11th Standard Syllabus & Materials
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Published on: 07/06/2021
QB365 provides detailed and simple solution for every Book back Questions in class 11 Chemistry Subject. It will helps to get more idea about question pattern in every book back questions with solution.
Download Tamil Nadu 11th Standard Chemistry question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Chemistry Test1.
How many radial nodes for 2s, 4p, 5d and 4f orbitals exhibit? How many angular nodes
2.
The stabilisation of a half filled d - orbital is more pronounced than that of the p-orbital why?
3.
Give the electronic configuration of Mn2+ and Cr3+
4.
How fast must a 54g tennis ball travel in order to have a de Broglie wavelength that is equal to that of a photon of green light 5400\(\overset { 0 }{ A } \) ?
5.
An atom of an element contains 35 electrons and 45 neutrons. Deduce
(i) the number of protons
(ii) the electronic configuration for the element
(iii) All the four quantum numbers for the last electron
1.
| Orbital | n | 1 | Radial node n-1-1 | Angular node 1 |
| 2s | 2 | 0 | 1 | 0 |
| 4p | 4 | 1 | 2 | 1 |
| 5d | 5 | 2 | 2 | 2 |
| 4f | 4 | 3 | 0 | 3 |
2.
Energy electrons symmetry
This is due to the symmetrical distribution and exchange energy of given d- electrons. Symmetry leads to stability.
Exchange energy:
If two or more electrons with the same spin are present in degenerate orbitals, there is a possibility for exchanging their positions. During exchange process, the energy is released and the released energy is called exchange energy. If more number of exchanges are possible, more exchange energy in released. More number of exchanges are possible only in case of half filled and fully filled configurations.
For example, in chromium the electronic configuration is [Ar]3d5 4s1. The 3d orbital is half filled and there are ten possible exchanges as shown in figure. On the other hand only six exchanges are possible for [Ar]3d4 4s2 configuration. Hence, exchange energy for the half filled configuration is more. This increases the stability of half filled 3d orbitals.

The exchange energy is the basis for Hund's rule, which allows maximum multiplicity, that is electron pairing is possible only when all the degenerate orbitals contain one electron each.
3.
i) 25Mn - 1s2, 2S2, 2p6, 3s2, 3p6, 4s2, 3d5
23Mn2+ - 1s2, 2S2, 2p6, 3s2, 3p6, 3d5
ii) 24Cr - 1s2, 2S2,2p6, 3s2, 3p6, 4s1, 3d3
21Cr3+ - 1s2, 2S2,2p6, 3s2, 3p6, 3d3
4.
De Broglie wavelength of the tennis ball equal to 5400 \(\overset { 0 }{ A } \).
m = 54 g
V = ?
\(\lambda=\frac{h}{mV}\)
\(V=\frac{h}{m\lambda}\)
\(\mathrm{v}=\frac{6.626 \times 10^{-34} \mathrm{JS}}{54 \times 10^{-3} \mathrm{~kg} \times 5400 \times 10^{-10} \mathrm{~m}}=2.27 \times 10^{-26} \mathrm{~ms}^{-1}\)
5.
(i) no. of electrons: 35 (given)
no. of protons : 35
(ii) Electronic configuration
1s2 2S2 2p6 3s2 3p6 4s2 3d10 4p5
(iii) Last electron:
| \(\downharpoonleft\upharpoonright\) | \(\upharpoonleft\downharpoonright\) | \(\upharpoonleft\) |
4Px 4Py 4pz
last electron present in 4Py orbital y
n = 4, l = 1 m1 = either + 1 or -1 and s = -1/2
11th Standard Syllabus & Materials
11th Standard
TN 11th Tamil பீடு பெற நில் - செய்யுள் - காவடிச்சிந்து Important Questions And Answers Study Material - QB365 Set A
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