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Published on: 27/05/2021
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Questions + Answers key
Take MCQ Physics Test1.
Why is the ionization power of \(\alpha\) – particle of greater than \(\gamma\) – rays?
2.
What happens to the fringe pattern when YDS experiment is performed in water instead of air?
3.
How does the self inductance of a coil change, when Number of turns in the coil is decreased? An iron rod is introduced into it. Justify your answer in each case
4.
A coil A is connected to voltmeter V and the other coil B to an alternating current source D. If a large copper sheet CC is placed between the two coils, how does the induced e.m.f in the coil A change due to current in coil B?
5.
The above figure shows a horizontal solenoid connected to a battery and a switch. A copper ring is placed on a frictionless track near the solenoid, the axis of the ring being along the axis of the solenoid. What will happen to the ring as the switch is closed? Justify your answer
6.
A magnetic needle suspended freely in a uniform magnetic field experiences torque but no net force. A nail made up of iron kept near a bar magnet experience a force of attraction and torque .Give reason
7.
How does a ferromagnetic material change its Magnetic properties if it is heated beyond its curie temperature?
8.
Out of Ammeter and Milliammeter, which has the higher resistance?
9.
A cylindrical metallic wire is stretched to increase its length by 5%. Calculate the percentage change in resistances.
10.
Two wire of equal length one copper and manganin have same resistance , which wire is thicker?
11.
Device an arrangemnet of three point charges separated by finite distances that has zero electric potential energy.
12.
A positively charged particle is released from rest in a uniform electric field.What happens to its electrostatic potential energy?
13.
Two charges of -9C and +9C are palced at the points P(1, 0, 4) and Q(2,-1, 5) located in an electric field E = 0.20i V/cm. Calculate the torque acting on the dipole.
14.
What is the solid angle subtended by a hemisphere at a point inside it?
1.
Owing to greater mass and charge, it is able to knock out/pull out electrons which colliding with atoms and molecules in its path.
2.
Shrinks
3.
i. L \( \alpha\) n2 \(\Rightarrow\) L is decreased
ii. L Will Increase
4.
The induced e.m.f in coil A decreases due to large copper plate introduced between the two coils as Cu is diamagnetic material.
5.
The Ring Moves a way From the Solenoid
6.
Due to the non uniform magnetic field of bar magnet nail experience torque and translatory force
7.
Becomes Paramagnetic
8.
We know the resistance connected to galvanometer to convert it into ammeter is S =(Ig/( I – Ig))xG
So for higher resistance, the range of I should be small, therefore milliammeter has the higher resistance.
9.
\(R = ρ L/A
\)
(i.e) 10.25%
10.
Resistivity of Copper is less, hence mangain wire is thicker
11.
U = kq2/a - kq2/2a - kq2/2a = 0
12.
As, the positively charged particle experiences electrostatic force in the direction of electric field. Some work is done by the electric field on the positive charge, hence electrostatic potential energy decreases.
13.
As, P(1, 0, 4) and (2,-1, 5)
\(\therefore \ 2l=PQ=[(2-1)\hat { i } +(-1-0)\hat { j } +(5-4)\hat { k] }\\
=(\hat { i } -\hat { j } +\hat { k } )\)
and \(\ q=\pm 9\times { 10 }^{ -6 }C,E=0.20\hat { i } V/cm.\tau =?\)
Since, \(\tau =\rho \times E=q(2l)\times E\)
\(\therefore \ \tau =9\times { 10 }^{ -6 }(\hat { i } -\hat { j } +\hat { k } )\times 0.20=18\times { 10 }^{ -7 }(\hat { k } -\hat { j) }
\)
Magnitude of torque,
\(\tau =18\times { 10 }^{ -7 }[\sqrt { { (1) }^{ 2 }+{ (1) }^{ 2 } } ]=25.45\times { 10 }^{ -7 }N-m\)
14.
Soild angle, \(\omega \) = \(\frac { S\cos { \theta } }{ { { r }^{ 2 } } } \)
Here, \(S = 2\pi { r }^{ 2 }, \theta = 0^{o} \)
\(\omega\) = \(\frac { 2\pi { r }^{ 2 }\times 1 }{ { { r }^{ 2 } } } \)
\( = 2\pi\) steradian.
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