11th Standard Syllabus & Materials
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Published on: 04/10/2019
Periodic Classification Of Elements
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1.
Why are noble gases chemically inert?
2.
How many elements can be accommodated in the long form of the periodic table? Explain.
3.
Predict the position of the element having an electron configuration(n -1) d1 ns2 for n = 4.
4.
Mention any two anomalous properties of second period elements.
5.
6.
Elements a, b, c and d have the following electronic configurations:
a: 1s2, 2s2, 2p6
b: 1s2, 2s2, 2p6, 3s2, 3p1
c: 1s2, 2s2, 2p6, 3s2, 3p6
d: 1s2, 2s2, 2p1
Which elements among these will belong to the same group of periodic table.
7.
Justify that the fifth period of the periodic table should have 18 elements on the basis of quantum numbers.
8.
In what period and group will an element with Z = 118 will be present?
9.
The electronic configuration of atom is one of the important factor which affects the value of ionisation potential and electron gain enthalpy. Explain.
10.
Energy of an electron in the ground state of the hydrogen atom is -2.8 x 10-18 J. Calculate the ionisation enthalpy of atomic hydrogen in terms of kJ mol-1.
1.
Noble gases having completely filled electronic configuration so neither accept nor lose their electron readily and hence they are chemically inert in nature.
2.
In the present set up of the long form of the periodic table, we have eighteen groups, seven periods (i.e. principal quantum number, n = 7) and four blocks (s, p, d and f -block elements).
Therefore, the maximum number of elements which can be accommodated in the present set up of the long form of the periodic table in accordance with Aufbau principle is
1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d10, 4p6, 5s2, 4d10,
5p6, 6s2, 4f14, 5d10, 6p6, 7s2, 5f14, 6d10, 7p6 = 118.
3.
Electronic configuration of the element is 3d1 4S2.
The element belongs to fourth period and group 3.
The element is scandium (Z = 21).
4.
(i) Lithium and beryllium form more covalent compounds, unlike the alkali and alkali earth metals which predominantly form ionic compounds.
(ii) The elements of the second period have only four orbitals (2s & 2p) in the valence shell and have a maximum co-valence of 4, whereas the other members of the subsequent periods have more orbitals in their valence shell and shows higher valences. For example, boron forms BF4- and aluminium forms AIF63-.
5.
6.
In the periodic table vertical columns are called groups.
Elements in the same vertical column possess similar number of electrons in the outer orbitals.
∴ Elements a and c belongs to group 18
Elements b and d belongs to group 13
7.
(i) According to aufbau's principle 5th period has nine orbital (one 5s, five 4d and three 6p) to be filled.
(ii) Nine orbitals can accommodate a maximum of 18 electrons. Hence fifth period of the periodic table should has 18 elements from rubidium (2 = 37) to Xenon (Z = 54).
8.
Z = 118; [86Rn] 5f14 6d10 7s2 7p6
In the periodic table the element with Z = 118 is located in p-block,
Period no = 7 (as n = 7 for valence shell)
Group no. = 18 (group no = 10+ ns electrons + np electrons) (n - outer most shell)
9.
(i) Electronic configuration is the arrangement of electrons in an atom. The outermost electron shell is often referred to as the "valence shell"determines the chemical properties.
(ii) Ionization energy and electron affinity is the amount of energy released or required in pulling out or adding an electron to a neutral atom. So both depend on electronic configuration of the element.
10.
Ionisation energy is the amount of energy required to remove the electron from the ground state (EI) to excited state (E∞)
E1=-2.18 x 10-18 J; E∞=0
ΔE=E∞-E1
=0-(-2.18 x 10-18 J)=2.18 x 10-18 J
I.E per hydrogen atom = 2.18 x 10-18 J
I.E per mole of H-atom =2.18 x 10-18 J x 6.023 x 1023
=13.13 x 105 J mol-1
11th Standard Syllabus & Materials
11th Standard
TN 11th Tamil பீடு பெற நில் - செய்யுள் - காவடிச்சிந்து Important Questions And Answers Study Material - QB365 Set A
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