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Published on: 01/10/2019
Simple Equations
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1.
Each of the 2 equal sides of an isosceles triangle is twice as large as the third side. If the perimeter of the triangle is 30 em, find the length of each side of the triangle.
2.
The length of a rectangle is two times its width. The perimeter of the rectangle is 180 cm. Find the dimensions of the rectangle.
3.
In a class of 60 students, the number of girls is one-third the number of boys. Find the number of girls and boys in the class.
4.
If 45 is added to half a number, then result is triple the number. Find the number.
5.
In a school, the number of girls is 50 more than the number of boys. The total number of students is 1070. Find the number of girls.
6.
The age of Sohan Lal is four times that of his son Amit. If the difference of their ages is 27 yr, find the age of Amit.
7.
What will be the value of y for which expressions (y -15) and (2y + 1) becomes equal?
8.
If \(\frac{3x-2y}{x-5y}=\frac{2}{3}\) find the value of \(\frac{x}{y}\)
9.
Follow the directions and correct the given incorrect equation written in Roman numerals: Remove two of these matchsticks to make a valid equation: IX - VI = V.
10.
If one side of a square is represented by 5 - 4x and the adjacent side is represented by 3x - 2, find the length of the side of the square.
1.
Let third side of an isosceles triangle be x.
Then two other equal sides are twice.
So, the both equal sides are 2x and 2x.
Here, perimeter = 30 cm as perimeter is addition of lengths of all sides.
So, x + 2x + 2x = 30 \(\Rightarrow\) 5x = 30
On dividing both sides by 5, we get
\(\frac{5x}{5}=\frac{30}{5}\Rightarrow\) x = 6cm
\(\therefore\) Third side = x = 6 cm
So, the other equal sides are 2x and 2x = 2 x 6 and 2 x 6 = 12 cm and 12 cm.
2.
As per the given information in the question, the perimeter of the rectangle is 180 cm.
Let x be the width of the rectangle.
So, length of the rectangle will be 2x.
Perimeter of a rectangle = 2 length + 2 width
\(\therefore\) 2x + 2(2x) = 180 \(\Rightarrow\) 6x = 180
\(x=\frac{180}{6}=\) 30cm
Hence, width of the rectangle is 30 cm and length of the rectangle is 2 x 30 = 60 cm.
3.
As per the given information in the question, the total number of students in the class = 60
Let x be the number of boys in the class.
So, the number of girls in the class = \(\frac{x}{3}\)
\(\therefore x+\frac{x}{3}=60\Rightarrow \frac{3x+x}{3}=60\Rightarrow \frac{4x}{3}=60\)
4x = 60 x 3 \(\Rightarrow\) 4x = 180 \(\Rightarrow x=\frac{180}{4}=45\)
Hence, the number of boys in the class is 45 and number of girls in the class is \(\frac{45}{3}=15\)
4.
Let x be the number. So, half of x is \(\frac{x}{2}\)
Then, \(\frac{x}{2}+45=3x\Rightarrow \frac{x+90}{2}=3x\)
x + 90 = 6x \(\Rightarrow\) 90 = 5x \(\Rightarrow \quad x=\frac{90}{5}=18\)
Hence, the number is 18.
5.
As per the given information in the question, the total number of students is 1070.
Let x be the number of boys in the school.
So, the number of girls in the school will be x + 50.
Then, x + (x + 50) = 1070
2x + 50 = 1070 \(\Rightarrow\) 2x = 1070 - 50
2x =1020 \(\Rightarrow\) x = 510
Hence, the number of boys in the school is 510.
So, the number of girls in the school will be
= 510 + 50 = 560.
6.
Let x be the age of Amit.
So, age of Sohan Lal, the father of Amit = 4x yr
If the difference of their ages is 27 yr.
Then, 4x- x = 27 \(\Rightarrow\) 3x = 27 \(\Rightarrow x=\frac{27}{3}=9\)
Hence, age of Amit is 9 yr.
7.
-16
8.
\(-\frac{4}{7}\)
9.
X - V = V.
10.
1
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