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CBSE 11th Standard Chemistry Subject Organic Chemistry: Some Basic Principles and Techniques Ncert Exemplar 2 Mark Questions 2021

Published on: 27/05/2021

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Std: 11th Standard CBSE - Chemistry

chapter: - NCERT Exemplers

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Questions:

Generic 2

4 x 2 = 8

For testing halogens in an organic compound with AgNO₃ solution sodium extract (Lassaigne's test) is acidified with dilute HNO₃. What will happen if a student acidifies the extract with dilute H₂SO₄ in place of diluate HNO₃?

Which of the following compounds will not exist as resonance hybrid. Give reason for your answer.
(a) CH₃OH
(b) CH₃CH = CHCH₂NH₂

Identify the most stable species in the following set of ions giving reasons
\(\overset { - }{ C } { H }_{ 3 },\overset { - }{ C } { H }_{ 2 }CI,\overset { - }{ C } { H }CI_{ 2 },\overset { - }{ C } CI_{ 3 }\)

Identify the most stable species in the following set of ions giving reasons
\(\overset { + }{ C } { H }_{ 3 },\overset { + }{ C } { H }_{ 2 }Br,\overset { + }{ C } { H }B{ r }_{ 2 },\overset { + }{ C } B{ r }_{ 3 }\)

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Answers Key:

Generic 2

4 x 2 = 8

On adding dilute H₂ SO₄ for testing halogens in an organic compound with AgNO₃ white precipate of Ag₂SO₄ Mmay be mistaken for white precipate of chlorine as AgCI.Hence dilute HNO₃ is used instead of dilute H₂SO₄.

(a) CH₃OH as it lacks \(\pi \) -electrons hence it will not exist as resonance hybrid.
(b) CH₃CH = CHCH₂NH₂ As the lone pair of electrons on the N-atom is not conjugated with the -electrons of the double bond, thus, resonance is not possible and hence no resonance hybrid will exist.

\(\overset { - }{ C } CI_{ 3 }\) is the most stable species because on replacing H by CI, negative charge on carbon is reduced and species is stabilized.

\(\overset { + }{ C } { H }_{ 3 }\) is the most stable species because the replacement of H by Br increases positive charge on carbon atom and destabilizes the species.