7th Standard CBSE Syllabus & Materials
7th Standard CBSE
CBSE 7th Social Science Theme E - Understanding Market - New Sample Question Papers Study Material - QB365 Set A
NEW7th Standard CBSE
CBSE 7th Social Science Theme E - From Barter to Money - New Sample Question Papers Study Material - QB365 Set A
NEW7th Standard CBSE
CBSE 7th Social Science Theme D - The Constitution of India- An Introduction - New Sample Question Papers Study Material - QB365 Set A
NEW7th Standard CBSE
CBSE 7th Social Science Theme D - From the Rulers to the Ruled : Types of Governments - New Sample Question Papers Study Material - QB365 Set A
NEW7th Standard CBSE
CBSE 7th Social Science Theme B - The Age of Reorganisation - New Sample Question Papers Study Material - QB365 Set A
NEW7th Standard CBSE
CBSE 7th Social Science Theme B - The Rise of Empires - New Sample Question Papers Study Material - QB365 Set A
Published on: 31/10/2025
Download CBSE Class 7th Standard CBSE Mathematics question papers, sample papers, important questions, and previous year solved papers in PDF format. Get free study materials, NCERT solutions, and exam preparation resources for Class 7th Standard CBSE Mathematics
Questions + Answers key
Take MCQ Mathematics Test
1.
Find x, if: 3x - 5 =7
2.
Find x, if: \(\frac { x }{ 2 } +5=10\)
3.
Convert the following equation in statement form 4p=21
4.
Convert the following equation in statement form x+5 =6
5.
Solve for x: \(\frac { 2x-1 }{ 3 } -\frac { 6x-2 }{ 5 } =\frac { 1 }{ 3 } \)
6.
Solve the following equation 16 = 4 + 3(t + 2).
7.
Solve the following equation 4 = 5(p - 2).
8.
If one side of a square is represented by 5 - 4x and the adjacent side is represented by 3x - 2, find the length of the side of the square.
9.
Which of the following numbers satisfy the equation - 6 + x = - 12 ?
2
6
-6
-2
10.
If \(\frac { x }{ 2 } =3\), then the value of 3x + 2 is
20
11
\(\frac { 13 }{ 2 } \)
8
11.
The equation which cannot be solved in integers is
5y - 3 = -18
3x - 9 = 0
3z + 8 = 3 + z
9y + 8 = 4y-7
12.
The sum of the ages of three persons is 50 years. What will be the sum of their ages after 5 years ?
65
55
150
21
13.
The sum of three times a number and 11 is 32. Find the number?
6
7
10
21
14.
Which of the following is the value of 'm' in the equation 3m - 14 = 4
4
5
6
7
15.
Which of the following numbers satisfies the equation -6 + x = -18?
10
-13
-12
-16
16.
The equation having 5 as a solution is
4x + 1= 2
3 - x = 8
x - 5 = 3
3 + x = 8
17.
If k + 7 = 16, then the value of 8k - 72 is equal to
0
1
112
56
18.
The solution of the equation mx + n = 0 is
\(\frac{-n}{m}\)
\(\frac{n}{m}\)
\(\frac{2n}{m}\)
\(\frac{m}{n}\)
19.
In natural number, x - 5 = - 5 has _____________ solution.
20.
If z + 3 = 5, then z = ____________
21.
x - ________ = 15, when \(\frac{x}{2}=6\)
22.
x - 0 = ________, when 3x = 12.
23.
x + 7 = 16 has solution _________.
24.
One third of a number added to itself gives 10, can be represented as \(\frac { x }{ 3 } \) + 10 = x.
25.
\(\frac { 9 }{ 5 } \) is the solution of the equation 4x - 1 = 8.
26.
5 is the solution of the equation 3x + 2 = 17.
27.
One-third of a number when added to itself, gives 10, then it can be represented as \(\frac{x}{3}+10=x\)
28.
If 2(k + 1) = 19, then the value of 6k - 3 is 32.
29.
The root of 5x + 2 = 12
30.
One-fourth the sum of a number and 5 is 10
31.
The product of 20 and half of a number added to 30 is 50.
32.
The root of \(\frac{3x}{4}+1=3\)
33.
The root of 6x+ 2 = 14.
34.
Divide 184 into two parts such that one third of one part may exceed one seventh of other part by 8.
35.
If 18x = 72, then what is 10x?
36.
What do we call the process of taking a term of an equation from one side to the other with a change in its sign?
1.
3x-5 = 7
\(\Rightarrow\) 3x = 7 + 5
[On transposing 5 to RHS]
\(\Rightarrow\) 3x = 12
\(\frac { 3x }{ 3 } =\frac { 12 }{ 3 } \) [Dividing by 3]
\(\Rightarrow\) x = 4
2.
Since,
\(\frac { x }{ 2 } +5=10\)
\(\Rightarrow \quad \frac { x }{ 2 } =10-5\)
[On transposing 5 to RHS]
\(\Rightarrow \quad \frac { x }{ 2 } =5\)
\(\frac { x }{ 2 } \times 2=5\times 2\)
Multiplying both sides by 2
\(\Rightarrow\) x = 10
3.
4P = 21, Four times a number P is 21.
4.
x + 5 = 6, Add x and 5 to get 6.
5.
