11th Standard Syllabus & Materials
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Published on: 25/06/2021
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Download Tamil Nadu 11th Standard Chemistry question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Chemistry Test1.
Explain why BeH2 molecule has a zero dipole moment although the Be - H bonds are polar.
2.
What are the main postulates of Valence Shell Electron Pair Repulsion (VSEPR) theory ?
3.
What are Lewis structures? Write the Lewis structure of H2, BeF2 and H2O.
4.
Write the important conditions required for the linear combination of atomic orbitals to form molecular orbitals.
5.
Distinguish between a sigma bond and a pi bond.
1.
The Lewis structure for BeH2 molecule is as follows : H : Be : H
There is no lone pair at the central atom (Be) and there are two bond pairs. Hence, BeH2 is of the type AB2. It has a linear structure.
Dipole moments of each Be-H bond are equal and opposite in direction. Therefore, they nullify each other. Hence, BeH2 has a net zero dipole moment.
2.
(i) The shape of a molecule depends upon the no. of electron pairs around the central atom.
(ii) There is a repulsive force between the electron pairs, which tend to repel one another.
(iii) The electron pairs in space tend to occupy such positions that they are at maximum distance, so that the repulsive force will be minimum.
(iv) A multiple bond is treated as if it is a single bond and the remaining electron pairs which constitute the bond may be regarded as single super pair.
3.
The outer shell electrons are shown as dots surrounding the symbol of the atom. These symbols are known as Lewis symbols or Lewis structures. The Lewis structure of
(i) H2-H:H
(ii)
4.
(i) The combining atomic orbitals should have comparable energies. For example, ls orbital of one atom can combine with Is atomic orbital of another atom, 2s orbital can combine with 2s orbital and so on.
(ii) The combining atomic orbitals must have proper orientations so that they are able to overlap to a considerable extent.
(iii) The extent of overlapping should be large.
5.
| Sigma (σ) Bond | Pi (π) Bond | |
| 1. | a-bond is formed by the axial overlap of the atomic orbitals | rt-bond is formed by the sidewise overlap of atomic orbitals. |
| 2. | The bond is quite strong | It is comparatively a weaker bond |
| 3. | Only one lobe of the p-orbitals is involved in the overlap | Both lobes of the p-orbitals are involved in the overlap |
| 4. | Electron cloud of the molecular orbital is symmetrical around the internuclear axis. | The electron cloud is not symmetrical |
11th Standard Syllabus & Materials
11th Standard
TN 11th Tamil பீடு பெற நில் - செய்யுள் - காவடிச்சிந்து Important Questions And Answers Study Material - QB365 Set A
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NEW11th Standard
TN 11th Tamil மாமழை போற்றுதும் - துணைப்பாடம் - யானை டாக்டர் Important Questions And Answers Study Material - QB365 Set A
NEW11th Standard
TN 11th Tamil மாமழை போற்றுதும் - செய்யுள் - ஐங்குறுநூறு Important Questions And Answers Study Material - QB365 Set A
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