The taxi fare after each kilometre, when the fare is Rs.15 for the first kilometre and Rs. 8 for each additional kilometre, does not form an AP as the total fare (in Rs.) after each kilometre is 15, 8, 8 ,8, .... Is the statement true? Give reasons.

Find 11th term of AP : - 5, - 5 / 2, 0, 5 / 2, ...

Which of the following form an AP? Justify your answer.
\(4,4+\sqrt{2}, 4+2 \sqrt{2}, 4+3 \sqrt{2}, \ldots\)

Find the sum of all the 11 terms of an AP whose middle most term is 30.

Split 207 into three parts such that these are in A.P. and the products of the two smaller parts is 4623.

How many terms of the AP: -15, -13, -11,.... are needed to make the sum -55? Explain the reason for double answer.

Find the sum of the two middle terms of the AP: \(-\frac{ 4}{3 },-1,-\frac{ 2}{ 3},....,4\frac{ 1}{ 3}.\)

In which of the following situations do the lists of numbers involved form an AP? Give reasons for your answers.
(i) The fee charged from a student every month by a school for the whole session, when the monthly fee is Rs.400.
(ii) The fee charged every month by a school from classes I to XII, when the monthly fee for class I is Rs.250, and it increased by Rs.50 for the next higher class.
(iii) The amount of money in the account of Varun at the end of every year when Rs.1000 is deposited at simple interest of 10% per annum.
(iv) The number of bacteria in a certain food after each second, when they double in every second.

The taxi fare each km, when the fare is Rs.15 for the first km and Rs.8 for each additional km, does not form an AP as the total fare (in Rs) after each km is 15, 8, 8, 8,.............

Two APs have the same common difference. The first term of one AP is 2 and that of the other is 7. The difference between their 10th terms is the same as the difference between their 21st terms, which is the same as the difference between any two corresponding terms. Why?