no electronswillbe emittedas onlyphotons can emit electrons

electronscan be emittedbut all with an energy,E₀

electronscan be emittedwith any energy,with a maximumof E ₀ - φ (φ is the work function)

electronscan be emittedwith any energy,with a maximumof E₀

He should measure I₁ more accurately

He should change Sto 1000Ω and repeat the experiment

He should change S to 3Ω and repeat the experiment

He should given up hope of a more accurate measurement with a meter bridge

they will break up

elastic collision of neutrons with heavy nuclei will not slow them down

the net weight of the reactor would be unbearably high

substances with heavy nuclei do not occur in liquid or gaseous state at room temperature

S₁ is true but S₂ is false

Both S₁ and S₂ are false

S₁ is true, S₂ is also true and S₁ is the cause of S₂

S₁ is true, S₂ is also true but the statements are independant

5\(\sqrt{2} A\)

5\(\sqrt{3/2}\) A

5 / 6 A

5 / \(\sqrt{2} A\)

perpendicular to the diameter

parallel to the diameter

at an angle tilted towards the diameter

at an angle tilted away from the diameter

Electrons crossover from emitter to collector

Holes move from base to collector

Electrons move from emitter to base

Electrons from emitter move out of base without going to the collector

no electrons will be emitted as only photons can emit electrons

electrons can be emitted but all with an energy E₀ 

electrons can be emitted with any energy, with a maximum of \({ E }_{ 0 }-\phi \)(\(\phi \)is the work function)

electrons can be emitted with any energy, with a maximum of E₀

will not be applicable to hydrogen in the molecular form 

will not be applicable as it is for a He-atom

is valid only at room temperature

predicts continuous as well as discrete spectral lines

because only one of these would have a minimum energy

because only one of these would have a minimum energy

angular momentum must be in the direction of spin of electron

because electrons go arround only in horizontal obits.