Since,
\(\frac { 2x-1 }{ 3 } -\frac { 6x-2 }{ 5 } =\frac { 1 }{ 3 } \)
\(\therefore \quad \frac { 5(2x-1) }{ 3\times 5 } -\frac { 3(6x-2) }{ 3\times 5 } =\frac { 1 }{ 3 } \)
\(\Rightarrow \quad \frac { 10x-5 }{ 15 } -\frac { (18x-6) }{ 15 } =\frac { 1 }{ 3 } \)
\(\Rightarrow \quad \frac { 10x-5-18x-6 }{ 15 } =\frac { 1 }{ 3 } \)
\(\Rightarrow \quad \frac { -18x+1 }{ 15 } =\frac { 1 }{ 3 } \)
\(\Rightarrow \) -18x+1=\(\frac { 15 }{ 3 } =5\)
\(\Rightarrow\) -18x = 5 - 1 = 4
\(\Rightarrow \quad x=\frac { 4 }{ -18 } \)
Thus, x=\(\frac { -2 }{ 9 } \)
6.
We have, 16 = 4 +3{t + 2)
Given equation can be written as
4 + 3 (t + 2) = 16
On transposing (+4) from LHS to RHS, we get
3(t + 2) = 16 - 4 \(\Rightarrow\) 3(t + 2) = 12
On dividing both sides by 3, we get
\(\frac{3(t+2)}{3}=\frac{12}{3}\quad \Rightarrow\) t + 2 = 4
Again, transposing (+2) from LHS to RHS, we get
t = 4 - 2 \(\Rightarrow\) t = 2
Hence, t = 2 is a solution of the given equation.
7.
We have, 4 = 5(p - 2)
We know that an equation remains same when the expression on the LHS and on the RHS are interchanged. So, the given equation can be written as 5{p- 2) = 4
On dividing both sides by 5, we get
\(\frac{5(p-2)}{5}=\frac{4}{5}\quad \Rightarrow\quad p-2=\frac{4}{5}\)
On transposing (-2) from LHS to RHS, we get
\(p=\frac{4}{5}+2\quad \Rightarrow \quad p=\frac{4}{5}+\frac{2}{1}\)
\(\Rightarrow \quad p=\frac{4+10}{5}=\frac{14}{5}\) [LCM of 5 and 1 = 5]
Hence, \(p=\frac{14}{5}\) is a solution of the given equation.
8.
1
9.
(c)
-6
10.
(a)
20
11.
(c)
3z + 8 = 3 + z
12.
(a)
65
13.
(b)
7
14.
(c)
6
15.
(c)
-12
16.
(d)
3 + x = 8
17.
(a)
0
18.
(a)
\(\frac{-n}{m}\)
19.
( )
No
20.
( )
2
21.
Given \(\frac{x}{2}=6 \Rightarrow\) = x = 6 x 2 = 12
\(\therefore\) 12 - (-3) = 12 + 3 = 15
So, x - (-3) = 15, When \(\frac{x}{2}=6\)
22.
If 3x = 12 \(\Rightarrow x=\frac{12}{3}=4\)
x - 0 = 4, when 3x = 12.
23.
Given, x + 7 = 16 \(\Rightarrow\) x = 16 - 7 = 9
So, x + 7 = 16 has solution 9.
24.
(b)
25.
(b)
26.
(a)
27.
(b)
28.
(b)
29.
( )
x = 2
30.
( )
\(\frac{1}{4}\)(x + 5) = 10
31.
( )
\(\frac{1}{2}\)x \(\times\) 20 + 30 = 50
32.
( )
\(x=\frac{8}{3}\)
33.
( )
x = 2.
34.
Let one part of 184 be x.
\(\therefore\) Other part be (184 - x)
Now, according to question,
\(\Rightarrow \quad \frac { 1 }{ 3 } x-\frac { 1 }{ 7 } (184-x)=8\)
\(\Rightarrow \quad \frac { x }{ 3 } +\frac { x }{ 7 } -\frac { 184 }{ 7 } =8\)
\(\Rightarrow \quad \frac { 7x+3x }{ 21 } =8+\frac { 184 }{ 7 } \)
\(\Rightarrow \quad \frac { 10x }{ 21 } =\frac { 56+184 }{ 7 } \)
\(\Rightarrow \quad \frac { 10x }{ 21 } =\frac { 240 }{ 7 } \)
\(\Rightarrow \quad x=\frac { 21\times 240 }{ 7\times 10 } \)
= 72
Hence, parts are 72 and 184 - 72 = 112.
35.
( )
40
36.
( )
Transposition
7th Standard CBSE Syllabus & Materials
7th Standard CBSE
CBSE 7th Social Science Theme B - New Beginnings : Cities and States - New Sample Question Papers Study Material - QB365 Set A
NEW7th Standard CBSE
CBSE 7th Social Science Theme A - Climates of India - New Sample Question Papers Study Material - QB365 Set A
NEW7th Standard CBSE
CBSE 7th Social Science Theme A - Geographical Diversity of India - New Sample Question Papers Study Material - QB365 Set A
NEW7th Standard CBSE
CBSE 7th Science Earth, Moon and the Sun - New Sample Question Papers Study Material - QB365 Set A
NCERT Books
Syllabus
Exam Pattern
Sample Question Papers
Previous year Question Papers
Important Notes
MCQ Practice test
NCERT Exemplers
Case study Questions
Image Based Questions
Passage based Questions
HOT Questions
Value Based Questions
Model Questions Papers
NCERT ( Book Back ) Questions
Assertion and Reason
Important Questions And Answers
CBSE 7th Standard CBSE Subjects
CBSE Standards
