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Questions + Answers key
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1.
At 298 K, Kp for the reaction, N2O4(g) \(\leftrightharpoons \) 2NO2(g) is 0.98. Predict whether the reaction is spontaneous or not.
2.
Which quantity out of \(\Delta _{ r }G\) and \(\Delta _{ r }G^{ \circ }\) will be zero at equilibrium?
3.
The enthalpy of atomisation for the reaction,
\({ CH }_{ 4 }\left( g \right) \longrightarrow C\left( g \right) +4H\left( g \right) \)
is 1665 KJ mol-1. What is the bond energy of C-H bond ?
4.
Given that \(\Delta H\) = 0 for mixing of two gases. Explain whether the diffusion of these gases into each other in a closed container is a spontaneous process or not?
5.
Enthalpy of combustion of carbon to CO2 is –393.5 kJ mol–1. Calculate the heat released upon formation of 35.2 g of CO2 from carbon and dioxygen gas.
1.
ΔrG∘ = −2.303 RT logKp
Here Kp= 0.98, i.e. Kp < 1 therefore, ΔrG∘ is positive. Hence, the reaction is non-spontaneous.
2.
\(\Delta_r G=\Delta_r G^{\circ}+R T \ln K\)
At equilibrium,
\( 0=\Delta_r G^{\circ}+R T \ln K\left(\because \Delta_r G=0\right) \)
\( \text { or } \Delta_r G^{\circ}=-R T \ln K \)
\(\Delta_r G^{\circ}=0 \text { when } K=1\)
For all other values of \(\mathrm{K}, \Delta_r G^{\circ}\) will be non-zero.
3.
In CH4 there are four C-H bonds. The enthalpy of atomisation of 1 mole of CH4 means dissociation of four moles of C-H bond.
∴ C-H bond energy per mol \(=\frac{ 1665 KJ}{4 mol }\)= 416.25 KJ mol-1.
4.
It is a spontaneous process because although ΔH=0, i.e., energy factor has no role to play but randomness increases, i.e. randomness factor favours the process.
5.
The reaction for the combustion of carbon into CO2 is
C(s) + O2(g) ⟶ CO2(g); △H = -393.5 KJ mol-1
Heat released in the formation of 44 g CO2 = 393.5 KJ
∴∴ Heat released in the formation of 35.2 g CO2
\(=\frac{393 KJ × 35.2 g}{44 g} \)= 314.8 KJ
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