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Published on: 01/08/2018
Based on the Organic Compounds containing Nitrogen ( Amines ), some of the important questions are covered in this question paper. The questions are prepared from the book back and the creative questions.
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Questions + Answers key
Take MCQ Chemistry Test
1.
Which is soluble in water NH3 or methylamine?
2.
Explain the following reactions:
(i) Gabriel phthalimide reaction
(ii) Coupling reaction
3.
How can you convert aniline to iodobenzene?
4.
What is the role of NHO3 in the nitrating mixture used for nitration of benzene?
5.
Mention one commercial use of N, N-Dimethylaniline (DMA).
6.
Write a chemical reaction in which the iodide ion replaces the diazonium group in a diazonium salt.
7.
Explain why the amino group in aniline acts as a powerful activator and ortho and para director towards electrophilic substitution reaction.
8.
Complete the folowing reaction equations:
(i) C6H5N2CI+CH3COCI \(\longrightarrow \)
(ii)C2H5NH2+C6H5SO2CI \(\longrightarrow \)
(iii) C2H5NH2+HNO2 \(\longrightarrow \)
9.
Write chemical equations for the following conversions:
(i) Nitrobenzene to benzoic acid
(ii) Benzyl chloride to 2-phenylethanamine.
(iii) Aniline to benzyl alcohol.
10.
Draw the structures of different isomers corresponding to the molecular formula, C3H9N. Write the IUPAC names of the isomers which will liberate nitrogen gas on treatment with nitrous acid.
11.
p-Chloroaniline and anilinium hydrochloride can be distinguished by
Sandmeyer reaction
NaHCO3 solution
AgNO3 solution
Carbylamine reaction
12.
Isopropylamine can be obtained by
\(\left( { CH }_{ 3 } \right) _{ 2 }C=O+{ NH }_{ 2 }OH\longrightarrow ?\quad \overset { LiAIH_{ 4 } }{ \longrightarrow } \)
\(\left( { CH }_{ 3 } \right) _{ 2 }CO+{ NH }_{ 3 }\overset { Ni/H_{ 2 } }{ \underset { \triangle }{ \longrightarrow } } \)
\(\left( { CH }_{ 3 } \right) _{ 2 }CH-Br+NaNH_{ 2 }\longrightarrow \)
\(\left( { CH }_{ 3 } \right) _{ 2 }CH-Br\overset { { NaN }_{ 3 } }{ \longrightarrow } ?\overset { { LiAIH }_{ 4 } }{ \longrightarrow } \quad \)
13.
Which of the following will be the most stable diazonium salt, \({ RN }_{ 2 }^{ + }{ X }^{ - }\) ?
\(CH_{ 3 }{ N }_{ 2 }^{ + }{ X }^{ - }\)
\({ C }_{ 6 }H_{ 5 }{ N }_{ 2 }^{ + }{ X }^{ - }\)
\(CH_{ 3 }{ CH }_{ 2 }{ N }_{ 2 }^{ + }{ X }^{ - }\)
\({ C }_{ 6 }H_{ 5 }{ CH }_{ 2 }{ N }_{ 2 }^{ + }{ X }^{ - }\)
14.
Positive carbylamine test is shown by
N, N-dimethylaniline
triethylamine
N-methylaniline
p-methylbenzylamine
dimethylamine
15.
Anorganic compound A upon reacting with NH3 gives B. On heating, B gives C. C in presence of KOH reacts with Br2 to give CH3CH2NH2. A is
CH3CH2COOH
CH3COOH
CH3CH2CH2COOH
\({ CH }_{ 3 }-\underset { \underset { { CH }_{ 3 } }{ | } }{ CH } -COOH\)
16.
Reduction of aromatic nitro compounds using Fe and HCI gives............................ .
aromatic oxime
aromatic hydrocarbon
aromatic primary amine
aromatic amide
17.
Amongst the following, the strongest base in aqueous medium is ____________.
CH3NH2
NCCH2NH2
(CH3)2NH
C6H5NHCH3
18.
Which of the following compounds gives dye test?
