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CBSE 12th Standard Physics Subject Dual Nature of Radiation and Matter HOT Questions 1 Mark Questions With Solution 2021

Published on: 27/05/2021

QB365 Provides the HOT Question Papers for Class 12 Physics, and also provide the detail solution for each and every HOT Questions. HOT Questions will help to get more idea about question pattern in every exams and also will help to get more marks in Exams

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Std: 12th Standard CBSE - Physics

chapter: - HOT Questions

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Questions:

Generic 2

5 x 2 = 10

Visible light can not eject photo electrons from copper surface, whose work function is 4.4 ev , why? Prove mathematically

If the potential difference used to accelerate electron is doubled , by what factor the Debroglie wave length of the electron beam changed

The De-broglie wave length associated with proton and neutron are equal.Which has greater kinetic energy?

Following table gives values of work function for a few photosensitive metal

S.NO	Metal	Work functions
1	Na	1.92
2	K	2.15
3	Mo	4.17

If each metal is exposed to radiation of wavelength 300nm which of them will not emit photo electron

The de-broglie wave length of a photon is same as the wave length of electron. Show that K.E. of a photon is 2mc \(\lambda \)/h times K.E. of electron. Where ‘m’ is mass of electron,c is velocity of light.

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Answers Key:

Generic 2

5 x 2 = 10

\(\lambda=h c / \Phi=2823 \mathrm{~A}\)

\(\lambda=\lambda / \sqrt{ } 2\)

\(\mathrm{R} \alpha 1 / \mathrm{q}\)

M_o will not emit photo electron , because its work function is more than 4 ev

\(\lambda_{p h}=\lambda=\lambda=h / m v\)
K.E of electrons E \(=1 / 2 m v^2=1 / 2 m\left[h / m^2\right] \lambda\)
\( =\mathrm{h}^2 / 2 \mathrm{~m}^2 \lambda \\ \therefore \mathrm{Eph}=\mathrm{Ee}(2 \mathrm{mc} \lambda / \mathrm{h}) \)