Selling price of each radio = Rs 5000
Let the cost price of each radio be Rs x.
10% profit on one radio
i.e.\({110\over 100}\times x=5000\)
\(x={5000\over 110}\times100={50000\over11}=Rs.4545.45\)
10% loss on other radio i,e, \( {90\over100}\times x =5000\)
\( x={5000\times100\over 90}={50000\over 9}=Rs5555.55\)
Total cost price = Rs 4545.45 + Rs 5555.55 = Rs 10101
Loss = Total cost price - Total selling price
=Rs 10101- Rs10000=Rs 101
[\(\because\) Total selling price = 2 x 5000 = 10000]
\(\therefore\)\(Loss \%={Loss\over cost \ price}\times 100\)
\(={101\over10101}\times 100={10100\over10101}=10\%\)
Hence, 10% loss in the whole transactions.

The ratio of present ages of A and B is 3 : 2.
Let 3x and 2x be the ages of A and B.
5 yr after, their ages ratio wi II be 14 :11.
\(\therefore {3x+5\over2x+5}={14\over11}\)
11(3x + 5) = 14 (2x + 5) \(\Rightarrow\) 33x + 55 = 28x + 70
33x - 28x = 70 - 55 - 5x = 15 \(\Rightarrow\) x = 3
Hence, present age of A = 3 x 3 = 9 yr
and present age of B = 3 x 2 = 6 yr

Total number of voters = 20000
Percentage of voters who vote = 60%
Percentage of voters who did not vote =100 - 60 = 40%
\(\therefore\) Number of voters who did not vote=\({40\over 100}\times 20000=40\times 200=8000\)
Hence, 8000 voters did not vote.

No profit, no loss

7%

2.5yr

(i) Total parts = 4 and coloured part = 1
\(\therefore\)Coloured parts of the figure in fraction =\({1\over4}\)
Now, required per cent of coloured parts
=\(({1\over4}\times100)\%=25\%\)
(ii) Total parts = 5 and coloured parts = 3
\(\therefore\)Coloured parts of the figure in fraction=\({3\over5}\)
Now, required per cent of coloured parts =\(({3\over5}\times100)\%\)
\(=(3\times20)\%=60\%\)
(iii) Total parts = 5 and coloured parts = 3
\(\therefore\)Coloured parts of the figure in fraction =\({3\over8}\)
Now, required per cent of coloured part = \(({3\over8}\times 100)\%\)
\(=({3\over2}\times25)\%=({75\over2})\%=37.5\%\)

The complete table is shown below:

Let the number of students = 100
Passed students = 12
Hence, failed students = 100 - 12 = 28
\(\because \) When failed are 28, then total no. of students
=100
 \(\because \)When failed are 392, then total no. of students
=\(\frac { 100 }{ 28 } \times \)392
=1400

(a) 9% of Rs.700= \(\frac { 9 }{ 100 } \times \)700
= 9 X 7
= Rs.63
(b) 6 \(\frac { 2 }{ 3 } \)% of 75m =\(\frac { 20 }{ 3 } \)% of 75 m
=\(\frac { 20 }{ 300 } \times \)75 m
=\(\frac { 1 }{ 15 } \times \)75 m
=5 m
(c) 7.5 % of 80 kg =\(\frac { 7.5 }{ 100 } \times \)80 kg
=\(\frac { 3 }{ 40 } \times \)80 = 6 kg
(d) 8% of 5 liters =\(\frac { 8 }{ 100 } \times \)5 litres
=\(\frac { 40 }{ 100 } \times \)0.4 litre.