CBSE 7th Standard Mathematics Rational Numbers Important Questions And Answers Study Material - QB365 Set D | QB365

7th Standard CBSE Syllabus & Materials

7th Standard CBSE

CBSE 7th Social Science Theme E - Understanding Market - New Sample Question Papers Study Material - QB365 Set A

7th Standard CBSE

CBSE 7th Social Science Theme E - From Barter to Money - New Sample Question Papers Study Material - QB365 Set A

7th Standard CBSE

CBSE 7th Social Science Theme D - The Constitution of India- An Introduction - New Sample Question Papers Study Material - QB365 Set A

NEW

7th Standard CBSE

CBSE 7th Social Science Theme D - From the Rulers to the Ruled : Types of Governments - New Sample Question Papers Study Material - QB365 Set A

NEW

7th Standard CBSE

CBSE 7th Social Science Theme B - The Age of Reorganisation - New Sample Question Papers Study Material - QB365 Set A

NEW

7th Standard CBSE

CBSE 7th Social Science Theme B - The Rise of Empires - New Sample Question Papers Study Material - QB365 Set A

CBSE 7th Standard Mathematics Rational Numbers Important Questions And Answers Study Material - QB365 Set D

Published on: 31/10/2025

Question Set D

CBSE 7th Standard Mathematics Rational Numbers Important Questions And Answers Study Material - QB365

Download CBSE Class 7th Standard CBSE Mathematics question papers, sample papers, important questions, and previous year solved papers in PDF format. Get free study materials, NCERT solutions, and exam preparation resources for Class 7th Standard CBSE Mathematics

Questions + Answers key

Take MCQ Mathematics Test

QB365 Student Learing Managemnet System

Std: 7th Standard CBSE - Mathematics

chapter: Rational Numbers - Important Questions And Answers

Visit QB365-SLMS - https://www.qb365.in/slms/ Complete Questions and Answers

Questions:

Generic 2

5 x 2 = 10

Simplify and express the result in standard from \(\left( -\frac { 2 }{ 5 } +\frac { 1 }{ 2 } \right) +\left( \frac { 1 }{ 3 } -\frac { 5 }{ 2 } \right) \)

Multiply the sum of \(\frac { 1 }{ 8 } \) and \(\frac { 2 }{ 3 } \) by the additive inverse \(\frac { -5 }{ 7 } \)

Product of two rational numbers is 3.If one of them is \(\frac { 5 }{ 8 } \) then find other

By what number should we multiply -\(\frac { 2 }{ 5 } \) to get \(\frac { 3 }{ 5 } \) ?

Find the value of \(12\frac { 6 }{ 9 }\div \frac { 1 }{ 18 } \times \frac { 1 }{ 2 } \)

Generic 3

5 x 3 = 15

Given rational numbers are \(\frac { -4 }{ 5 } \) and \(\frac { -2 }{ 3 } \)

Write 3 rational numbers between \(\frac { 1 }{ 2 } \) and \(\frac { 1 }{ 3 } \)

Divide the reciprocal of \(\frac { 1 }{ 3 } \) by the additive inverse of -5 to get a rational number.

Add reciprocal of \(\frac { 2 }{ -9 } \) to the additive inverse \(\frac { -3 }{ 8 } \)

10.

Average \(\frac { 1 }{ 5 } ,\frac { 2 }{ 8 } ,\frac { 3 }{ 4 } \) in ascending order.

Multiple Choice Question

5 x 1 = 5

11.

The product of \(2\frac { 6 }{ 8 } \) and \(4\frac { 1 }{ 4 } \)

(a)

\(11\frac { 11 }{ 16 } \)

(b)

\(\frac { 29 }{ 31 } \)

(c)

\(\frac { 34 }{ 57 } \)

(d)

\(\frac { 86 }{ 97 } \)

12.

The subtraction \(6\frac { 4 }{ 5 } \)from \(\frac { 50 }{ 5 } \)

(a)

\(3\frac { 1 }{ 5 } \)

(b)

\(2\frac { 1 }{ 5 } \)

(c)

\(\frac { 31 }{ 95 } \)

(d)

\(\frac { 39 }{ 95 } \)

13.

