11th Standard Syllabus & Materials

11th Standard

TN 11th Tamil இயற்கை வேளாண்மை,சுற்றுச்சூழல் -செய்யுள் - மனோன்மணீயம் Important Questions And Answers Study Material - QB365 Set A

NEW

11th Standard

TN 11th Tamil என்னுயிர் என்பேன் -துணைப்பாடம் - இசைத்தமிழர் இருவர் Important Questions And Answers Study Material - QB365 Set A

NEW

11th Standard

TN 11th Tamil மொழி கலை -செய்யுள் - ஒவ்வொரு புல்லையும் Important Questions And Answers Study Material - QB365 Set A

NEW

11th Standard

TN 11th Tamil பீடு பெற நில் - இலக்கணம் - பகுபத உறுப்புகள் Important Questions And Answers Study Material - QB365 Set A

NEW

11th Standard

TN 11th Tamil பீடு பெற நில் - துணைப்பாடம் - வாடிவாசல் Important Questions And Answers Study Material - QB365 Set A

NEW

11th Standard

TN 11th Tamil பீடு பெற நில் - செய்யுள் - குறுந்தொகை Important Questions And Answers Study Material - QB365 Set A

11th Standard English Medium Chemistry Subject Basic Concepts of Chemistry and Chemical Calculations Book Back 3 Mark Questions with Solution Part - I Set A

Published on: 08/06/2021

Question Set A

QB365 provides detailed and simple solution for every Book back Questions in class 11 Chemistry Subject. It will helps to get more idea about question pattern in every book back questions with solution.

Download Tamil Nadu 11th Standard Chemistry question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.

Questions + Answers key

Take MCQ Chemistry Test

QB365 Student Learing Managemnet System

Std: 11th Standard - Chemistry

chapter: - Book back Questions

Visit QB365-SLMS - https://www.qb365.in/slms/ Complete Questions and Answers

Questions:

Generic 5

3 x 5 = 15

Calculate the empirical and molecular formula of a compound containing 76.6% carbon, 6.38 % hydrogen and rest oxygen its vapour density is 47.

What is the empirical formula of the following?
i) Fructose (C₆ H₁₂O₆) Found in honey
ii) Caffeine (C₈H₁₀N₄ O₂) a substance found in tea and Coffee

Mass of one atom of an element is 6.645 x 10^-23g. How many moles of element are there in 0.320 kg.

Generic 3

2 x 3 = 6

How much volume of chlorine is required to form 11.2 L of HCI at 273 K and 1 atm pressure?

How many moles of hydrogen is required to produce 10 moles of ammonia ?

Visit QB365-SLMS - https://www.qb365.in/slms/

Answers Key:

Generic 5

3 x 5 = 15

Element	Percentage	Atomic mass	Relative number of atoms	simple ratio	Whole no
C	76.6	12	\(\frac { 76.6 }{ 12 } =6.38\)	\(\frac { 6.38 }{ 1.06 } =6\)	6
H	6.38	1	\(\frac { 6.38 }{ 1 } =6.38\)	\(\frac { 6.38 }{ 1.06 } =6\)	6
0	17.02	16	\(\frac { 17.02 }{ 16 } =1.06\)	\(1.06\frac { 1.06 }{ 1.06 } =1\)	1

Empirical Formula = C₆H₆O
n = \(\frac { molar\ mass }{ calculated\ eprirical\ formula\ mass } \)
= \(\frac { 2\times \ vapour\ density }{ 94 } \frac { 2\times 47 }{ 94 } =1,\)
Molecular formula (C₆H₆O) x 1 = C₆H₆O.

Compound	Molecular formula	Empirical Formula
Fructose	C₆H₁₂O₆	C H₂O
Caffeine	C₈H₁₀N₄O₂	C₄H₅N₂O

mass of one atom = 6.645 x 10^-23g
\(\therefore\) mass of 1 mole of an atom = 6.645 x 10^-23 g x 6.022 x 10²³= 40 g
\(\therefore\) number of moles of element in 0.320 kg = \(\frac { 1\quad mole }{ 40g } \times 0.320kg\)
= \(\frac { 1mol\times 320g }{ 40g } \)
= 8 mol

Generic 3

2 x 3 = 6

The balanced equation for the formation of HCI is,
H₂(g) + CI₂(g) \(\rightarrow\) 2 HCI (g)
As per the stoichiometric equation, under given conditions,
To produce 2 moles of HCI, 1 mole of chlorine gas is required.
To produce 44.8 litres of HCI, 22.4 litres of chlorine gas are required.
\(\therefore\) To produce 11.2 litres of HCI,

= 5.6 litres of chlorine are required.

The balanced stoichiometric equation for the formation of ammonia is
N₂(g) + 3H₂ (g) \(\rightarrow\) 2NH₃ (g)
As per the stoichiometric equation,
To produce 2 moles of ammonia, 3 moles of hydrogen are required.
\(\therefore\) to produce 10 moles of ammonia,

= 15 moles of hydrogen are required.