12th Standard CBSE Syllabus & Materials
12th Standard CBSE
CBSE 12th Economics Government Budget and the Economy Previous year Question Papers Study Material - QB365 Set A
NEW12th Standard CBSE
CBSE 12th Computer Science Interface Python with MySQL - New Previous year Question Papers Study Material - QB365 Set A
NEW12th Standard CBSE
CBSE 12th Computer Science Database Concept - New Previous year Question Papers Study Material - QB365 Set A
NEW12th Standard CBSE
CBSE 12th Computer Science Data Communication - New Previous year Question Papers Study Material - QB365 Set A
NEW12th Standard CBSE
CBSE 12th Computer Science Data Structures - New Previous year Question Papers Study Material - QB365 Set A
NEW12th Standard CBSE
CBSE 12th Computer Science Functions - New Previous year Question Papers Study Material - QB365 Set A

Published on: 25/05/2021
QB365 Provides the updated NCERT Exemplar Questions for Class 12, and also provide the detail solution for each and every NCERT Exemplar questions. NCERT Exemplar questions are latest updated question pattern from NCERT, QB365 will helps to get more marks in Exams
Download CBSE Class 12th Standard CBSE Chemistry question papers, sample papers, important questions, and previous year solved papers in PDF format. Get free study materials, NCERT solutions, and exam preparation resources for Class 12th Standard CBSE Chemistry
Questions + Answers key
Take MCQ Chemistry Test

1.
Express the relation among conductivity of the solution in the cell, the cell constant and resistance of solution in the cell.
2.
How do metallic and ionic substances differ in conducting electricity ?
3.
How many faradays of electric charge is required to liberate 5600 cm3 of oxygen at STP ?
4.
What is meant by Faraday constant?
1.
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\text { Conductivity }(k)=\frac{1}{\text { Resistance }(R)} \times \text { Cell constant }\)
2.
In metallic substances, flow of electricity is due to flow of electrons while in ionic substances in the aqueous solution or molten state, the flow of electricity is due to flow of ions.
3.
\( O^{2-} \longrightarrow \frac{1}{2} O_2+2 e^{-} \text {or } 2 O^{2-} \longrightarrow O_2+4 e^{-}\)
Thus, 1 mole of O2 , i.e., 22400 cm3 require 4 faradays of charge.
5600 cm3 of O2 will require charge \(=\frac{4}{22400}=5600=\) 1 fara day
4.
Faraday constant, F = 96500 coulombs. It is that quantity of electricity which deposits one gram equivalent of the substance or it is the charge carried by one mole of electrons.
12th Standard CBSE Syllabus & Materials
12th Standard CBSE
CBSE 12th Computer Science Python Revision Tour I - New Previous year Question Papers Study Material - QB365 Set A
NEW12th Standard CBSE
CBSE 12th Business Studies Planning Important Questions And Answers Study Material - QB365 Set A
NEW12th Standard CBSE
CBSE 12th Business Studies Business Environment Important Questions And Answers Study Material - QB365 Set A
NEW12th Standard CBSE
CBSE 12th Business Studies Principles of Management Important Questions And Answers Study Material - QB365 Set A
NCERT Books
Syllabus
Exam Pattern
Sample Question Papers
Previous year Question Papers
Important Notes
MCQ Practice test
NCERT Exemplers
Case study Questions
Image Based Questions
Passage based Questions
HOT Questions
Value Based Questions
Model Questions Papers
NCERT ( Book Back ) Questions
Assertion and Reason
Important Questions And Answers
CBSE 12th Standard CBSE Subjects
CBSE Standards