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Published on: 30/08/2019
Integers
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Questions + Answers key
Take MCQ Mathematics Test
1.
The maximum temperature of a city on a particular day was 18°C while the minimum temperature recorded on the same day was -3°C. What is the fall in temperature?
2.
Use the sign of >, < or = in the blank to make the statement true. (-3) + 7 - 19 ___ 15 - 8 + (-9)
3.
Solve (-6) - (-16)
4.
In a magic square, each row, column and diagonal have the same sum. Check, which of the following is a magic square?
(i)
| 5 | -1 | -4 |
| -5 | -2 | 7 |
| 0 | 3 | -3 |
(ii)
| 1 | -10 | 0 |
| -4 | -3 | -2 |
| -6 | 4 | -7 |
5.
At Srinagar, the temperature was -5° C on Monday and then it dropped by 2° C on Tuesday. What was the temperature of Srinagar on Tuesday? On Wednesday, it rose by 4°C. What was the temperature on this day?
6.
Following number line shows the temperature in degree Celsius (oC) at different places on a particular day.
What is the temperature difference between the hottest and the coldest places among the above?
7.
(- 206) \(\div\) ____ = 1
8.
(- 75) \(\div\) _____ = - 1
9.
Insert the correct sign = or \(\neq\) in the given blank space.
21 x (-9) _____ 9 x (-21)
10.
2 \(\div\) (-2) = 1
11.
a \(\div\) (-1) = - a for any integer a. Take different values of a and check.
12.
1 \(\div\) a = 1 for any integer a
13.
In a class test, (+ 3) marks are given for every correct answer and (- 2) marks are given for every incorrect answer and no marks for not attempting any question.
(i) Radhika scored 20 marks. if she has got 12 correct answers, how many questions has she attempted incorrectly?
(ii) Mohini scores (-5) marks in this test, though she has got 7 correct answers. How many questions has she attempted incorrectly?
14.
(16) \(\div\) 4 is not same as:
(-4) \(\div\) 16
-(16 \(\div\) 4)
16 \(\div\) (-4)
-4
15.
If \(\bigotimes \) , O and \(\bullet\) represent some integers on the number line, then descending order of these numbers is
\(\bullet ,\bigotimes ,\oslash ,O\)
\(\bigotimes ,\bullet ,\oslash ,O\)
\(O,\oslash ,\bigotimes ,\bullet \)
\(O,\bullet ,\bigotimes ,\oslash \)
16.
(-43) x (-99) + 43 is equal to
4300
-4300
4257
-4214
17.
The value of (-10) x (-5) + (-7) is
40
-43
43
23
1.
-21°C
2.
We have, LHS = -3 + 7 -19 = -3 + 7 -19 = - (19 + 3) + 7 = - 22 + 7 = - 15
and RHS =15 -8 + (-9) = 15 + (-8 -9) = 15 + (-17) = - 2
Since, -15 < - 2
\(\therefore\) -3 + 7 -19 < 15 - 8 + (- 9)
3.
(-6) - (-16) = -6 + (16)= + 10 or 10 [\(\because\) (-)( -) = (+), difference = 10, higher integer sign is '+']
4.
We have,
| 5 | -1 | -4 |
| -5 | -2 | 7 |
| 0 | 3 | -3 |
Sum of the digits along
Ist row = 5 + (-1) + (-4) = 5 - 5 = 0
Ilnd row = (-5) + (-2) + 7= -7 + 7=0
IIIrd row = 0 + 3 + (- 3) = 3 + (-3) = 0
Similarly, sum of the digits along
Ist column = 5 + (-5) +0=5 + (-5)=0
IInd column = (-1) + (-2) + 3= (-3) +3 =0
IIIrd column = (-4) + 7 + (- 3) = 7 + (-7) = 0
Sum of the digits along
Ist diagonal =5 + (-2) + (-3)= 5 + (-5)=0
IInd diagonal = (-4) + (-2) + 0 = - 6 \(\neq\) 0
Since, the sum of digits along the Ilnd diagonal \(\neq\) 0, so it is not a magic square.
(ii)Magic Square:
Sum of the digits along:
1st row = 1+ (-10) + 0 = 1 - 10
= -9
2nd row = (-4) + (-3) + (-2)
= (-7) + (-2) = -9
3rd row = (-6) + 4 + (-7) = (-13) + 4
= -9
1st column = 1 + (-4) + (-6) = 1 - 10
= -9
2nd column = (-10) + (-3) + 4
= (-13) + 4 = -9
3rd column = 0 + (-2) + (-7) = 0 + (-9)
=-9
One diagonal = 1 + (-3) + (-7) = 1 + (-10)
= -9
Second diagonal = (-6) + (-3) + 0
= (-9) + 0 = -9
∵ Each row, column and diagonal have the same sum.
∴ The square (ii) is the magic square.
5.
At Srinagar, temperature on Monday = - 5°C
Bur the temperature dropped 2° C on Tuesday.
\(\therefore\) Temperature on Tuesday = - 5°C - 2°C = -7°C
According to the question,
The temperature increased by 4°C on Wednesday.
Temperature on Wednesday = - 7°C + 4°C = - 3°C
Hence, temperature on Wednesday is - 3° C.
6.
Number line with all numbers is shown below:
From the above number line, the temperature of the indicated places are as follow:
| Places | Temperature |
| Lahulspiti | - 8o C |
| Srinagar | - 2o C |
| Shimla | 5o C |
| Ooty | 14o C |
| Bangalore | 22o C |
7.
( )
We have, (- 206) \(\div\) (- 206) = -206/-206 = 1 [ \(\because\) (-a) \(\div\) (-a) = 1 ]
8.
( )
We have, (-75) \(\div\) 75 = -75/75 = -1 [ \(\because\) ( -a) \(\div\) a = -1 ]
9.
( )
21 x (-9) = 9 x (-21)
10.
(b)
11.
(a)
12.
(b)
13.
Given, marks for every correct answer = + 3
Marks for every incorrect answer = - 2
(i) Total marks scored by Radhika = 20
Marks scored for correct answer = 12 \(\times\) 3 = 36
\(\therefore\) Marks given for incorrect answers
= Total marks - Marks given for correct answers
= 20 -36= -16
\(\therefore\) Number of incorrect answers
= \(\frac { Total\ Marks\ of\ incorrect\ answers }{ Marks\ of\ every\ incorrect\ answer } \)
= \(\frac { \left( -16 \right) }{ \left( -2 \right) } =\frac { -16 }{ -2 } \)= 8
Hence, Radhika attempted 8 questions incorrectly
(ii) Marks obtained by Mohini = - 5
Marks obtained for 7 correct answers = 7 \(\times\) 3 = 21
\(\therefore\)Marks obtained for incorrect answers
= - 5 - 21 = - 26
\(\therefore\)Number of incorrect answers
= \(\frac { Total~ Marks \ obtained \ for \ incorrect \ answers }{ Marks \ of \ every \ incorrect \ answer } \)
= \(\frac { -26 }{ -2 } \)
= 13
14.
(a)
(-4) \(\div\) 16
15.
(c)
\(O,\oslash ,\bigotimes ,\bullet \)
16.
(a)
4300
17.
(c)
43
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