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CBSE 12th Standard Chemistry Subject Chemical Kinetics Ncert Exemplar 2 Mark Questions 2021

Published on: 25/05/2021

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Std: 12th Standard CBSE - Chemistry

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Questions:

Generic 2

3 x 2 = 6

In a reaction, if the concentration of reaction A is tripled, the rate of reaction becomes twenty seven times. What is the order of the reaction ?

How can you determine the rate law of the following reaction ?
2 NO (g) + O₂ (g) \(\longrightarrow\) 2 NO₂ (g)

Write the rate equation for the reaction 2 A + B \(\longrightarrow\) C if the order of the reaction is zero.

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Answers Key:

Generic 2

3 x 2 = 6

\({ r }_{ 1 }={ k\left[ A \right] }^{ \alpha }={ ka }^{ \alpha };\quad { r }_{ 2 }=k{ \left( 3a \right) }^{ \alpha };\frac { { r }_{ 2 } }{ { r }_{ 1 } } ={ 3 }^{ \alpha }=27\quad (Given)={ 3 }^{ 3 }\)
\(\therefore \ \alpha =3\)

We can measure the rate of this reaction as a function of initial concentrations either by keeping the concentration of one of the reactants constant and changing the cone of the other reactant and observing the change in rate of reaction.
When the cone. of NO is doubled and O₂ is kept constant initial rate increases by 4, therefore, order is 2 w.r.t NO. When cone of [NO] is kept constant, [O₂] is doubled, rate becomes double so order is 1
W.r.t \({ O }_{ 2 }\)Rate law: \(Rate=k{ \left[ NO \right] }^{ 2 }{ \left[ { O }_{ 2 } \right] }^{ 1 }\)

The rate equation for the given reaction is rate
Rate = k [A]⁰ [B]⁰ = k.