11th Standard Syllabus & Materials
11th Standard
TN 11th Tamil இயற்கை வேளாண்மை,சுற்றுச்சூழல் -செய்யுள் - மனோன்மணீயம் Important Questions And Answers Study Material - QB365 Set A
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TN 11th Tamil என்னுயிர் என்பேன் -துணைப்பாடம் - இசைத்தமிழர் இருவர் Important Questions And Answers Study Material - QB365 Set A
NEW11th Standard
TN 11th Tamil மொழி கலை -செய்யுள் - ஒவ்வொரு புல்லையும் Important Questions And Answers Study Material - QB365 Set A
NEW11th Standard
TN 11th Tamil பீடு பெற நில் - இலக்கணம் - பகுபத உறுப்புகள் Important Questions And Answers Study Material - QB365 Set A
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TN 11th Tamil பீடு பெற நில் - துணைப்பாடம் - வாடிவாசல் Important Questions And Answers Study Material - QB365 Set A
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TN 11th Tamil பீடு பெற நில் - செய்யுள் - குறுந்தொகை Important Questions And Answers Study Material - QB365 Set A

Published on: 19/09/2019
Basic Concepts of Chemistry and Chemical Calculations
Download Tamil Nadu 11th Standard Chemistry question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
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Take MCQ Chemistry Test

1.
Calculate the equivalent mass of the following : CO3-2,
2.
What do you understand by the term stoichiometry of the reaction ?
3.
3 grams of hydrogen reacts with 29g of O, to yield H2O. Calculate the amount of one of the reactants which remains unreacted.
4.
Calculate the oxidation number of underlined atoms of the following:
S2O3-2
5.
Calculate the equivalent masses of the following - Ferrous Sulphate
6.
Calculate the equivalent masses of the following - Crystalline Oxalic acid, H2C2O4 , 2H2O
7.
Why atomic masses are called as relative atomic masses?
8.
Balance the following equations by oxidation number method - \(Cu+{ HNO }_{ 3 }\longrightarrow Cu\left( { No }_{ 3 } \right) _{ 2 }+{ No }_{ 2 }+{ H }_{ 2 }O\)
9.
Balance the following equations by oxidation number method - \({ K }Mno_{ 4 }+{ Na }_{ 2 }{ So }_{ 3 }\longrightarrow { MnO }_{ 2 }+{ Na }_{ 2 }{ So }_{ 4 }+KOH\)
10.
What do you understand by the term oxidation number ?
11.
Define equivalent mass.
12.
What do you understand by the term mole ?
13.
Balance the following equations by ion electron method
\(Zn+{ NO }_{ 3 }^{ - }\longrightarrow { Zn }^{ 2+ }+No\)
1.
\(Equivalent \ mass ={sum \ of \ the \ atomic \ masses \ of \ atoms \ present \ in \ the \ ion \over charge \ on \ the \ ion}\)
For CO3 -2 ion
\(Equivalent \ mass ={1 x atomic \ mass \ of C + 3 x atomic \ mass \ of 'O'\over 2}\)
\(={12+3\times 16\over 2}={60\over2}=30\ g\ eq^{-1}\)
2.
Stoichiometry gives the numerical relationship between chemical quantities in a balanced chemical equation.
3.
2 mole of H2 react with 1mole of O2.
1.5 mole of H react with 0.75 mole of O2.
Excess O2 = 0.9062 - 0.75 = 0.1562 mol.
4.
S2O3-2 (S in S2O3-2)
Oxidation number of sulphur = x
Oxidation number of oxygen = - 2
2x + 3 (- 2) \(\Rightarrow\) 2x - 6 = - 2 (or) 2x ~ 4 or x = +2
Hence, the oxidation number of sulphur is S2O3-2 is + 2.
5.
Molar Mass of ferrous Sulphate = \(\begin{cases} atomic\ \ mass\ of\ Fe+atomic\ mass\ of\ s' \\ +4x\ atomic\ mass\ of\ O\ \end{cases}\)
= 56 + 32 + 4 x 16 = 152
In reactions, Fe+2 ion is oxidised to Fe+3 ion Fe+2 \(\rightarrow\) Fe+3 + e
equivalent mass = \(\frac { Molar\quad mass }{ no\quad of\quad involved } =\frac { 152 }{ 1 } =152g{ eq }^{ -1 }\)
6.
molar mass of crystalline oxalic acid (H2C2O4.2H2o) = Molar Mass of ocalic acid + 2 x Molar mass of H2o
= 90 + 2 x 18 = 126
Bascity = 2
\(\therefore\) \(\begin{matrix} W\ equivalent\ \ mass\ of \\ crystalline\ \ oxalic\ \ acid \end{matrix}\} =\frac { 126 }{ 2 } =63g\) eq-1
7.
