11th Standard Syllabus & Materials
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Published on: 13/05/2022
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1.
Calculate the amount of depreciation and depreciation rate from the following by using ‘straight line method’. Also give journal entries for the first two years. The books are closed on 31st December every year.
| January 1, 2016 Payment to vendor for purchase of machinery | Rs.2,00,000 |
| January 1, 2016 Transportation cost | Rs.2,000 |
| January 1, 2016 Installation cost | Rs.18,000 |
| Estimated scrap value at the end of the life | Rs.10,000 |
| Estimated life | 10 years |
2.
From the following information, calculate the amount of depreciation and rate of depreciation under straight line method.
Purchase price of machine Rs.2,00,000
Expenses to be capitalised Rs.50,000
Estimated residual value Rs.15,000
Expected useful life 5 years
3.
On 1.1.2017 a firm purchased a machine at a cost of Rs.1,00,000. Its life was estimated to be 10 years with a scrap value of Rs.10,000. Compute the amount of depreciation to be charged at the end of each year.
4.
A furniture costing Rs 5,000 was purchased on 1.1.2016, the installation charges being Rs 1,000. The furniture is to be depreciated @10% p.a. on the diminishing balance method. Pass journal entries for the first two years.
5.
An asset is purchased for Rs. 50,000. The rate of depreciation is 15% p.a. Calculate the annual depreciation for the first two years under diminishing balance method.
1.
Amount of depreciation per year = \({Original\ cost\ of\ the\ asset − Estimated\ scrap\ value\over Estimated\ useful\ life\ of\ the\ asset\ in\ years}\)
\(= \frac{2,20,000 - 10,000}{10} \\ =\frac{2,10,000}{10}\)
= Rs.21,000 per year
Rate of depreciation per year = \({Amount\ of\ depreciation\over Original\ cost}\times100\)
\(={21,500\over 2,20,000}\times100=9.55\%\)
2.
Amount of depreciation per year = \(Original\ cost\ of\ the\ asset − Estimated\ scrap\ value\over Estimated\ useful\ life\ of\ the\ asset\ in\ years\)
\(={2,50,000 – 15,000\over 10}={2,35,000\over 10}\) = Rs.47,000 per year
Rate of depreciation = \({Amount\ of\ depreciation\ per\ year\over Original\ cost}\times100\)
\(={47,000\over 2,50,000}\times100=18.8\%\)
3.
Amount of depreciation per year = \(Original\ cost\ of\ the\ asset − Estimated\ scrap\ value\over Estimated\ useful\ life\ of\ the\ asset\ in\ years\)
\(={1,00,000 – 10,000\over 10}={90,000\over 10}\) = Rs. 9,000 per year
When it is plotted on a graph for 5 years, it appears as follows:
4.
| Date | Particulars | L.F. | Debit Rs. |
Credit Rs. |
|
|---|---|---|---|---|---|
| 1.1.2016 | furniture A/c | Dr. | 6,000 | ||
| To Bank A/c | 6,000 | ||||
| (Furniture purchased) | |||||
| 31.12.2016 | Depreciation A/c | Dr. | 600 | ||
| To Furniture A/c | 600 | ||||
| (Annual depreciation) | |||||
| 31.12.2016 | Profit and loss A/c | Dr. | 600 | ||
| To Depreciation A/c | 600 | ||||
| (Depreciation transferred te profit and loss A/c) | |||||
| 31.12.2017 | Depreciation A/c | Dr. | 540 | ||
| To Furniture A/c | 540 | ||||
| (Annual depreciation) | |||||
| 31.12.2017 | Profit and loss A/c | Dr. | 540 | ||
| To Depreciation A/c | 540 | ||||
| (Depreciation transferred to profit and loss A/c) |
5.
| Particulars | Amount Rs. |
|---|---|
| Cost price | 50,000 |
| Less : Ist year depreciation | 7,500 |
| (50,000 \(\times\) \(\frac { 15 }{ 100 }\)) | |
| 42,500 | |
| .Less : IInd year depreciation | 6,375 |
| (42,500 \(\times\) \(\frac {15}{100}\)) | |
| 36,125 |
∴ Ist year depreciation = Rs.7,500
IInd year depreciation = Rs. 6,375
11th Standard Syllabus & Materials
11th Standard
TN 11th Tamil பீடு பெற நில் - செய்யுள் - காவடிச்சிந்து Important Questions And Answers Study Material - QB365 Set A
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Tamilnadu Stateboard 11th Standard Subjects

Maths

Commerce

Economics

Biology

Business Maths and Statistics

Accountancy

Computer Science

Physics

Chemistry

Maths

Biology

Economics

Physics

Chemistry

History

Business Maths and Statistics

Computer Science

Accountancy

Computer Applications

History

Computer Technology

Commerce

Computer Applications

Computer Technology

Tamil

English

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