Given, length of the door = 2 m and breadth of a door = 1m
Since door is in the shape of a rectangle
\(\therefore\)  Area of the door = Length x Breadth = 2 x 1= 2 m
Also, length of the wall = 4.5 m and breadth of the wall = 3.6 m
\(\therefore\)  Area of the wall including door = Length x Breadth = 4.5 x 3.6 = 16.2 m²
Now, area of the wall for whitewash = Area of the wall including door - Area of the door = 16.2 - 2 = 14.2 m²
\(\therefore\) Cost of whitewashing the wall at the rate of Rs 20 per m²
                                 = Rs (14.2 x 20) = Rs 284
Hence, the cost of whitewashing the wall is Rs 284.

Given, length of a rectangular shape = 40 cm and breadth of a rectangular shape = 22 cm²
\(\therefore\) Length of wire = Perimeter of a rectangular shape
                        = 2 (l + b) = 2 (40 + 22) = 2 x 62 = 124 cm
Since, this wire is rebent in the shape of square.
\(\therefore\) Perimeter of the square = Length of wire  \(\Rightarrow\)   4 x Side = 124
On dividing both sides by 4, we get, Side = \(\frac{124}{4}=31cm\)
Hence, the side of a square shape is 31 cm.
\(\therefore\) Area of a rectangular shape = L x b = 40 x 22 = 880 cm² and area of square shape = (Side)² = (31)² = 961 cm²
Hence, area of square shape is more than the area of rectangular shape.

Let b be the breadth of the rectangular park.
Given, side of a square park, a = 60 m and length of the rectangular park, I = 90 m
Now, area of a square park = (Side)² = (60)² = 3600 m²
According to the question,
Area of a rectangular park = Area of a square park
\(\Rightarrow\)  I x b = 3600 [\(\therefore\) area of a rectangular park = I x b]
\(\Rightarrow\) 90 x b = 3600  \(\Rightarrow\) b = \(\frac{3600}{90}\Rightarrow\) b = 40 m
Hence, the breadth of a rectangular park is 40 m.

Given, perimeter of a rectangular sheet = 100 cm and length of a rectangular sheet, I = 35 cm
Let b be the breadth of a rectangular sheet .
We know that, perimeter of a rectangular sheet = 2 (/ + b)
\(\Rightarrow\)  2(/ + b) = 100  \(\Rightarrow\) 2(35 + b) = 100
\(\Rightarrow\) \(35+b=\frac{100}{2}\)    [dividing by 2 on both sides]
\(\Rightarrow\) 35 + b = 50  \(\Rightarrow\) b = 50 - 35  \(\Rightarrow\) b = 15 cm
\(\therefore\) Area of a rectangular sheet = I X b = 35 x 15 = 525 cm²
Hence, the breadth and area of a rectangular sheet are 15 cm and 525 cm², respectively.

Let b be the breadth of a rectangular plot of land.
Given, length of a rectangular plot of land, I = 22 m and area of a rectangular plot of land = 440 m²
We know that area of a rectangular plot of land = I x b
\(\Rightarrow\) 440 = 22 X b  \(\Rightarrow\)  22b = 440  \(\Rightarrow\)  b = \(\frac{440}{22}\) = 20 m
\(\therefore\) Perimeter of a rectangular plot of land = 2(/ + b)
                                                           = 2(22 + 20) = 2 x 42 = 84 m
Hence, the breadth and perimeter of a rectangular plot of land are 20 m and 84 m, respectively.

15⁵

4¹⁰

2⁸

5.2x10¹⁸>2.5x10¹⁸