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Published on: 24/05/2021
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Questions + Answers key
Take MCQ Maths Test1.
Which of the following functions is decreasing on \(\left(0, \frac{\pi}{2}\right)\)?
sin2x
tanx
cosx
cos3x
2.
The function \(f(x)=\tan x-x\)
always increases
always decreases
never increases
sometimes increases and sometimes decreases
3.
If \(y=x(x-3)^{2}\) decreases for the values of x given by
\(1<x<3\)
\(x<0\)
\(x>0\)
\(0<x<\frac{3}{2}\)
4.
A ladder, 5 m long, standing on a horizontal floor, leans against a vertical wall. If the top of the ladder slides downwards at the rate of 10 cm/s, then the rate at which the angle between the floor and the ladder is decreasing when lower end of ladder is 2 m from the wall is
\(\frac{1}{10} \mathrm{rad} / \mathrm{s}\)
\(\frac{1}{20} \mathrm{rad} / \mathrm{s}\)
\(20 \mathrm{rad} / \mathrm{s}\)
10 rad/s
1.
In the interval \(\left(0, \frac{\pi}{2}\right), f(x)=\cos x\)
\(\Rightarrow \quad f^{\prime}(x)=-\sin x\)
which gives \(f^{\prime}(x)<0 \text { in }\left(0, \frac{\pi}{2}\right)\)
Hence, f(x) = cos x is decreasing in \(\left(0, \frac{\pi}{2}\right)\)
2.
We have, f(x) = tan x - x
\(\therefore \quad f^{\prime}(x)=\sec ^{2} x-1 \Rightarrow f^{\prime}(x) \geq 0, \forall x \in R\)
So, f(x) always increases
3.
We have,\(y=x(x-3)^{2}\)
\(
\therefore \quad \frac{d y}{d x} =x \cdot 2(x-3) \cdot 1+(x-3)^{2} \cdot 1 \\
=2 x^{2}-6 x+x^{2}+9-6 x=3 x^{2}-12 x+9 \\
=3\left(x^{2}-3 x-x+3\right)=3(x-3)(x-1)
\)
So, y = x(x - 3)2 decreases for (1, 3).
[since, y' < 0 for all x E (1,3), hence y is decreasing on (1, 3)]
4.
(b)
\(\frac{1}{20} \mathrm{rad} / \mathrm{s}\)
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