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Published on: 31/10/2025
Download CBSE Class 7th Standard CBSE Mathematics question papers, sample papers, important questions, and previous year solved papers in PDF format. Get free study materials, NCERT solutions, and exam preparation resources for Class 7th Standard CBSE Mathematics
Questions + Answers key
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1.
Simplify the following: 73 x 23
2.
Express the following numbers as a power of - 3: 729
3.
Simplify (-2)3 x (-10)3
4.
Express each of the following as product of powers of their prime factors. 648
5.
Express the following in exponential form: 2 x 2 x a x a
6.
Standard form corresponding to the number 654300100 is
6.543001 X107
6.543001 x108
6.543 x108
6.543001 x 109
7.
The number corresponding to expanded form, 6 x 108 + 3 x 107 + 4 x 105 + 3 x 102 + 1x 100 is
63040301
63040031
630400301
63400301
8.
If (3102 x 3101) ÷ 3101= k- 3100, then the value of k
9
10
11
12
9.
(- 4)4 x (-2)0 x (-1)202 is equal to
64
1
0
256
10.
For any two non-zero rational numbers x and y, x5 ÷ y5 is equal to.
(x ÷ y)1
(x ÷ y)0
(x ÷ y)5
(x ÷ y)10
11.
10000 _____ 105
12.
74 _____ 54
13.
< ,> or = sign. 63 ....... 44
14.
27500000 = 2.75 x 10...
15.
340900000 = 3.409 x 10.....
16.
9001006001 =9 x 109 + 1 x 106 + 6 x 103 +1 x 100
17.
5x105+ 3 x103+2 x1 0= 50302
18.
a5 x a4 x a-3 x a-2 = a4
19.
37\(\div\)3-3=34
20.
5° x 25° x 125° = (5°)6
21.
Write the number 6.234269 x 106 in the usual form.
22.
Simplify: \({ \left( \frac { 3 }{ 4 } \right) }^{ 4 }\div { \left( \frac { 6 }{ 8 } \right) }^{ 2 }\times \left( \frac { 1 }{ 2 } \right) \)
23.
Write the difference between 83 and 73
24.
If 2n+2 - 2n+1 +2n = c x 2n, then find the value of c.
25.
If 21998- 21997- 21996+ 21995= k.21995, then the value of k is?
26.
By what number should we multiply (-8)-1 to obtain a product equal to 10-1?
27.
A light year is a distance that light can travel in one year.
1 light year = 9,460,000,000,000 km
(a) Express one light year in scientific notation.
(b) The average distance between Earth and Sun is 1.496 x 108 km. Is the distance between Earth and the Sun greater than, less than or equal to one light year?

1.
2744
2.
(-3)6
3.
We have, (-2)3 x (-10)3
= (-2) x (-2) x (-2) x (-10) x (-10) x (-10)
= (-8) x (-1000) = 8000 [ \(\because\)(-1) odd number =-1]
Hence, the value of (-2)3 x (-10)3 is 8000.
4.
We have, 648

= 2 x324 = 2 x 2 x162
= 2 x 2 x 2 x81 = 2 x 2 x 2 x3 x 27
=2x2x2x3x3x9
= 2 x 2 x 2 x3 x3 x3 x3 = 23 x34
Hence, the number 648 can be expressed as 23 x34 ,
which is the required form.
5.
2 x 2 x a x a =22 x a2 [since, 2 is multiplied 2 times and a is multiplied 2 times]
6.
(c)
6.543 x108
7.
(c)
630400301
8.
(c)
11
9.
(d)
256
10.
(c)
(x ÷ y)5
11.
( )
10000 < 105
12.
( )
74 > 54
13.
( )
63 < 44
14.
( )
107
15.
( )
108
16.
(a)
17.
(b)
18.
(a)
19.
(b)
20.
(a)
21.
6234269
22.
\(\frac { 9 }{ 32 } \)
23.
169
24.
Given, 2n+2- 2n = c x 2n
⇒ 2n+2 = 2n x 22, 2n+1 = 2n x 21
So, 2n x 22 - 2n x 21 + 2n = c x 2n
Taking ~ common from both the side, we get
2n (22-21)= c x 2n
⇒ (22-21+1)c
∴ c = 4-2+1 [∵ 22= 2 x 2=4, 21=2]
=2 +1 =3
25.
Given, 21998- 21997- 21996+ 21995= k.21995
\(\Rightarrow\)21995+3 - 21995+ 2 - 21995+ 1+ 21995 x1 = k.21995
\(\Rightarrow\)21995 [23 - 22 - 21 + 1] = k. 21995
\(\Rightarrow\)21995 [8 - 4 - 2 + 1] = k. 21995
\(\Rightarrow\)3=\(\frac { k.{ 2 }^{ 1995 } }{ { 2 }^{ 1995 } }\) \(\Rightarrow\) 3 = k
So, the value of k is 3.
26.
\(-\frac { 4 }{ 5 } \)
27.
(a) 1 light year = 9.460,000,000,000 km
= 946 x 1010km = \(\frac { 946 }{ 100 } \)x 1010 X 100 km
= 9,46 x 1012km.
(b) Average distance between Earth and Sun =1.496 x108 km
\(\therefore\) Distance between Earth and Sun = \(\frac { 1.496 }{ 10000 } \times { 10 }^{ 8 }\times { 10 }^{ 4 }\)km
= 0,0001496 x 1012km
\(\Rightarrow\)9.46 > 0.0001496
So, the distance between Earth and Sun less than one light year.
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