We have \(65\%=65\times{1\over100}={65\over100}\)
\(={13\over20}\)
Thus, \(65\%={13\over20}\)

Cost of bowl =Rs.90
Cost of 1 bowl = Rs. \(\frac { 90 }{ 6 } \)
Hence, cost of 10 bowls = Rs.\(\frac { 90 }{ 6 } \times 10\)
= Rs.150.

Let the principal P = Rs.x, R =?, T = 10 years, A = 3 times of P = Rs.3x, 51 = A - P = 3x - x = Rs. 2x
Now, we know that \(R={S\times 100\over P \times T}={2 \times 10 \over x \times 10}=20\%\)
Thus, at 20% per annum, a sum of money will triple itself in 10 years.

Given, Principal, P = Rs 10000; Rate of interest, R = 5%
Time, T= 1yr
\(\therefore Interest , I = {P\times R\times T\over 100}={10000\times 5\times 1\over100}=100\times 5=Rs500\)
Hence, the interest at the end of 1 yr is Rs 500.

45.6kg

80cm

16

I will be able to carry 50 times of my weight.

Rs 24500

Given, Principal, P = Rs 56000, Interest, I = Rs 280,
Time,T=2yr
Let rate of interest be R % p. a.
Now, 
\(I={P\times R\times T\over 100}\)
\( \\ \Rightarrow R=({I\times 100\over P\times T}) \%=({280\times100\over 56000\times 2})\%=({28\over 56\times 2})\)
\( ={1\over4}\%=0.25\%\)
Hence, the rate of interest is 0.25%.nj

Given, CP (cost price) of a chair = Rs 375
SP (selling price) of a chair = Rs 400
Here, SP> CP. So, gain = SP - CP = Rs (400 - 375)= Rs 25
Now, gain percentage=\(({Gain \over CP \ of \ a \ chair }\times 100)\%\)
\(=({25\over375}\times 100)\%={100\over15}\%={20\over3}\%=6{2\over3}\%\)
Hence, the gain percentage is \(6{2\over3}\%\)

 (i) It is clear from the figure that, shaded triangular parts are 3 out of 4.
Shaded triangular parts in fraction \(={3\over4}\)
\(\therefore\)Percentage of shaded part \( = ({3\over4}\times 100)\%=75\%\)
Hence, 75% of the figure is shaded.
(ii)From the figure,
fraction of tangram which is not shaded
\(={1\over16}+{1\over16}+{1\over8}+{1\over 4}={1+1+2+4\over16}={8\over16}={1\over2}\)
i.e. half of the tangram is shaded.
\(\therefore\)Percentage of tangram which is shaded|
\(=({1\over2}\times100)\%=50\%\)
Hence, 50% of the tangram is shaded.

Putting the data in the tabular form, we get

Given, population of Rajasthan = 570 lakhs
Population of UP = 1660 lakhs
Area of Rajasthan = 3 lakh km ², Area of UP = 2 lakh km ²
(i) For Rajasthan,
​​​​​​Number of people per km² \(={Population \ of \ Rajasthan \over Area \ of \ Rajasthan} \)
\(={570\over3}=190\)
Hence, the number of people in Rajasthan is
190 per km ².
For Up,
Number of people per km ²
\(={Population \ of \ UP \over Area \ of \ UP}\)
\( ={1660\over2}=830\)
Hence, the number of people in UP is 830 per km ².
(ii) It is clear from part (i) that Rajasthan is less populated

2.5yr

(i) Total parts = 4 and coloured part = 1
\(\therefore\)Coloured parts of the figure in fraction =\({1\over4}\)
Now, required per cent of coloured parts
=\(({1\over4}\times100)\%=25\%\)
(ii) Total parts = 5 and coloured parts = 3
\(\therefore\)Coloured parts of the figure in fraction=\({3\over5}\)
Now, required per cent of coloured parts =\(({3\over5}\times100)\%\)
\(=(3\times20)\%=60\%\)
(iii) Total parts = 5 and coloured parts = 3
\(\therefore\)Coloured parts of the figure in fraction =\({3\over8}\)
Now, required per cent of coloured part = \(({3\over8}\times 100)\%\)
\(=({3\over2}\times25)\%=({75\over2})\%=37.5\%\)