CBSE 7th Standard Science Motion and Time Important Questions And Answers Study Material - QB365 Set C | QB365

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CBSE 7th Standard Science Motion and Time Important Questions And Answers Study Material - QB365 Set C

Published on: 31/10/2025

Question Set C

CBSE 7th Standard Science Motion and Time Important Questions And Answers Study Material - QB365

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Std: 7th Standard CBSE - Science

chapter: Motion and Time - Important Questions And Answers

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Questions:

Generic 3

4 x 3 = 12

Plot a distance-time graph of the tip of the second hand of a clock by selecting 4 points on X-axis and Y-axis, respectively. The circumference of the circle traced by the second hand is 64 cm.

Suppose, the two photographs, shown in two figures had been taken at an interval of 10 s. If a distance of 100 m is shown by 1 cm in these photographs, then calculate the speed of the circled car.

Salma takes 15 min from her house to reach her school on a bicycle. If the bicycle has a speed of 2 m/s, calculate the distance between her house and the school.

Which of the following are not correct?
(a) The basic unit of time is second.
(b) Every object moves with a constant speed.
(c) Distances between two cities are measured in kilometres.
(d) The time period of a given pendulum is not constant.
(e) The speed of a train is expressed in m/h.

Multiple Choice Question

5 x 1 = 5

Which one records the distance travelled by a vehicle?

(a)

Speedometer

(b)

Manometer

(c)

Motometer

(d)

Odometer

If we denote speed by S, distance by D and time by T, the relationship between these quantities is

(a)

S =D \(\times\) T

(b)

\(T=\frac{S}{D}\)

(c)

\(S=\frac{1}{T}\times D\)

(d)

\(S=\frac{T}{D}\)

How will you convert the speed given in km/h to m/s?

(a)

By multiplying with 5/16

(b)

By multiplying with 6/5

(c)

By multiplying with 18/5

(d)

By multiplying with 5/18

What is the relation between distance and speed?

(a)

Distance = Speed \(\times\) Time

(b)

Distance = Speed/Time

(c)

Distance = Time/Speed

(d)

None of the above

Which of the following relations is correct?

(a)

Speed = Distance \(\times\) Time

(b)

\(Speed=\frac{Distance}{Time}\)

(c)

\(Speed=\frac{Time}{Distance}\)

(d)

\(Speed=\frac{1}{Distance\times\ Time}\)

Generic 2

4 x 2 = 8

10.

A spaceship travels 36000 km in one hour. Express its speed in km/s.

11.

Briefly explain how will decide which object is moving fast and which one is moving slow.

12.

A simple pendulum is oscillating between two points A and B as shown in figure. Is the motion of the bob uniform or non-uniform?

13.

Give the basic unit of speed.

Generic 5

2 x 5 = 10

14.

Explain by giving example that how can we choose a suitable scale.

15.

Boojho goes to the football ground to play football. The distance-time graph of his journey from his home to the ground is given as figure.
(a) What does the graph between points B and C indicate about the motion of Boojho?
(b) Is the motion between 0 to 4 min uniform or non-uniform?
(c) What is his speed between 8 to 12 min of his journey.

Fill up / 1 Marks

5 x 1 = 5

16.

The distance-time graph for the motion of an object moving with a constant speed is a____________.

17.

Motion of objects can be represented in the pictorial form by their__________graph.

18.

A________________is one billionth of a second.

19.

The symbols of all units are written in_____________

20.

Time period of a pendulum depends on its_____________.

True or False

5 x 1 = 5

21.

Periodic events are used for the measurement of time.

(a)

False

(b)

True

22.

The distance-time graph of standing vehicle is a straight line parallel to x-axis.

(a)

False

(b)

True

23.

The symbols of all units are written in singular.

(a)

False

(b)

True

24.

The time period of simple pendulum is not constant.

(a)

False

(b)

True

25.

The distance-time graph of standing vehicle is a straight line parallel to x-axis.

(a)

False

(b)

True

Match the following

5 x 1 = 5

26.

Month

27.

Second

28.

Days

29.

Minute

30.

Years

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Answers Key:

Generic 3

4 x 3 = 12

Time (s)	X	15	30	45	60
Distance (cm)	Y	16	32	48	64

As, here equal distance is covered in equal intervals of time.
So, graph will be straight line

Speed of the circled car is given by
\(=\frac{Distance\ covered}{Time\ taken}=\frac{100}{10\times 100}\)
\((1\ cm=\frac{1}{100}m)\)
\(=\frac{1}{10}m/s\)

As, we know that
Distance covered by the body = Speed \(\times\) Time
speed = 2 m/s
Time =15 min =15 \(\times\) 60= 900s
So, distance = 900 \(\times\)2 = 1800 m = 1.8 km

(b), (d) and (e) are not correct.

Multiple Choice Question

5 x 1 = 5

(d)
Odometer

(d)
By multiplying with 5/18

(a)
Distance = Speed \(\times\) Time

(b)
\(Speed=\frac{Distance}{Time}\)

Generic 2

4 x 2 = 8

10.

\(Speed=\frac{Distance}{Time}\)
\(=\frac{36000}{1\times3600}=\) [\(\therefore\) 1 h = 36000 s]
= 10 km/s

11.

If an object covers more distance in equal intervals of time with respect to other, then we can say that object is moving faster with respect to the other object.

12.

The motion of bob is non-uniform as it does not cover equal distance in equal intervals of time.

13.

Metre/second is the basic unit of speed.

Generic 5

2 x 5 = 10

14.

While choosing the most suitable scale for drawing a graph, we should keep the following points in mind
(i) The difference between the highest and lowest values of each quantity.
(ii) The intermediate values of each quantity so that with the scale chosen, it is easy to mark the values on the graph.
(iii) To utilise the maximum part of the paper on which the graph is to be drawn, assume that we have a graph paper of size 25 cm \(\times\) 25 cm and we have to accommodate following data:

Tim (AM)	Odometer reading	Distance from the starting point
8:00 AM	36540 km	0 km
8:30 AM	36560 km	20 km
9:00 AM	36580 km	40 km
9:30 AM	36600 km	60 km
10:00 AM	36620 km	80 km

Since, one of the scales will be
Distance 5 km = 1 cm and Time 6 min = 1 cm

15.

(a) Since, the graph between B and C is parallel to time-axis, so it indicates that Boojho is at rest.
(b) Since, the graph is not straight line, so it is a non-uniform motion.
\(Speed=\frac{Distance}{Time}=\frac{225-150}{12-8}=\frac{75}{4}=18.75\ m/min\)

Fill up / 1 Marks

5 x 1 = 5

16.