odd. e.g., 1.6145, if reported up to four significant figures will become 1.614 after rounding off. Similarly, 1.6175 will become 1.618.
4. If during rounding off, more than one digit is to be dropped from a particular number, then they are dropped on at a time by following the above rules.
(i) 34.2
(ii) 10.4
(iii) 0.0460
(iv) 2810