11th Standard Syllabus & Materials

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TN 11th Tamil பீடு பெற நில் - செய்யுள் - குறுந்தொகை Important Questions And Answers Study Material - QB365 Set A

11th Standard English Medium Chemistry Subject Basic Concepts of Chemistry and Chemical Calculations Book Back 2 Mark Questions with Solution Part - I Set B

Published on: 07/06/2021

Question Set B

QB365 provides detailed and simple solution for every Book back Questions in class 11 Chemistry Subject. It will helps to get more idea about question pattern in every book back questions with solution.

Download Tamil Nadu 11th Standard Chemistry question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.

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Std: 11th Standard - Chemistry

chapter: - Book back Questions

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Questions:

Generic 2

2 x 2 = 4

Define equivalent mass.

Define relative atomic mass.

Generic 3

3 x 3 = 9

Hydrogen peroxide is an oxidising agent. It oxidises ferrous ion to ferric ion and reduced itself to water. Write a balanced equation.

Which contains the greatest number of moles of oxygen atoms
i) 1 mol of ethanol
ii) 1 mol of formic acid
iii) 1 mol of H₂O

Distinguish between oxidation and reduction.

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Answers Key:

Generic 2

2 x 2 = 4

Gram equivalent mass of an element, compound or ion is the mass that combines or displaces 1.008 g hydrogen or 8 g oxygen or 35.5 g chlorine.

''The relative atomic mass is defined as the ratio of the average atomic mass factor to the unified atomic mass unit''.

Generic 3

3 x 3 = 9

\({ H }_{ 2 }\overset { -1 }{ \underset { \overset { \uparrow }{ (ie\times 2) } }{ { O }_{ 2 } } } +{ \underset { \overset { \downarrow }{ Ie^{ - } } }{ Fe } }^{ 2 }+\rightarrow { Fe }^{ 3+ }+\overset { -2 }{ {H}_{2} O} \)
\({ H }_{ 2 }{ O }_{ 2 }+{ 2Fe }^{ 2+ }+\rightarrow Fe^{ 3+ }+{ H }_{ 2 }O\)
\(\Rightarrow \) \({ H }_{ 2 }{ O }_{ 2 }+{ 2Fe }^{ 2+ }+{ 2 }H^{ + }\rightarrow 2Fe^{ 3+ }+{ 2H }_{ 2 }O\)

Compound	Given No.of moles	No.of oxygen atoms
Ethanol - C₂H₅OH	1	1\(\times\)6.022\(\times\)10²³
Formic acid - HCOOH	1	2\(\times\)6.022\(\times\)10²³
Water - H₂O	1	1\(\times\)6.022\(\times\)10²³
Formic acid

	Oxidation	Reduction
1.	Addition of oxygen	Addition of Hydrogen
2.	Removal of Hydrogen	Removal of oxygen
3.	Addition of an electronegative element.	Addition of an electro positive element
4.	Removal of an electro positive element	Removal of an electro negative element
5.	Loss of electron	Gain of electron
6.	Increase in oxidation state / number	Decrease in oxidation state/ number.