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Published on: 04/12/2019
Communication Systems
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1.
Out of the following, which is not an essential element of a communication system?
Transmitter
Transducer
Receiver
Communication Channel
2.
Audio sine waves of 3kHz frequency are used to amplitude modulate a carrier signal of 1.5 MHz. Which of the following statements are true?
The side band frequencies are 1506kHz and 1494kHz.
The bandwidth required for amplitude modulation is 6kHz
The bandwidth required for amplitude modulation is 3MHz.
The side band frequencies are 1503kHz and 1497 kHz.
3.
Identify the mathematical expression for amplitude modulated wave:
\({ A }_{ c }sin\left[ { { \omega }_{ c }+{ k }_{ 1 }{ v }_{ m }\left( t) \right] t+\phi } \right] \)
\({ A }_{ c }sin\left[ { { \omega }_{ c }t+{ \phi +k }_{ 2 }{ v }_{ m }(t) } \right] \)
\([\{ { A }_{ c }+{ k }_{ 2 }{ v }_{ m }(t)\} sin\left( { \omega }_{ c }t+\phi \right) ]\)
\({ A }_{ c }{ v }_{ m }(t)sin\left( { \omega }_{ c }t+\phi \right) \)
4.
A speech signal of 3kHz is used to modulate a carrier signal of frequency 1MHz, using amplitude modulation.The frequencies of the sidebands will be
1.003 MHz and 0.997 MHz
3001 kHz and 2997 kHz
1003 kHz and 1000 kHz
1 MHz and 0.997 MHz
5.
Frequencies in the UHF range normally propagate by means of:
Ground waves
sky waves
surface waves
space waves
6.
A 100 MHz carrier is modulated by a 12 kHz sine wave so as to cause a frequency swing of +50kHz. Find the modulation index
7.
Differentiate between (i) PAM and (ii) PPM
8.
Why cannot the
(i) ground waves
(ii) space waves and
(iii) sky waves be sustained for long distance communication system beyond 10 MH to 20 MHz.
9.
What is a transducer? Give two examples.
10.
What are the limitations of amplitude modulation?
11.
An audio signal of amplitude 0.1 V is used in amplitude modulation of a carrier wave of amplitude 0.2V.Calculate the modulation index.
12.
Define the critical frequency in relation to sky wave propagation of electromagnetic waves.On a particular day, the maximum frequency reflected from the ionosphere is 10 MHz.On another day, it was found to decrease to 8 MHz.Calculate the ratio of the maximum electron densities of the ionosphere on the two days.
13.
Explain that microwaves are better carriers of signals than radio waves?
14.
A T.V tower has a height 100 m. What is the population density around the T.V tower if the total population covered is 50 lakh? Radius of earth \( =6.4\times{ 10 }^{ 6 }m\)
15.
Explain why T.V. transmission towers are usually made high.
16.
(a) Distinguish between sinusoidal and pulseshaped signals.
(b) Explain, showing graphically, how a sinusoidal carrier wave is superimposed on a modulating signal to obtain the resultant amplitude modulated (AM) wave.
17.
Arnab was talking on his mobile to his friend for a long time. After his conversation was over, his sister Anita advised him that if his conversation was of such a long duration, it would be better to talk through a land line.
Answer the following questions :
(a) Why is it considered harmful to use a mobile phone for a long duration?
(b) Which values are reflected in the advice of his sister Anita?
(c) A message signal of frequency 10 kHz is superposed to modulate a carrier wave of frequency 1 MHz. Determine the sidebands produced.
18.
By what percentage will the transmission range of a T.V. tower be affected when the height of the tower is increased by 21%?
19.
A TV transmitting antenna is tall. How much service area this transmitting antenna cover, if the receiving antenna is at the ground level? Radius of earth = 6400 km.
1.
(b)
Transducer
2.
(b)
The bandwidth required for amplitude modulation is 6kHz
3.
(c)
\([\{ { A }_{ c }+{ k }_{ 2 }{ v }_{ m }(t)\} sin\left( { \omega }_{ c }t+\phi \right) ]\)
4.
(a)
1.003 MHz and 0.997 MHz
5.
(d)
space waves
6.
Modulation index ,mf = \(\frac { Maximum\ frequency\ deviation }{ minimum\ signal\ freqency } \)
7.
(i) Pulse Amplitude Modulation : Amplitude of the pulse varies in accordance with the modulating signal.
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(ii) (ii) Pulse Position Modulation. : Pulse position (ie) time of rise or fall of the pulse ) changes with the modulating signal.
8.
(i) In ground wave propagation, the conduction losses due to ground are very high at higher frequencies.
(ii) The space wave propagation has a limited line of sight distance due to curvature of earth.
(iii) At frequencies beyond 30 MHz, the sky waves pass through the ionosphere and are not reflected back.
9.
A transducer is a device which converts one form of energy into another.A microphone at the transmitting station and a loudspeaker at the receiving station are two examples of transducers. Infact a transducer provides output in electrical form or it has input in electrical form.
10.
(i) Efficiency of AM transmission is low
(ii) Amplitude modulation suffers from noise
(iii) Quality of audio signal is often poor.
11.
Here, Am = 0.1 V, Ac = 0.2 V,\(\mu \)=?
\(\mu \)= \(\frac { { A }_{ m } }{ { A }_{ c } } =\frac { 0.1 }{ 0.2 } =0.5\)
12.
Let N1 and N2 be maximum electron densities of the ionosphere on first and second days corresponding to 10 MHz and 8 MHz, respectively.
