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Published on: 28/05/2021
QB365 Provides the HOT Question Papers for Class 12 Chemistry, and also provide the detail solution for each and every HOT Questions. HOT Questions will help to get more idea about question pattern in every exams and also will help to get more marks in Exams
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Questions + Answers key
Take MCQ Chemistry Test1.
Name a hexadentate ligand and write the formula of its complex with Co(III).Draw its structure.
2.
\(Cu{ \left( OH \right) }_{ 2 }\)is soluble in \({ NH }_{ 4 }OH\)but not in NaOH solution.Why?
3.
Calcium dihydrogen salt of EDTA is used as an antidote for lead poisoning, why?
4.
Why do the two complexes \({ PtCl }_{ 4 }.2{ NH }_{ 3 }\)and \({ PtCl }_{ 4 }.2KCL\)not give a precipitate of AgCl with \({ AgNO }_{ 3 }\)solution?
1.
Hexadentate ligand is EDTA (ethylenediaminetetra acetate).

2.
\(Cu{ \left( OH \right) }_{ 2 }\) is soluble in\({ NH }_{ 4 }OH\) due to the formation of soluble complex.\(\left[ Cu{ \left( { NH }_{ 3 } \right) }_{ 2 } \right] { \left( OH \right) }_{ 2 }\)But no such complex is formed by the reaction of \(Cu{ \left( OH \right) }_{ 2 }\)with NaOH.
3.
EDTA coordinates lead in the body because of more soluble lead-EDTA complex, which can be eliminated in urine without causing any harmful effects.The calcium salt of EDTA is used so that any excess EDTA will not remove Ca2+ ions from the body.
4.
\({ PtCl }_{ 4 }.2{ NH }_{ 3 }\)has the structural formula \(\left[ Pt{ \left( { NH }_{ 3 } \right) }_{ 2 }{ Cl }_{ 4 } \right] \)and\({ PtCl }_{ 4 }.2KCL\) has the structural formula \({ K }_{ 2 }\left[ { PtCl }_{ 6 } \right] \). In both cases, the Cl- ions are present in the coordination sphere and are not ionizable. Therefore, these don't give tests for Cl- ions with \({ AgNO }_{ 3 }\) solution.
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