11th Standard Syllabus & Materials
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Published on: 13/05/2022
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Questions + Answers key
Take MCQ Chemistry Test1.
Give the structure for the following compound.
3- ethyl - 2 methyl -1-pentene
2.
0.2346g of an organic compound containing C, H & O, on combustion gives 0.2754g of H2O and 0.4488g CO2. Calculate the % composition of C, H & O in the organic compound [C = 52.17, H = 13.04, O = 34.79]
3.
0.26g of an organic compound gave 0.039 g of water and 0.245 g of carbon dioxide on combustion. Calculate the percentage of C & H.
4.
5.
0.185 g of an organic compound when treated with Conc. HNO3 and silver nitrate gave 0.320 g of silver bromide. Calculate the % of bromine in the compound. (Ag =108, Br = 80)
1.
2.
w = 0.2346 g
x = 0.2754 g
y = 0.4488 g
\(
\% \mathrm{H} =\frac{2}{18} \times \frac{x}{w} \times 100=\frac{2}{18} \times \frac{0.2754}{0.2346} \times 100=13.04 \%
\)
\(\% \mathrm{C} =\frac{12}{44} \times \frac{\mathrm{y}}{\mathrm{w}} \times 100=\frac{12}{44} \times \frac{0.4488}{0.2346} \times 100=52.17 \%
\)
\(\% \mathrm{O} =100-[\% \mathrm{C}+\% \mathrm{H}]
\)
\(=100-[52.17+13.04]=34.79 \%\)
3.
Weight of organic compound = 0.26g
Weight of water = 0.039g
Weight of CO2 = 0.245g
Percentage of hydrogen
\(
\% =\frac{2}{18} \times \frac{x}{\mathrm{w}} \times 100
\)
\(=\frac{2}{18} \times \frac{0.039}{0.26} \times 100
\)
\(=1.66 \%\)
Percentage of carbon
\(\% \mathrm{C} =\frac{12}{44} \times \frac{\mathrm{y}}{\mathrm{w}} \times 100
\)
\(=\frac{12}{44} \times \frac{0.245}{0.26} \times 100=25.69 \%
\)
4.
5.
(w) = 0.185 g
(x) = 0.320 g
\(\% \mathrm{Br}=\frac{80}{188} \times \frac{b}{w} \times 100=\frac{80}{188} \times \frac{0.320}{0.185} \times 100=73.6 \%\)
11th Standard Syllabus & Materials
11th Standard
TN 11th Tamil பீடு பெற நில் - செய்யுள் - காவடிச்சிந்து Important Questions And Answers Study Material - QB365 Set A
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TN 11th Tamil மாமழை போற்றுதும் - செய்யுள் - ஐங்குறுநூறு Important Questions And Answers Study Material - QB365 Set A
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