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Published on: 25/05/2021
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Questions + Answers key
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1.
How is copper extracted from low grade copper ores?
2.
Wrought iron is the purest form of iron.Write a reaction used for the preparation of wrought iron from cast iron.How can impurities of sulphur,silicon and phosphorus be removed from cast iron?
3.
At temperature above 1073 K coke can used to reduce FeO to Fe.How can you justify this reduction with Ellingham diagram?
4.
Why is an external emf of more than 2.2 V required for the extraction of Cl2 from brine?
5.
Which method is used for refining Zr and Ti? Explain with equation.
1.
Copper is extracted by hydrometallurgy from low grade, ores. It is leached out using acid or bacteria. The solution containing copper ions (Cu2+) is treated with scrap iron, zinc or H2 as:
\({Cu }^{ 2+ }(aq)+{ H }_{ 2 }(g)\longrightarrow Cu(s)+{ 2H }^{ + }(aq)\)
\({Cu}^{ 2+ }+Fe(s)\longrightarrow Cu(s)+{ Fe }^{ 2+ }(aq)\)
In this way, copper is obtained.
2.
The reaction is:
\({ Fe }_{ 2 }{ O }_{ 3 }+3C\longrightarrow 2Fe+3CO\)
Limestone is added as flux and the impurities of sulphur, silicon and phosphorus change to their oxides and pass into slag.
3.
At temperatures above 1073 K,\(\Delta\)fG0 (Fe,FeO) curve,i.e.,\(\Delta\)fG0(C,CO)<\(\Delta\)fG0(Fe,FeO),therefore,coke can reduce FeO to Fe
4.
For the reaction
\(2{ Cl }^{ - }(aq)+{ 2H }_{ 2 }O(l)\longrightarrow { 2OH }^{ - }(aq)+{ H }_{ 2 }(g)+{ Cl }_{ 2 }(g),\)
the value of \(\Delta G°\) is +422 kJ. Using the equation \(\Delta G°\) = \(-nE°F\), the value of \(E°\) comes out nearly to be -2.2 V.
[+ 422 X 103 J = -2 x 96500 x \(E°\)
\(E°\) = -2.2V]
Therefore, extraction of CI2 from brine will require an external emf of greater than 2.2 volts.
5.
van Arkel method is used for refining Zr and Ti. In this method, impure metal is heated with iodine which decomposes to give pure metal and iodine is recovered.
\(Zr+2{ I }_{ 2 }\rightarrow Zr{ I }_{ 4 }\)
(Impure)
\(Zr{ I }_{ 4 }\overset { 1800\quad K }{ \rightarrow } Zr+2{ I }_{ 2 }\)
(Pure)
\(\mathrm{T}_{1}+2 \mathrm{I}_{2} \longrightarrow \mathrm{T}_{1} \mathrm{I}_{4} \stackrel{1800 \mathrm{~K}}{\longrightarrow} \mathrm{T}_{1}+2 \mathrm{I}_{2}\)
(Impure) (Pure)
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