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Published on: 07/09/2019
Hydrocarbons
Download Tamil Nadu 11th Standard Chemistry question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Chemistry Test
1.
Which among the following alkenes on reductive ozonolysis produces only propanone?
2 – Methyl propene
2 – Methyl but – 2 - ene
2, 3 – Dimethyl but – 1 – ene
2, 3 – Dimethyl but – 2 – ene
2.
The compound that will react most readily with gaseous bromine has the formula (NEET)_____________
C3H6
C2H2
C4H10
C2H4
3.
The general formula for cyclo alkanes _________
CnHn
CnH2n
Cn H2n–2
Cn H2n+2
4.
The C – H bond and C – C bond in ethane are formed by which of the following types of overlap _________
sp3 – s and sp3 – sp3
sp2 – s and sp2 – Sp2
sp – sp and sp – sp
p – s and p – p
5.
An alkyl bromide (A) reacts with sodium in ether to form 4, 5– diethyloctane, the compound (A) is _________
CH3 (CH2)3 Br
CH3(CH2)5 Br
CH3(CH2)3 CH(Br)CH3
\({ CH }_{ 3 }-{ \left( { CH }_{ 2 } \right) }_{ 2 }-CH\left( Br \right) -\underset { \overset { { | } }{ { CH }_{ 3 } } }{ { CH }_{ 2 } } \)
6.
The correct statement regarding the comparison of staggered and eclipsed conformations of ethane is (NEET)______________
the eclipsed conformation of ethane is more stable than staggered conformation even though the eclipsed conformation has torsional strain
the staggered conformation of ethane is more stable than eclipsed conformation, because staggered conformation has no torsional strain
the staggered conformation of ethane is less stable than eclipsed conformation, because staggered conformation has torsional strain
the staggered conformation of ethane is less stable than eclipsed conformation, because staggered conformation has no torsional strain
7.
How will you distinguish 1 – butyne and 2 – butyne?
8.
Identify A and B.
9.
Give IUPAC names for the following compounds
CH3 – CH = CH – CH = CH – C ≡ C – CH3
10.
An alkylhalide with molecular formula C6H13Br on dehydro halogenation gave two isomeric alkenes X and Y with molecular formula C6H12. On reductive ozonolysis, X and Y gave four compounds CH3COCH3, CH3CHO, CH3CH2CHO and (CH3)2 CHCHO. Find the alkylhalide.
11.
How is propyne prepared from an alkyene dihalide?
12.
Identify the compound A, B, C and D in the following series of reactions
13.
What happens when isobutylene is treated with acidified potassium permanganate?
14.
Suggest a simple chemical test to distinguish propane and propene.
15.
How does Huckel rule help to decide the aromatic character of a compound.
1.
(d)
2, 3 – Dimethyl but – 2 – ene
2.
(a)
C3H6
3.
(b)
CnH2n
4.
(a)
sp3 – s and sp3 – sp3
5.
(d)
\({ CH }_{ 3 }-{ \left( { CH }_{ 2 } \right) }_{ 2 }-CH\left( Br \right) -\underset { \overset { { | } }{ { CH }_{ 3 } } }{ { CH }_{ 2 } } \)
6.
(b)
the staggered conformation of ethane is more stable than eclipsed conformation, because staggered conformation has no torsional strain
7.
An alkyne shows acidic nature only if it contains terminal hydrogen.
CH3 - CH2 - C \(\equiv \) CH + 2AgNO3 + 2NH4OH \(\rightarrow\) CH3 - CH2 - C \(\equiv \) C - Ag + 2NH4NO3 + 2H2O
1 - butyne Silver butynide
CH3 - C \(\equiv \) C - CH3 + 2AgNO3 + 2NH4OH \(\rightarrow\) No Reaction due to absence of acidic hydrogen
8.
9.
10.
11.
12.
| compound | Structural formula | Name |
| A | CH2 = CH2 | Ethene |
| B |  |
1,2 - dichloroethane |
| C | HCHO | Methanal |
| D | \(\mathrm{CH} \equiv \mathrm{CH}\) | Ethyne |
13.
The purple KMnO4 becomes colourless producing acetone.
14.
Decolotrisation of Bromine - water (Reddish brown) colour takes place with Propene as it is unsaturated.
15.
Huckel proposed that aromaticity is a function of electronic structure. A compound may be aromatic, if it obeys the following rules
(i) The molecule must be co-planar
(ii) Complete delocalization of \(\pi\) electron in the ring
(iii) Presence of (4n+2) \(\pi\) electrons in the ring where n is an integer (n = 0,1,2 .... ) This is known as Huckel's rule.
Eg:
(i) The benzene is a planar molecule
(ii) It has six deloclaised \(\pi\) electoms
(iii) 4n + 2 = 6
4n = 6-2
4n = 4
n = 1
it obeys Huckel's (4n+2) \(\pi\) electron rule with n = 1 hence, benzene is aromatic.
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