Aniline
Methylamine
Diphenylamine
Ethylamine
19.
\({ CH }_{ 3 }{ CH }_{ 2 }\overset { Aq.KOH }{ \underset { \triangle }{ \longrightarrow } } A\overset { KMnO_{ 4 }\quad /\quad { H }^{ + } }{ \underset { \triangle }{ \longrightarrow } } B\overset { N{ H }_{ 3 } }{ \underset { \triangle }{ \longrightarrow } } C\overset { B{ r }_{ 2 } }{ \underset { Alkali }{ \longrightarrow } } D;D\quad is\)
\({ CH }_{ 3 }Br\)
\({ CH }_{ 3 }CONH_{ 2 }\)
\({ CH }_{ 3 }NH_{ 2 }\)
\({ CH }Br_{ 3 }\)
20.
Nitration of nitrobonzene results in..............
o-dinitrobenzene
1, 3, 5-trinitrobenzene
p-dinitrobenzene
m-dinitrobenzene
21.
Lakshay and Varun were going to the market.On the way they saw tie and dye shop of clothes Varun was surprised to see that and was unable to understand surprised to see that and was unable to understand how the clothes get coloured there. When they came back Lakshay explained reason to Varun Diazonium salts are the most reactive derivatives of aromatic primary amines These are formed as a result of diazotization reaction carried under ice cooled conditions.Diazonium salts lead to coloured azodyes by coupling reactions under acidic or alkaline conditions. A very popular azodye is methyl orange.
Give the answer of two following questions:
(i) What are the constituents of methyl orange?
(ii) How is methyl orange is useful?
(iii) How is methyl orange is useful?
(iv) What are the values shown by them?
22.
Why is an amide more acidic than amine?
1.
NH3 is more soluble in water due to more H-bonding.
2.
(i) Gabriel's phthalimide synthesis: Phthalimide when treated with alcoholic potassium hydroxide is easily converted into potassium phthalimide which on treatment with alkyl halide followed by hydrolysis with acid or alkali yields phthalic acid and a primary amine.
(ii) Coupling reaction: It involves the reaction of benzene diazonium salts with phenols or aryl amines. Coupling of phenol takes place in mild alkaline solution while with aromatic 10 amines in mild, acidic medium.
3.
4.
It acts as a base and provides electrophile \(\stackrel{\oplus}{\mathrm{N}} \mathrm{O}_2\)
5.
It is used in preparation of dyes.
6.
7.
-NH2 group has lone pair of electrons, therefore, it increases electron density at o and p-positions and that is why electrophilic substitution takes place at o- and p-positions.
8.
9.
10.
Four structural isomers are possible.
11.
Both p-chloroaniline and anilinium hydrochloride are \({ 1 }^{ \circ }\) amines and hence cannot be ditinguished by carbylamine reaction.
12.
NaNH2 brings out dehydrobromination to form propene.
13.
Due to delocalization of the +ve charge on the benzene ring, aromatic diazonium salts are more satble, i.e., option (b) is correct.
14.
Only \({ 1 }^{ \circ }\) amines, i.e., p-methylbenzylamine, (p) CH3-C6H4-CH2NH2, give carbylamine test.
15.
(a)
CH3CH2COOH
16.
(c)
aromatic primary amine
17.
(c)
(CH3)2NH
18.
(a)
Aniline
19.
(c)
\({ CH }_{ 3 }NH_{ 2 }\)
20.
(d)
m-dinitrobenzene
21.
The constituents of methyl orange are sodium salt of sulphanilic acid and N-dimethyl aniline
(ii) The structure of methyl orange is:
(iii) It is very useful indicator for acid alkali titrations In acidic medium its colour is red and it becomes alkaline or basic
(iv) Varun was curious and Lakshay was having scientific attitude,friendly nature helpful.
22.
The amide has the following resonating structures:
Due to the delocalisation of lone pair of electrons on N over C==O group, amino group acquires a positive charge which ma, es N-H bond weak. Moreover, the anion formed after removal of a proton is also stabilized by resonance as :
.png)
However, no such stabilization is possible in amines.
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