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Published on: 14/09/2019
Electrochemistry
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1.
Zn rod weighing 25 g was kept in 100 mL of 1M copper sulphate solution. After certain time interval, the molarity of Cu2+ was found to be 0.8 M. What is the molarity of SO42- in the resulting solution and what should be the mass of Zn rod after cleaning and drying ?
2.
Set-up Nernst equation for the standard dry cell. Using this equation show that the voltage of a dry cell decreases with use.
3.
The standard electrode potential (\(E°\))for Daniell cell is +1.1 V. Calculate the \(\Delta G°\) for the reaction.
Zn(s)+Cu2+(aq)\(\rightarrow\)Zn2+(aq)+Cu(s);
(1 F = 96500 C mol-1)
4.
The molar conductivity at infinite dilution of \({ Al }_{ 2 }{ \left( { SO }_{ 4 } \right) }_{ 3 }\) is 858 S cm2 mol-1. Calculate the molar ionic conductivity of \({ Al }^{ 3+ }\)given that \({ \lambda }^{ \circ }\left( { SO }_{ 4 }^{ 2- } \right) =160\) S cm2 mol-1.
5.
Define conductivity and give its units. Why is alternating current not used in place of direct current for measuring the electrolytic.
6.
Arrange the following metals in the order in which they displace each other from the solution of their salts : Al, Cu, Fe, Mg and Zn
7.
Solutions of two electrolytes A and B each having a concentration of 0.2 M have conductivities 2 x 10-2 and 4 x 10-4 S cm-1 respectively. Which will offer greater resistance to the flow of current and why ?
8.
The same quantity of electrical charge deposited 0.583 g of Ag when passed through AgNO3, AuCl3 solution. Calculate the weight of gold formed.
(At weight of Au = 197 g mol-1).
9.
What are fuel cells?How do they resemble and differ from galvanic cells?
1.
mass of Zn rod = 23.725 g, molarity of SO42- remains same.
2.
Dry cell (Leclanche cell) consists of a zinc container which acts as anode and cathode is a carbon rod surrounded by powdered manganese dioxide and carbon. The space between the electrodes is filled by a moist paste of NH4 CI and ZnCl2
The reactions are:
At anode \(Zns\rightarrow Zn^{ 2+ }(aq)+2e^{ - }\)
At cathode
\(2e^{ - }+2NH^{ + }_{ 4 }(aq)\rightarrow 2NH_{ 3 }(g)+H_{ 2 }(g)\)
\(2NH_{ 3 }(g)+Zn^{ 2+ }(aq)\rightarrow 2NH_{ 3 }(g)+H_{ 2 }(g)\)
Overall reaction
\(Zn(s)+2NH^{ + }_{ 4 }(aq)+MnO_{ 2 }(s)\rightarrow \left[ Zn(NH_{ 3 }) \right] ^{ 2+ }(aq)+Mn_{ 2 }O_{ 3 }(s)+H_{ 2 }O(l)\)
By using Nernst equation,
\(E_{ cell }=E^{ 0 }_{ cell }-\frac { 2.303RT }{ nF } in\frac { \left[ Zn(NH_{ 3 } \right] ^{ 2+ } }{ \left[ NH^{ + }_{ 4 } \right] } \)
Due to the presence of ions in the overall reaction, its voltage decreases with time.
3.
\(\begin{aligned}
\mathrm{Zn}(s)+\mathrm{Cu}^{2+}(a q) \longrightarrow & \mathrm{Zn}^{2+}(a q)+\mathrm{Cu}(s)
\end{aligned}\)
\(\begin{aligned}
E^{\circ} & =+1.1 \mathrm{~V}, \Delta G^{\circ}=?
\end{aligned}\)
\(\begin{aligned}
1 \mathrm{~F} & =96500 \space \mathrm{C} \space \mathrm{mol}^{-1}, n=2
\end{aligned}\)
\(\begin{aligned}
\Delta G^{\circ} & =-n F E^{\circ}
\end{aligned}\)
\(\begin{aligned}
=-2 \times 96500 \times 1.1=-212300 \mathrm{~J} \mathrm{~mol}^{-1}
\end{aligned}\)
4.
\({ \wedge }^{ ° }\left[ { Al }_{ 2 }{ \left( { SO }_{ 4 } \right) }_{ 3 } \right] =2{ \lambda }^{ ° }\left( { Al }^{ 3+ } \right) +3{ \lambda }^{ ° }\left( { { SO }_{ 4 } }^{ 2- } \right)\)
\({ \wedge }^{ ° }\left[ { Al }_{ 2 }{ \left( { SO }_{ 4 } \right) }_{ 3 } \right] =858S{ cm }^{ 2 }{ mol }^{ -1 },\)
\( { \lambda }^{ ° }\left( { { SO }_{ 4 } }^{ 2- } \right) =106S{ cm }^{ 2 }{ mol }^{ -1 }\)
\(\therefore \ 858=2{ \lambda }^{ ° }\left( { Al }^{ 3+ } \right) +3\times 160\)
\(\\ or \ 2{ \lambda }^{ ° }\left( { Al }^{ 3+ } \right) =858-480=378\)
\(\therefore \ { \lambda }^{ ° }\left( { Al }^{ 3+ } \right) =\frac { 378 }{ 2 } =189S{ cm }^{ 2 }{ mol }^{ -1 }\)
5.
Conductivity is the conductance of a solution of 1 cm length and having 1 sq.cm as the area of cross-section i.e., of one-centimeter cube.
Direct current results in the electrolysis of the electrolytic solution. As a result, the concentration of the electrolyte near the electrodes changes and these result change in the resistance of the solution.
6.
Mg, Al, Zn, Fe, Cu, Ag
7.
\(k=G\times \frac { 1 }{ a } =\frac { 1 }{ R } \frac { 1 }{ a } ,i.e.,k \ \infty \frac { 1 }{ R } \) Hence, B will offer greater resistance.
8.
\(\frac { { W }_{ Ag } }{ Eq.wt \ of \ Ag } =\frac { { W }_{ Au } }{ Eq.wt \ of \ Au } \)
Eq.wt. of Ag = 108, Eq.wt. of Au = \(\frac{197}{3}\)
\(\frac{0.583}{108}\)= \(\frac { { W }_{ Au } }{ \frac { 197 }{ 3 } } \), WAu = \(\frac { 0.583\times 197 }{ 108\times 3 } \)= 0.354 g
9.
Fuel cells are those cells in which chemical energy of fuel is converted into electrical energy. In both cells chemical energy is converted into electrical energy. The efficiency of fuel cell is higher than that of galvanic cell.
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