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Published on: 13/05/2022
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Take MCQ Business Maths and Statistics Test

1.
Find the yearly income on 120 shares of 7% stock of face value Rs.100?
2.
A man wishes to pay back his depts of Rs.3783 due after 3 years by 3 equal yearly instalments. Find the amount of each instalments,money being worth 5% p.a. compounded annually
3.
Find the present value of an annuity due of Rs.200 p.a. payable annually for 2 years at 4%p.a
4.
If I deposit Rs.500 every year for a period of 10 years in a bank which gives C.I 5% per year, Find out the amount I will receive at the end of 10 years
5.
If I deposit Rs.500 every year for a period of 10 years in a bank which gives C.I. 5% per year, find out the amount I will receive at the end of 10 years.
1.
Given no.of shares = 120
FV = Rs.100
Dividend = 7%
Annual income = No.of shares x FV x Rate of dividend
=120 x 100 x \(\cfrac { 7 }{ 100 } \) = Rs.840
2.
Given A = Rs.3783,i = 0.05,n = 3
A = \(\cfrac { a }{ i } \left[ \left( 1+i \right) ^{ n }-1 \right] \)
3783 = \(\cfrac { a }{ i } \) [(1.05)3-1]
3783 x 0.05 = a[1.1576-1]
a = \(\cfrac { 189.15 }{ 0.1576 } \) = 1200.19
\(\therefore\) a =Rs.1200
(1.05)3 = 3 log (1.05)
= 3(0.212)
= 0.636
Antilog of 0.636 is 1.1576
3.
Given a = Rs.200, I = 0.04 , n = 2
P = \(\cfrac { a }{ i } \left( 1+i \right) \left[ \left( 1+i \right) ^{ n }-1 \right] \)
=\(\cfrac { 200 }{ 0.04 } \) (1.04)[1-(1.04)-2]
= 5200[1-0.9247]
= 5200(0.09247)
= Rs.391.56
(1.04)-2 = -2log(1.04)
= -2(0.0170)
= -0.340+1-1
Antilog of \(\bar { 1 } .9660\) is 0.9247
4.
Given a = Rs.500,i = 5% =0.05,n =10
A=\(\cfrac { a }{ i } \left[ 1-\left( 1+i \right) ^{ -n } \right] \)
=\(\cfrac { 500 }{ 0.05 } \left( 1.05 \right) \left[ \left( 1.05 \right) ^{ 10 }-1 \right] \)
=10,500 [1.629-1]
=10,500(0.629)
= Rs.6604.50
\(\therefore\) At the end of 10 years. I will receive Rs.6604.5
(1.05)10 = 10 log(1.05)
= 10(0.0212)
= 0.2120
Antilog of 0.2120 is 1.629
5.
Given a = Rs.500,i = 5% = 0.05,n =10
A =\(\cfrac { a }{ i } \left( 1+i \right) \left[ \left( 1+i \right) ^{ n }-1 \right] \)
\(=\frac { 500 }{ 0.05 } (1.05)\left[ (1.05)^{ 10 }-1 \right] \)
\(=10,500[1.629-1]\)
\(=10,500(0.629)\)
\(\therefore\) = Rs. 6604.50
At the end of 10 years, I will receive Rs. 6604.50.
\((1.05)^{ 10 }=10log(1.05)\)
\(=0.2120\)
Antilog of 0.2120 is 1.629
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