59.91 g/L

Interaction of H⁺ and OH^- ions of H₂O with the anion and the cation of a salt respectively to yield the original acid and the original base is called hydrolysis.
eg.
\(Na2​​​​​​​CO3+2H2O\rightarrow 2NaOH+H_{ 2 }CO_{ 3 }\\ Salt\quad \quad \quad \quad \quad \quad Base\quad \quad \quad Acid\)
Hydration, on the other hand, means addition of H₂O to ions or moleclues to form hydrated ions or hydrated.
\(KCl(s)+H_{ 2 }O(l)\rightarrow K^{ + }(aq)+cl^{ - }(aq)\\ Salt\)
\(\\ CuSo_{ 4 }(s)+5H_{ 2 }O(l)\rightarrow \ CuSO_{ 4 }.5H_{ 2 }O(s)\\ Colourless\quad \quad \quad \quad \quad \quad \quad \quad Blue\)

68 g of \({ H }_{ 2 }{ O }_{ 2 }\)produce \({ O }_{ 2 }\)= 22700 mL at NTP
\(\therefore \) 0.91 g of \({ H }_{ 2 }{ O }_{ 2 }\)will produce \({ O }_{ 2 }\)=\(\frac { 22700\times0.91 }{ 68 } \) = 303 mL at NTP
\(\therefore \) Volume strength \(\approx \) 303/10 \(\approx \) 30

27.2 g/L

In water, oxygen is sp³ -hybridised. Due to stronger lone pair-lone pair repulsions than bond pair-bond pair repulsion, the HOH bond angle decreases from 109.5^o to 104.5^o. Thus, water is a bent molecule as shown in figure.

It is a highly polar molecule. Hydrogen peroxide has a non-planar structure. Dipole moment value of H₂O₂ suggests that all the four atoms in H₂O₂ do not lie in a plane. The structure of H₂O₂ in gas phase, can be compared with a book open at angle 111.5^o.The H-O-O bind angle is 94.8^o.

Oxidising agent
\({ 2Cr(OH) }_{ 3 }+4NaOH+3{ H }_{ 2 }{ O }_{ 2 }\rightarrow 2Na_{ 2 }CrO_{ 4 }+8{ H }_{ 2 }O\)
Here,\({ Cr }^{ 3+ }\) gets oxidised to \({ Cr }^{6+ }\)
Reducing agent
\(2K_{ 3 }[Fe(CN)_{ 6 }]+2KOH+{ H }_{ 2 }{ O }_{ 2 }\rightarrow 2{ K }_{ 4 }[Fe(CN)_{ 6 }]+2{ H }_{ 2 }O+{ O }_{ 2 }\)
Here, \({ Fe }^{ 3+ }\) gets reduced to \({ Fe }^{ 2+ }\)

Anhydrous \(BaO_{ 2 }\) is not used because the \(BaSO_{ 4 }\)formed during the reaction forms a protective layer around unreacted \(BaO_{ 2 }\) and the reaction stops after sometime.

\({ H }_{ 2 }O_{ 2 }\) decomposes slowly on exposure to light and dust particles. In the presence of metal surfaces or traces of alkali present in glass containers, the traces of alkali present in glass containers, the decomposition of \({ H }_{ 2 }O_{ 2 }\) is catalysed. It is, therefore, stored in wax lined glass or plastic vessels in dark. Urea is added as a negative catalyst or stabiliser to check its decomposition.
\({ 2H }_{ 2 }O_{ 2 }(l)\overset { hv }{ \rightarrow } { 2H }_{ 2 }O(l)+{ O }_{ 2 }(g)\)

Sodium reacts with dihydrogen to form sodium hydride which is a crystalline ionic solid.
\(2Na+H_{ 2 }\rightarrow 2Na^{ + }H^{ - }\)
It reacts violently with water to produce H₂ gas
\(2NaH+2H_{ 2 }O\rightarrow 2NaOH+2H_{ 2 }\uparrow \)
In solid state NaH does not conduct electricity. When electrolysed in its molten state, it gives H₂ at anode and Na at cathode.

5.28 N

0.2 L(or 200 mL) of 5M solution will contain 
\(\frac { 340\times0.2 }{ 2 } =34g{ H }_{ 2 }{ O }_{ 2 }\)
\(\underset { 2\times 34=68g }{ { 2H }_{ 2 }O_{ 2 } } \rightarrow { 2H }_{ 2 }O+\underset { 2\times 16=32g }{ { O }_{ 2 } } \)
\(\because \ 68g \ { H }_{ 2 }O_{ 2 }\) on decomposition will give 32g\(O_{ 2 }\)
\(\therefore \ 34g \ { H }_{ 2 }O_{ 2 }\) on decomposition will give
\(\frac { 32\times 34 }{ 68 } =16g{ O }_{ 2 }\)

Molar mass of \({ H }_{ 2 }{ O }_{ 2 }=34 \ gmol^{ -1 }\)
1L of 5M solution of \({ H }_{ 2 }O_{ 2 }\)will contain 34 x 5g \({ H }_{ 2 }O_{ 2 }\)
2L of 5M solution of \({ H }_{ 2 }O_{ 2 }\)will contain 34 x 5 x 2 = 340g \({ H }_{ 2 }O_{ 2 }\)
Mass of \({ H }_{ 2 }O_{ 2 }\)present in 2L of 5 molar solution = 340g

(a) Element with Z = 15, belongs to p-block. It forms covalent hydride, PH₃
(b) Element with Z = 19 belongs to s-block. It forms ionic or saline hydride, KH
(c) Element5 with Z = 23 belongs to d-block and Vth group elements. It forms interstitial hydride, VH_1.6. It is non-stoichiometric hydride.
(d) Element with Z = 44 belongsto d-block and VIIth group elements. It is ruthinium. It does not form any hydride (hydride gap). Only ionic hydride, KH reacts violently with water producing dihydrogen gas
\(KH(s)+H_{ 2 }O(aq)\rightarrow KOH(aq)+H_{ 2 }(g)\)