The mass of an atom (10-27 kg) is too small to be measured directly. They are measured with reference to a standard atom, Hence they are called as relative atomic masses.
8.
(iii) \(\overset { 0 }{ \underset { \underset { 2e^{ - } }{ \downarrow } }{ Cu } } { O }_{ 7 }+H\overset { +5 }{ \underset { { 1e }^{ - } }{ \underset { \uparrow }{ N } } } { O }_{ 3 }\longrightarrow \overset { +2 }{ Cu } \left( { No }_{ 3 } \right) _{ 2 }+\overset { +4 }{ N } { O }_{ 2 }+{ H }_{ 2 }O\)
Cu +2HNO3 \(\longrightarrow \) Cu(NO3)2 + NO2 + H2O
Cu + 2HNO3 + 2HNO3 \(\longrightarrow \) Cu(NO3)2 + 2NO2 + 2H2O
Cu + 4HNO3 \(\longrightarrow \) Cu (NO3)2 + 2No2 + 2H2O
9.
(ii) \({ K }\overset { +7 }{ \underset { \underset { 3e^{ - } }{ \uparrow } }{ M } } n{ O }_{ 4 }+{ Na }_{ 2 }\overset { +4 }{ \underset { { 2e }^{ - } }{ \underset { \downarrow }{ S } } } { O }_{ 3 }\longrightarrow \overset { +4 }{ M } { nO }_{ 2 }+{ Na }_{ 2 }\overset { +6 }{ s } { O }_{ 4 }+KOH\)
\(\Rightarrow\) 2KMnO4 + 3Na2SO3 \(\longrightarrow \) MnO2 + Na2SO4 + KOH
\(\Rightarrow\) 2KMnO4 + 3Na2SO3 \(\longrightarrow \) 2MnO2 + 3Na2SO4 + KOH
\(\Rightarrow\) 2KMNO4 + 3NaSO3 + H2O \(\longrightarrow \) 2MnO2 + 3Na2SO4 +2KOH
10.
It is defined as the imaginary charge left on the atom when all other atoms of the compound have been removed in their usual oxidation states that are assigned according to set of rules.
11.
Gram equivalent mass of an element, compound or ion is the mass that combines or displaces 1.008 g hydrogen or 8 g oxygen or 35.5 g chlorine.
12.
One mole is the amount of substance of a system, which contains as many elementary particles as there are atoms in 12 g of carbon -12 isotope.
13.
\(\overset { o }{ Z } n\longrightarrow { Z }n^{ 2+ }\)
\(\overset { +5 }{ N } { O }_{ 3 }^{ - }\longrightarrow \overset { 2+ }{ NO } \)
(1) \(\Rightarrow \) Zn \(\rightarrow\) Zn2+ +2e- .....(3)
(2) \(\Rightarrow \) \({ NO }_{ 3 }^{ - }+{ 3e }^{ - }+{ 4H }^{ + }\longrightarrow NO+{ 2H }_{ 2 }O\)......(4)
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11th Standard Syllabus & Materials
11th Standard
TN 11th Tamil பீடு பெற நில் - செய்யுள் - காவடிச்சிந்து Important Questions And Answers Study Material - QB365 Set A
NEW11th Standard
TN 11th Tamil பீடு பெற நில் - உரைநடை - மலை இடப்பெயர்கள் : ஓர் ஆய்வு Important Questions And Answers Study Material - QB365 Set A
NEW11th Standard
TN 11th Tamil மாமழை போற்றுதும் - துணைப்பாடம் - யானை டாக்டர் Important Questions And Answers Study Material - QB365 Set A
NEW11th Standard
TN 11th Tamil மாமழை போற்றுதும் - செய்யுள் - ஐங்குறுநூறு Important Questions And Answers Study Material - QB365 Set A
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