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Published on: 14/09/2019
State of Matter
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Questions + Answers key
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1.
Why falling liquid drops are spherical?
2.
Why liquids diffuse slowly as compared to gases?
3.
Give mathematical expression for ideal gas equation.
4.
Name four properties of gases.
5.
What is the unit of coefficient of viscosity?
6.
Define boiling point of a liquid.
7.
Calculate the volume occupied by 8.8g of CO2 at 31.1oC and 1 bar pressure. (R = 0.083 bar L K-1mol-1)
8.
The relation between pressure exerted by an ideal gas(p ideal) and observed pressure (Preal) is given by the equation,\({ P }_{ ideal }={ P }_{ real }+\frac { { an }^{ 2 } }{ { V }^{ 2 } } \)
9.
The relation between the pressure exerted by an ideal gas(p ideal) and observed pressure (Preal) is given by the equation, \({ P }_{ ideal }={ P }_{ real }+\frac { { an }^{ 2 } }{ { V }^{ 2 } } \) If the pressure is taken in Nm-2, number of moles in mol and volume in m3 , calculate the unit of 'a'
10.
Calculate the pressure exerted by 10.2 g of NH3 in a 3.0 dm3 vessel at 25oC Using ideal gas equation. The van der Waals constants are a = 4.17 dm6 atm mol-2, b = 0.0371 dm3 mol-1
11.
150 mL of a gas at NTP were taken to 20oC and 0.96 bar pressure. What is the change in volume of the gas?
12.
It is desired to increase the volume of 800 mL of a gas by 20% keeping the pressure constant. To what temperature the gas must be heated if the initial temperature is 22oC?
13.
The density of liquid CO2 at room temperature is 0.8 g cm-3 .how large a cartridge of liquid CO2 must be provided to inflate a life jacket of 4 L capacity at STP?
14.
Calculate the kinetic energy of 2g of oxygen at -23oC
15.
Use the information and data given below to answer the question, stronger intermolecular forces result in higher boiling point.
Strength of London forces increases with the number of electrons in the molecules. Boiling point of HF, HCI, HBr, and HI are 293 K, 189 K, 206 K and 238 K respectively.
Looking at the trend of boiling points of HCI, HBr, and HI, explain out of dipole-dipole interaction and London interaction, which one is predominant here.
1.
Because of the property of surface tension, liquid tends to minimise its area.
2.
In liquids, the molecules are more compact in comparison to gases.
3.
PV = nRT
Where R is called Gas constant.
4.
(i) Gases, have no definite shape and no definite volume.
(ii) There is no force of attraction existing between the molecules of gases.
(iii) Gases are highly compressible.
(iv) Gases can mix evenly and can spread in whole space.
5.
Poise.
6.
The temperature at which the vapour pressure of a liquid is equal to external pressure is called boiling point of liquid.
7.
pV = nRT
\(pV=\frac { m }{ M } RT\)
Volume occupied by 8.8g of CO2
\(V=\frac { mRT }{ pM } =\frac { 8.8g\times 0.083 \ bar \ L \ { k }^{ -1 }{ mol }^{ -1 }\times 304.1k }{ 1 \ bar\times 44g{ mol }^{ -1 } } \)
V = 5.048L
8.
If units of p = atm, units of V = dm3 ,units of n = mol then,units of
\(a=\frac { { pV }^{ 2 } }{ { n }^{ 2 } } =\frac { atm.({ dm }^{ 3 })^{ 2 } }{ (mol)^{ 2 } } =atm \ dm^{ 6 } \ mol^{ -2 }\)
9.
Given that \({ P }_{ ideal }={ P }_{ real }+\frac { { an }^{ 2 } }{ { V }^{ 2 } } \)
\(a=\frac { { pV }^{ 2 } }{ { n }^{ 2 } } \) If units of \(p={ Nm }^{ -2 }\)
units of \(V={ m }^{ 3 }\) units of n = mol
then, units of \(a=\frac { Nm^{ -2 }(m^{ 3 })^{ 2 } }{ (mol)^{ 2 } } =Nm^{ 4 } \ mol^{ -2 }\)
10.
4.89 atm
11.
V = 169.91 mL
12.
T = 87oC
13.
V = 9.82 cm3
14.
Kinetic energy is given as \({ E }_{ k }=\frac { 3 }{ 2 } nRT\)
\(n=\frac { 2 }{ 32 } =\frac { 1 }{ 16 } mol,\)
\( R=8.314 \ JK^{ -1 }mol^{ -1 },\)
\( T=273-23=250 \ K\)
\( { E }_{ k }=\frac { 3 }{ 2 } \times \frac { 1 }{ 16 } \times 8.314\times 250=194.86J\)
15.
From the information and data given in the question, we concluded that Electronegativity of chlorine, bromine, and iodine decreases in the following order.
CI > Br >
Therefore, dipole should moment decrease from HCI to HI. As a result, dipole-dipole interaction should also decrease from HCI to HI. But boiling point increases on moving from HCI and HI. This means that London forces are predominant.
This is so because London forces increases as the number of electrons in a molecules increases and in this case, number of electrons is increasing from HCI towards HI.
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