Total number of plates = 6
i.e. The total number of outcomes = 6
.. Probability of the plate \(\boxed { 3 } \) is taken out. \({ P }_{ \boxed { 3 } }=\frac { 1 }{ 6 } \)

Median from data = x+ 2
or 21 = x + 2
x = 21-2
x = 19

Arranging in ascending order:
6,8,9,12,13,15,18,20,21,25
Since number of observations is even, the median is given by finding the average or mean of the two middle most observations:
So, median \(=\frac{13+15}{2}=\frac{28}{2}=14\)

Frequency distribution of ages of 25 students:

Age	Tally marks	Frequency
14	IIII	4
15		8
16		10
17	III	3
Total		25

 23 and 29

Total number of cards = 6
Total number of outcomes = 6
P (drawing a card with number 3) = \(\frac { 1 }{ 6 } \)

A standard deck contains 4 kings. 
So, probability of getting a king = \(\frac { 4 }{ 52 } =\frac { 1 }{ 13 } \)

Given data, 42,46,69,62,91,72,74
Ascending order of the given data
42,46,62,69,72,91,74
\(\therefore\)  Median = Middle value = 69

Given data, 12, 4, 6,7, 9,14, 26, 36
Ascending order of the given data
4,6,7,9,12,14,26,36
Range = Maximum value - t0inimum value
= 36 - 4 = 32

Possible outcomes = 1, 2, 3, 4, 5, 6
Favourable outcomes = 3, 4, 5, 6
\(\therefore\) Required probability = \(\frac { 4 }{ 6 } =\frac { 2 }{ 3 } \)

\(\frac { 1 }{ 4 } \)

Out of 6 marbles, one can be drawn in 6 ways
\(\therefore\) Total number of possible outcomes = 6
A probability of drawing marble with number 5, P(5) = \(\frac{1}{6}\)

p = 12

On arranging the data in ascending order, we get 128,132,135,139,141,143,146,149,150,151
We can observe from the ascending order of heights that last term is maximum. Thus, height of the tallest girl = 151 cm

Given data are 35,32, 35, 42, 38, 32 and 34.
For median of the given data, we first arrange the given data in ascending order, we get
Here, n = 7, which is odd
\(\left( \frac { n+1 }{ 2 } \right) ^{ th }\) data will be the median i.e. \(\frac { 7+1 }{ 2 } =\frac { 8 }{ 2 } \)=4th observation
Hence, 4th observation, i.e. 35 is the median of the given data