\(\therefore \left( \frac { { N }_{ 1 } }{ { N }_{ 2 } } \right) ^{ 1/2 }=\frac { { V }_{ c1 } }{ { V }_{ c2 } } =\frac { 10 \ MHz }{ 8 \ MHz }\)
\(\left( \frac { { N }_{ 1 } }{ { N }_{ 2 } } \right) ^{ 1/2 }=\frac { 5 }{ 4 } =\frac { { N }_{ 1 } }{ { N }_{ 2 } } =\frac { 25 }{ 16 } \)
\({ N }_{ 1 }:{ N }_{ 2 }=25:16\)
13.
Microwaves are the electromagnetic waves of wavelength of the order of a few millimeters, which is less than those of T.V. signals. On account of smaller wavelength, the microwaves can be transmitted as beam signals in a particular direction, much better than radiowaves because microwaves do not spread or bend around the corners of any obstacle coming in their way. Therefore, microwaves are better carriers of signals than radio waves.
14.
Population covered =\(\rho \times\pi { d }^{ 2 }=\rho \pi 2hR\)
so. \(50\times10^{ 5 }=\rho \times\frac { 22 }{ 7 }\times2\times100\times6.4\times{ 10 }^{ 6 }\)
or \(\rho =\frac { 5\times7 }{ 22\times2\times100\times6.4 } m^{ -2 }\\ \)
\(=\frac { 5\times7\times{ 10 }^{ 6 } }{ 22\times2\times100\times6.4 } \quad km^{ -2 } \ \\=1242.9\ km^{ -2 }\)
15.
AS the range of T.V. transmission, \(d=\sqrt { 2hr } \)so by increasing height of tower \(h\) the distance \(d\) upto which T.V. coverage can be done will increase. That is why to have greater T.V. coverage transmission has to be made using tall antennas.
16.
(a) In the process of modulation, some specific characteristics of the carrier wave is varied in accordance with the information or message signal.
The carrier wave may be :
(i) Continuous (sinusoidal) wave, or
(ii) Pulse, which is discontinuous.
A continuous sinusoidal carrier wave can be expressed as
\(E={ E }_{ 0 }sin\left( \omega t+\phi \right)\)
Three distinct characteristics of such a wave are amplitude (E0 ), angular frequency \(\left( \omega \right) \) and phase angle \(\left( \phi \right) \) . Anyone of these three characteristics can be varied in accordance with the modulating baseband (AF) signal, giving rise to the respective amplitude modulation; frequency modulation and phase modulation.
Again, the significant characteristics of a pulse are pulse amplitude, pulse duration or pulse width and pulse position (representing the time of rise or fall of the pulse amplitude). Anyone of these characteristics can be varied in accordance with the modulating baseband (AF)signal, giving rise to the respective, pulse amplitude modulation (PAM), pulse duration modulation (PDM) or pulse width modulation (PWM) and pulse position modulation (PPM).
(b) Amplitude Modulation: When a modulating AF wave is superimposed on a high frequency carrier wave in a manner that the frequency of modulated wave is same as that of the carrier wave, but its amplitude is made proportional to the instantaneous amplitude of the audio frequency modulating voltage, the process is called amplitude modulation (AM).
Let the instantaneous carrier voltage (ec ) and modulating voltage (em) be represented by
\({ e }_{ c }={ E }_{ c }sin{ \omega }_{ c }t ...(i)\)
\(\\ { e }_{ m }={ E }_{ m }sin{ \omega }_{ m } \quad ...(ii)\)
Thus, in amplitude modulation, amplitude A of modulated wave is made proportional to the instantaneous modulating voltage em
\(i.e., A={ E }_{ c }+{ ke }_{ m }\quad ...(iii)\)
where k is a constant of proportionality.
In amplitude modulation, the proportionality constant k is made equal to unity. Therefore, maximum positive amplitude of AM wave is given by
\(A={ E }_{ c }+{ e }_{ m }={ E }_{ c }+{ E }_{ m }\)
\(sin \ { \omega }_{ m }t \ \ ...(iv)\)
It is called top envelope.
The maximum negative amplitude of AM wave is given by
\(-A=-{ E }_{ c }-{ e }_{ m }\)
\(=-\left( { E }_{ c }+{ E }_{ m }sin\ { \omega }_{ m }t \right) ...(v)\)
17.
(a) The ultra-high frequency em radiations, continuously emitted by a mobile phone, may harm the system of the human body.
(b) Sister Anita shown
(i) Concern about her brother
(ii) Awareness about the likely effects of em radiations on human body
(iii) Sense of responsibility any two)
(c) The sidebands are
\(({ V }_{ c }+{ \upsilon }_{ m }) \ and \ ({ V }_{ c }-{ \upsilon }_{ m })\)
\(or \ (1000 \ + \ 10) \ kHz \ and \ (1000 \ - \ 10) \ kHz \)
\(1010 \ kHz \ and \ 990 \ kHz\)
18.
Original transmission range,
\(d=\sqrt { 2hR } \)
New height, \({ h }^{ \prime }=h+\frac { 21h }{ 100 } =1.21h\)
New transmission range,
\({ d }^{ \prime }=\sqrt { 2{ h }^{ \prime }R } =\sqrt { 2\times 1.21hR } =1.1d\)
% increase in range
\(=\frac { { d }^{ \prime }-d }{ d } \times 100=\frac { \left( 1.1d \right) -d }{ d } \times 100\)= 10%
19.
Here, h = 125 m ;
R = 6400 km = 6.4 x 106 m.
Area covered = \(\pi { d }^{ 2 }=\pi \times 2hR\ \left[ \because \ \sqrt { 2hR } \right] \)
= 3.14 x 2 x 125 x 6.4 x 106
= 5024 x 106 m2 = 5024 km2
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