How many rational numbers are there between two rational numbers?

(a)

(b)

(c)

unlimited

(d)

100

14.

Which of the following is equivalent to \(\frac { 4 }{ 5 } \)

(a)

\(\frac { 5 }{ 4 } \)

(b)

\(\frac { 16 }{ 25 } \)

(c)

\(\frac { 16 }{ 20 } \)

(d)

\(\frac { 15 }{ 25 } \)

15.

Which pair shows equivalent rational numbers?

(a)

\(\frac { 3 }{ 4 } ,\frac { 6 }{ 8 } \)

(b)

\(\frac { 5 }{ 6 } ,\frac { 5 }{ 12 } \)

(c)

\(\frac { 3 }{ 2 } ,\frac { 3 }{ 4 } \)

(d)

None of these

Fill up / 1 Marks

5 x 1 = 5

16.

\(\)\(\frac { -6 }{ 7 } =\frac { \_ \_ \_ \_ }{ 42 } \)

17.

\(\frac { -5 }{ 3 } \times \left( \frac { -3 }{ 5 } \right) =\) __________

18.

\(\frac { 3 }{ 4 } \times \left( \frac { -2 }{ 3 } \right) =\) ___________

19.

\(\frac { -5 }{ 6 } +\frac { -1 }{ 6 }\)=_________

20.

\(\frac { -3 }{ 5 } +\frac { 2 }{ 5 } =\) ______________

True or False

5 x 1 = 5

21.

if \(\frac { p }{ q } \) is rational number and m is a non zero common divisor of p and q ,then \(\frac { p }{ q } \) = \(\frac { p\div m }{ q\div m } \)

(a)

False

(b)

True

22.

The rational number \(\frac { -3 }{ 4 } \) lies to the right of zero on the number line.

(a)

True

(b)

False

23.

if \(\frac { p }{ q } \) is rational number and m is non zero integer, then \(\frac { p\times m }{ q\times m } \) is a rational number not equivalent to \(\frac { p }{ q } \) .

(a)

True

(b)

False

24.

if \(\frac { -6 }{ 7 } =\frac { x }{ 28 } ,\) then the value of x is \(\frac { -3 }{ 2 } \)

(a)

True

(b)

False

25.

\(9\frac { 3 }{ 4 } \div \frac { 4 }{ 8 } \times \frac { 1 }{ 2 } =\frac { 6 }{ 5 } \)

(a)

True

(b)

False

Generic 5

2 x 5 = 10

26.

Simplify
\(\\ 1\div \left( -\frac { 1 }{ 2 } \right) \)

27.

Simplify
\(\frac { 13 }{ 11 } \times \frac { -14 }{ 5 } +\frac { 13 }{ 11 } \times \frac { -7 }{ 5 } +\frac { -13 }{ 11 } \times \frac { 34 }{ 5 } \)

Visit QB365-SLMS - https://www.qb365.in/slms/

Answers Key:

Generic 2

5 x 2 = 10

\(\frac { -3 }{ 65 } \)

\(\frac { 95 }{ 168 } \)

\(\frac { 24 }{ 5 } \)

-\(\frac { 3 }{ 4 } \)

114

Generic 3

5 x 3 = 15

For common denominators, LCM of 5 and 3 is 15.
\(\frac { -4\times 3 }{ 5\times 3 } =\frac { -12 }{ 15 } \) and \(\frac { -2\times 5 }{ 3\times 5 } \frac { -10 }{ 15 } \)
\(\frac { -12\times 2 }{ 15\times 2 } =\frac { -24 }{ 30 } \) and \(\frac { -10\times 2 }{ 15\times 2 } =\frac { -20 }{ 30 } \)
so,\(\\ \frac { -24 }{ 30 } <\frac { -23 }{ 30 } <\frac { -22 }{ 30 } <\frac { -21 }{ 30 } <\frac { -20 }{ 30 } \)
Hence rational numbers between \(\frac { -4 }{ 5 } \) and \(\frac { -2 }{ 3 } \)
are \(\frac { -23 }{ 30 } <\frac { -22 }{ 30 } <\frac { -21 }{ 30 }\)

