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Published on: 04/09/2019
Principles of Inheritance and Variation
Download CBSE Class 12th Standard CBSE Biology question papers, sample papers, important questions, and previous year solved papers in PDF format. Get free study materials, NCERT solutions, and exam preparation resources for Class 12th Standard CBSE Biology
Questions + Answers key
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1.
Write the possible genotypes Mental got when crossed F1 tall pea plant with a dwarf pea plant
2.
If a father and son are both defective in red-green colour vision, is it likely that the son inherited the trait from his father? Comment.
3.
A pea plant homozygous for axial flower and constricted pods, is crossed with the pea plant homozygous for terminal flowers, having inflated pods. Work out the cross upto F1 generation. Show the genotypes of the parents and phenotype and genotype of the progeny.
4.
A child has blood group O. If the father has blood group A and mother has blood group B, work out the genotypes of the parents and the possible genotypes of the other offspring.
5.
Name the genetic disorder caused by an extra 'X' chromosome in a human male. State the diagnostic features of the individual suffering from it.
6.
Name the genetic disorder caused by trisomy of 21 st chromosome in humans. Write the diagnostic features of the disorder.
7.
Let us assume in a given plant, the genotype symbol 'Y' stands for dominant yellow seed colour and 'Y' for recessive green seed colour; symbol 'R' for round seed shape and 'r' for wrinkled seeds. Two homozygous parents (plant) with genotypes 'RRYY' and 'rryy' are crossed and their F1 generation progeny is then
(a) Phenotype of F1 progeny
(b) Genotype of F1 Progeny
(c) Gamete genotypes of F1 progeny
(d) Phenotypic ratio of F2 population
(e) Phenotypic ratio of yellow seeds to green seeds and round seeds to wrinkled seeds in F2 population.
8.
Two crosses between the same pair of genotype or phenotypes in which the sources of the gametes are reversed in one cross, is known as
Reverse cross
Dihybrid cross
Test cross
Reciprocal cross
9.
Heterozygous purple flower is crossed with recessive white flower. The progeny has the ratio :
75% purple and 25% white
50% purple and 50% white
All purple
All white
1.
( )
tt and tt (in the ratio 1:1)
2.
- No, the son never inherits colour blindness from his father.
- The gene for colour-blindness is present on the x-chromosome, but a son receives Y-chromosome from his father.
- Since a male receives the X-chromosome from his mother, he ihherits the disease from his mother only.
3.
5ince parents are homozygous, their genotypes are:
Axial-flowered, constricted pods-AAii
Terminal-flowered, inflated pods-aall

\(F_{ 1 }\) generation Aali-(Axial flowers, inflated flowers)
The phenotype of the \(F_{ 1 }\) progeny-Axial flowers and inflated pods
The genotype of the \(F_{ 1 }\)progeny-Aali
4.
The child with blood group O will have homozygous recessive alleles. Therefore, both the parents should be heterozygous, i.e. the genotype of father will be IAi and the mother will be IBi.
The other possible genotypes of offsprings willbe A, B and AB blood groups.
5.
Klinefelter's syndrome
The individual has 22 pairs of autosome and XY sex chromosomes, i,e. 47 chromosomes.
Symtoms:
The individual is a male.
He shows development of feminine characters like development of breasts.
Body hair is sparse.
The individual is sterile.
6.
Trisomy of 21st chromosome occurs due to non-disjunction, i.e. non-separation of the homologous pair of 21st chromosomes at anaphase I of meiosis during ova formation and ferlilisation of such an ovum with two 21st chromosomes with a normal sperm.
Symptoms of Down's Syndrome:
(i) Partially open mouth with furrowed tongue.
(ii) Broad, flat face with slanting eyes.
(iii) Broad palm with characteristic palm increase.
(iv) Small and arched palate.
(v) Epicanthic eye fold.
(vi) Congenital heart diseases.
(vii) Mental retardation
7.
(a) Round and yellow seeds
(b) Rr Yy

(d) 9 round, yellow seeded: 3 Round, green-seeded: 3 wrinkled, yellow seeded: 1 green, wrinkled - seeded
(e) Yellow-seeds: green seeds = 3 : 1 Round seeds: Wrinkled seeds = 3 : 1
8.
(d)
Reciprocal cross
9.
(b)
50% purple and 50% white
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