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Published on: 20/09/2019
Relations and Functions
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1.
If f(x) = x3 -\(1\over x^3\) ,Then find f(x) + f\(({1\over x})\) = 0
2.
If f(x) = x2- 3x + 4, find values of x satisfying f(x) = f(2x + 1).
3.
Determine the range and domain of the relation: R = {(x, y): y = I x + 1|, x \(\in\) Z, IxI \(\le\)3}.
4.
A function f: R \(\rightarrow\)R is defined as
\(f(x)=\begin{cases} x^2+1\quad x\le-2 \\ 2x+1 \quad -2<x\le3\\ 2x^3-3\quad 3<x<8 \end{cases}\)
Find f(-1)
5.
A function f: R \(\rightarrow\)R is defined as
\(f(x)=\begin{cases} x^2+1\quad x\le-2 \\ 2x+1 \quad -2<x\le3\\ 2x^3-3\quad 3<x<8 \end{cases}\)
Find f(0)
6.
Let R be a relation on the set Z of integers defined by R = {(x, y) : x, y \(\in\) Z, x2 + y2 = 25} Find R in roster form
7.
Let R be a relation on set N of natural numbers defined by R = {(x, y) : x, y\(\in\)N, x + 3y = 12} Find Range of R
8.
Let R be a relation on set N of natural numbers defined by R = {(x, y) : x, y\(\in\)N, x + 3y = 12} Find Domain of R
9.
Find the inverse relation \(\left( { R }^{ -1 } \right) \)in each of the following cases R= {(x,y) : x, y \(\in\) N, x + 2y = 8}
10.
Find the inverse relation \(\left( { R }^{ -1 } \right) \)in each of the following cases R = {(1,2),(1,3),(2,3),(3,2),(5,6)}
11.
If A x B = {a,1), (b,3), (a,3), (b,1), (a,2), (b,2)}. Then, find A and B.
12.
If two functions are defined as \(f(x)=\frac { 1 }{ (x-2) } ,x\neq 2\) and \(g(x)=(x-2)^{ 2 }\) then find \(\frac { f }{ g } \)
13.
If A = {1,2}, then find A x A x A
14.
If n(A) = 3 and B = {2,3,4,6,7,8}, then find the number of relations from A to B.
15.
If A = {a,b} and B = {2,3}, then find the number of relations from A to B.
Number of relations from A to B \(={ 2 }^{ n\left( A \right) \times n\left( B \right) }={ 2 }^{ n\left( A\times B \right) }\)
1.
0
2.
x = -1 and x = 2/3
3.
Domain = {-3, -2, -1,0, 1,2, 3};Range = {0,1,2,3, 4}
4.
-1
5.
1
6.
R= {(0,5), (0, -5), (3, 4), (-3, 4), (3, -4), (-3, -4), (4, 3), (-4, 3) (4, -3), (-4, -3), (5, 0), (-5, O)}
7.
Range of R = {3, 2, 1}
8.
Domain of R = {3, 6, 9}
9.
R = {(x,y) : x, y \(\in\) N, x + 2y = 8}
\(\therefore \) x + 2y = 8
When x=2, y=3
When x=4, y=2
When x=6, y=1
\(\Rightarrow \) R= {(2,3),(4,2),(6,1)}
\(\Rightarrow \)\({ R }^{ -1 }\)= {(3,2),(2,4),(1,6)}
10.
Given, R= {(1,2),(1,3),(2,3),(3,2),(5,6)}
\(\Rightarrow \) \({ R }^{ -1 }\) = {(2,1),(3,1),(3,2),(2,3),(6,5)}
11.
Here, first element of each ordered pair of A x B gives the elements of set A and corresponding second element gives the elements of set B
\(\therefore\) A = {a, b} and B = {l, 3, 2}
12.
\(\left( \frac { f }{ g } \right) (x)=\frac { f(x) }{ g(x) } =\frac { \left( \frac { 1 }{ x-2 } \right) }{ (x-2)^{ 2 } } ,x\neq 2\)
\(=\frac { 1 }{ (x-2)^{ 3 } } ,x\neq 2\)
13.
We have, A x A = {1,2} x {1,2}
= {(1,1),(1,2),(2,1),(2,2)}
Now, (A x A) x A = A x A x A = {(1,1),(1,2),(2,1),(2,2)} x {1,2}
={(1,1,1),(1,1,2),(1,2,1),(1,2,2),(2,1,1),(2,1,2),(2,2,1),(2,2,2)}
14.
Given, n(A) = 3 and B = {2,3,4,6,7,8} \(\Rightarrow\)n(B) = 6
\(\therefore \) Number of relations from A to B \(={ 2 }^{ n\left( A \right) \times n\left( B \right) }\)
\(={ 2 }^{ 3\times 6 }\ ={ 2 }^{ 18 }\)
15.
We have, A = {a,b} and B = {2,3},
\(\therefore \ n\left( A\times B \right) =n\left( A \right) \times n\left( B \right) =2\times 2=4\)
Now, number of subsets of A x B
\(={ 2 }^{ n\left( A\times B \right) }={ 2 }^{ 4 }=16\)
Thus, the number of relations from A to B is 16.
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