Given rational numbers are \(\frac { 1 }{ 2 } \) and \(\frac { 1 }{ 3 } \).
For common denominator, LCM of 2and 3 is 6,
\(\frac { 1\times 3 }{ 2\times 3 } \frac { 3 }{ 6 } \) and \(\frac { 1\times 2 }{ 3\times 2 } =\frac { 2 }{ 6 } \)
Now,\(\frac { 3\times 10 }{ 6\times 10 } =\frac { 30 }{ 60 } \) and \(\frac { 2\times 10 }{ 6\times 10 } =\frac { 20 }{ 60 } \)
so, \(\frac { 20 }{ 60 } <\frac { 21 }{ 60 } <\frac { 22 }{ 60 } <\frac { 23 }{ 60 } <.......<\frac { 30 }{ 60 } \)
Hence, 3 rational numbers between \(\frac { 1 }{ 2 } \) and \(\frac { 1 }{ 3 } \) are
\(\frac { 21 }{ 60 } <\frac { 22 }{ 60 } <\frac { 23 }{ 60 }\)

\(\frac { 3 }{ 5 } \)

\(\frac { -39 }{ 10 } \)

10.

\(\frac { 1 }{ 5 } <\frac { 2 }{ 8 } <\frac { 3 }{ 4 } \)

Multiple Choice Question

5 x 1 = 5

11.

(a)
\(11\frac { 11 }{ 16 } \)

12.

(a)
\(3\frac { 1 }{ 5 } \)

13.

14.

15.

(a)
\(\frac { 3 }{ 4 } ,\frac { 6 }{ 8 } \)

Fill up / 1 Marks

5 x 1 = 5

16.

\(\frac { -6 }{ 7 } =\frac { x }{ 42 } \Rightarrow x=\frac { 42\times (-6) }{ 7 } =6\times (-6)=-36\)

17.

\(\frac { -5 }{ 3 } \times \left( \frac { -3 }{ 5 } \right) =\frac { 15 }{ 15 } =1\)

18.

\(\frac { 3 }{ 4 } \times \left( \frac { -2 }{ 3 } \right) =\frac { 3\times (-2) }{ 4\times (3) } =\frac { -6 }{ 12 } =\)\(-\frac { 1 }{ 2 } \)

19.

\(\frac { -5 }{ 6 } +\frac { -1 }{ 6 } =\frac { -5-1 }{ 6 } =\frac { -6 }{ 6 } =\)-1

20.

\(\frac { -3 }{ 5 } +\frac { 2 }{ 5 } =\frac { -3+2 }{ 5 } =\)\(\frac { -1 }{ 5 } \)

True or False

5 x 1 = 5

21.

(a)
False

22.

(b)
False

23.

(b)
False

24.

(b)
False

25.

(b)
False

Generic 5

2 x 5 = 10

26.

\(\\ 1\div \left( -\frac { 1 }{ 2 } \right) \)
The reciprocal of \(\left( \frac { -1 }{ 2 } \right) \) is \(\frac { 2 }{ -1\\ } \)
So,\(\\ \frac { 1 }{ 1 } \times \frac { 2 }{ -1 } =\frac { 1\times 2 }{ 1\times (-1) } =\frac { 2 }{ -1 } =-2\)

27.

Given,
\(\frac { 13 }{ 11 } \times \frac { -14 }{ 5 } +\frac { 13 }{ 11 } \times \frac { -7 }{ 5 } +\frac { -13 }{ 11 } \times \frac { 34 }{ 5 } \)
\(\\ \therefore \) Product of rational numbers
\(=\frac { Product\quad of\quad rational\quad numbers\quad }{ Product\quad of\quad denominaters } \)
\(=\frac { 13\times (-14) }{ 11\times 5 } +\frac { 13\times (-7) }{ 11\times 5 } +\frac { (-13)\times (34) }{ 11\times 5 } \\ =\frac { (-182) }{ 55 } +\frac { (-91) }{ 55 } +\frac { (-442) }{ 55 } \\ =\frac { -715 }{ 55 } =\frac { -143 }{ 11 } =\frac { -13 }{ 1 } =-13\)