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CBSE 10th Standard Maths Subject Real Number Ncert Exemplar 2 Marks Questions With Solution 2021

Published on: 26/05/2021

QB365 Provides the updated NCERT Examplar Questions for Class 10 Maths, and also provide the detail solution for each and every ncert examplar questions , QB365 will give all kind of study materials will help to get more marks

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Std: 10th Standard CBSE - Maths

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Questions:

Generic 2

6 x 2 = 12

Check whether 12ⁿ can end with the digit 0 or 5, for any natural number n

Use Euclid's division algorithm to find the HCF of the following three numbers
625,3125 and 15625

Use Euclid's division algorithm to find the HCF of the following three numbers
4407,2938 and 1469

Use Euclid's division algorithm to find the HCF of the following three numbers
1620,1725 and 255

Use Euclid's division algorithm to find the HCF of the following three numbers
2, 7 and 12

A rational number in its decimal expansion is 327.7081. What can you say about the prime factors of q. when this number is expressed in the form \(\frac{p}{q}\)? Give reason.

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Answers Key:

Generic 2

6 x 2 = 12

Here, Number=12ⁿwhere n stand for any natural number .
Now 12ⁿ= (2² x3)ⁿ
Now , For 12ⁿ to end with 0, it should have 2 as well as 5 in its Prime factors to end with 0, Also to end with 5 , it requires at least a single multiple of 5 in its Prime Factors, So 12ⁿ cannot end with the digit 0 or 5.

625

1469

Here, 327.7081 is terminating. So, it represents a rational number.
Thus, \(327.7081=\frac { 3277081 }{ 10000 } =\frac { p }{ q } \)
Here, q = 10⁴ = 2 x 2 x 2 x 2 x 5 x 5 x 5 x 5
= 2⁴ x 5⁴ = (2 x 5)⁴
So, the prime factors of q are 2 and 5.