11th Standard Syllabus & Materials
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TN 11th Tamil இயற்கை வேளாண்மை,சுற்றுச்சூழல் -செய்யுள் - மனோன்மணீயம் Important Questions And Answers Study Material - QB365 Set A
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Published on: 21/09/2019
Thermodynamics
Download Tamil Nadu 11th Standard Chemistry question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
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1.
Calculate the entropy change in surroundings when 1 mol of H20(I) is formed under standard conditions. Given \(\Delta { H }^{ \ominus }\) = - 286 kJ mol-1.
2.
The equilibrium constant for the reaction is 10. Calculate the value of \(\Delta { G }^{ \ominus }\); Given R = 8.314 JK-1 mol-1; T = 300 K.
3.
For the equilibrium PCI5(s) ⇌ PCl3(g) + CI2(g) at 25°C kc = 1.8 x 10-7 R = 8.314 Jk-1 mol-1 Calculate ΔGo for the reaction.
4.
For the reaction, 2A(g) + B(g) ⟶ 2D(g) ΔU0 = -10.5 kJ and ΔS0 = - 44.1 JK-1. Calculate ΔG0 for the reaction and predict whether the reaction is spontaneous or not.
5.
The bond dissociation energies of gaseous chlorine, hydrogen, and hydrogen chloride are 104, 58, and 103 k.cal mol-1 respectively. Calculate the enthalpy of formation of HCI(g). Predict in which of the following, entropy increases/decreases. - 2NaHCO3(s) \(\rightarrow\)Na2CO3(s) + CO2(g) + H2O(s)
6.
The bond dissociation energies of gaseous chlorine, hydrogen, and hydrogen chloride are 104, 58, and 103 k.cal mol-1 respectively. Calculate the enthalpy of formation of HCI(g). Predict in which of the following, entropy increases/decreases. - Temperature of crystalline solid is raised from 0K to 115K.
7.
Describe the application of heat of combustion.
8.
Explain why Cp is always greater than Cv?
9.
Define molar heat capacity at constant volume and molar heat capacity at constant pressure.
10.
Give Kelvin statement of second law of thermodynamics.
11.
What is lattice energy?
12.
Define enthalpy of neutralization
13.
Define the calorific value of food. What is the unit of calorific value?
14.
Define molar heat capacity. Give its unit
15.
An engine operating between 127°C and 47°C takes some specified amount of heat from a high temperature reservoir. Assuming that there are no frictional losses, calculate the percentage efficiency of an engine.
1.
\(q_{rev}= (-\Delta_f H^{\ominus})=-286 kJ\ mol^{-1}=286000\ J\ mol^{-1}\)
\(\Delta{S}{_{(Surroundmgs)}}=\frac{q_{rev}}{T}=\frac{286000\ J\ mol^{-1}}{298\ K}\) = 959 J K-1 mol-1.
2.
\(\Delta { G }^{ \ominus }\) = -RT ln K = -2.303 RT log K.
R = 8.314 JK-1 mol-1;T = 300 K; K=10
\(\Delta { G }^{ \ominus }=-2.303 \times 8.314 \) JK-1 mol-1 x (300 K) x log 10
= -5527 J mol-1= -5.527 kJ mol-1
3.
ΔG0 = - 2.303 RT log kc
= - 2.303 x 8.314 x 298 log (1.8 x 10-7)
= - 38484 J mol-1
= - 38.484 kJ mol-1
4.
Δ H0= ΔU0 + RT(Δn)
= -10.5 + 8.314 x 10-3 x 298 x (-1)
= -12.978 kJ
We know, ΔG0= Δ H0 - TΔS0
= -12.978 - 298 (- 44.1 x 10-3)
= 0.164 kJ
Hence, the reaction is non spontaneous.
5.
In the reaction 2NaHCO3(s) \(\rightarrow\) Na2CO3(s) +CO2(g) + H2O(g) the number of gaseous components increase and hence entropy of the system will increase.
6.
When a crystalline solid is heated from 0K to 115K, the entropy increases (\(\triangle\)S = positive) because at higher temperature, the constituent units starts vibrating around their mean position.
7.
(i) The heat of formation of compounds can be calculated from heat of combustion values.
(ii) The calorific value of food and fuels can be calculated from heat of combustion.
8.
At constant pressure processes, a system has to do work against the surroundings. Hence, the system would require more heat to effect a given temperature rise than at constant volume, so Cp is always greater than Cv.
9.
(i) The heat capacity at constant volume (Cv) is defined as the rate of change of internal energy with respect to temperature at constant volume.
\({ C }_{ v }={ \left( \frac { \partial H }{ \partial T } \right) }_{ v }\)
(ii) The molar heat capacity at constant pressure (Cp ) can be defined as the rate of change of enthalpy with respect to temperature at constant pressure.
\({ C }_{ P }={ \left( \frac { \partial H }{ \partial T } \right) }_{ P }\)
10.
It is impossible to construct a machine that absorbs heat from a hot source and converts it completely into work by a cyclic process without transferring a part of heat to a cold sink
11.
Lattice energy is defined as "The amount of energy required to completely remove the constituent ions from its crystal lattice to an infinite distance." It is also referred as lattice enthalpy
12.
The heat of neutralisation is defined as "The change in enthalpy when one gram equivalent of an acid is completely neutralised by one gram equivalent of a base or vice versa in dilute solution"
13.
The calorific value is defined as "The amount of heat produced in calories (or joules) when one gram of the substance is completely burnt." The SI unit of calorific value is J kg-1. It is usually expressed in cal g -1.
14.
Molar heat capacity is defined as "The amount of heat absorbed by one 'mole of the substance to raise its temperature by 1 kelvin". The SI unit of molar heat capacity is JK-1 mol-1
15.
Given
T1 = 127°C = 127 + 273 = 400 K
T = 47°C = 47 + 273 = 320 K
% efficiency η = ?
η = \(\left[ \frac { { T }_{ 1 }-{ T }_{ 2 } }{ { T }_{ 1 } } \right] \) x 100
η =\(\left[ \frac { 400-320 }{ 400 } \right] \) x 100
η = \(\left[ \frac { 80 }{ 400 } \right] \) x 100
η = 20%
11th Standard Syllabus & Materials
11th Standard
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