No, two acute angles cannot form a linear pair because the sum of two angles forming a linear pair is always 180° but the sum of two acute angles is always less than 180°.

Let the supplement angle of 90° be x°,
We know that, the sum of two supplementary angles is 180°
\(\therefore\) x°+ 90° = 180° \(\Rightarrow\) x° = 180° - 90° = 90°
Hence, the supplement angle of 90° is 90°.

The complement angle of 41° is 49°

Let the complement angle of 45° be x°.
We know that, the sum of two complementary angles is 90°.
\(\therefore\) x°+ 45° = 90°
\(\Rightarrow\) x° = 90° - 45° = 45°
[transposing 45° to RHS]
Hence, the complement angle of 45° is 45°.

No, two obtuse angles can never be complement to each other because their sum cannot be 90°, as an obtuse angle has its measure greater than 90°.
e.g. 105° and 135° are two obtuse angles.
Their sum =105° + 135° = 240° \(\neq \)  90°
Therefore, two obtuse angles cannot be complement to each other.

60°

88°

Given, l || m || n and p || q
\(\therefore \quad \angle 6a=120°\) [corresponding angles]
\(\Rightarrow \quad \angle a=\frac { 120° }{ 6 } =20°\)
Similarly, \(\angle\)4c=120°    [corresponding angles]
\(\Rightarrow \quad \angle c=\frac { 120° }{ 4 } =30°\quad and\quad \angle 3b=\angle 4c\)
[ corresponding angles]
\(\Rightarrow \quad \angle b=\frac { 4\times 30° }{ 3 } \Rightarrow b=40°\)

Given, \(\angle \)2 = 58° \(\Rightarrow\) \(\angle \)1 = \(\angle \)2    [alternate angles]
Also, \(\angle \)1 + \(\angle \)3 =180°    [linear pair]
\(\therefore\) 58°+ \(\angle \)3=180° \(\Rightarrow\) \(\angle \)3=180°-58°
\(\Rightarrow\) \(\angle \)3 =122°
So, \(\angle \)1 = 58° and \(\angle \)3 = 122°

Let the angle be x°,
Therefore, its supplement be 180°- x°,
Since, the angle is equal to its supplement.
\(\therefore\) x°=180°-x°
On transposing x° from RHS to LHS, we get
x°+ x°= 180° \(\Rightarrow\) 2x° = 180°
On dividing both sides by 2, we get
\(\therefore \quad { x }^{ ° }=\frac { 180° }{ 2 } =90°\)
Hence, the required angle is 90°.

281°

Angle between d and f +
Angle between d and e = 180°
[\(\because\)  pair of cointerior angles]
\(\therefore\) Angle between d and f = 180° - 105°= 75°